Hi Charles, Charles C. Berry wrote: > Try this: > > f2 <- function(...) sapply( substitute(list(...)), deparse )[-1]
Wow, this works. Thanks a lot! > p.s. Why do you want this as mode "character"? For the usual purpose of 'substitute': to label something. The use case is that I have a function that takes an unspecified number of very large integer vectors which are visualized in some way. I first tried to pass all the vectors as one list, via '.Call', but that made R duplicate the vectors, when the list argument is built. So, I now use '...' and '.External', where duplication does not happen. I would like to conveniently label the vectors by the expression with which they have been passed (as 'plot' does, too), and with your construction, I can now extract the expressions as characters and pass them to make the labels. > Warning: > >> fortune(106) > > If the answer is parse() you should usually rethink the question. > -- Thomas Lumley > R-help (February 2005) Then, I am lucky that you offered a solution with 'deparse', not 'parse'. ;-) Still, I am (pleasently) surprised that the vectors within the '...' do not get duplicated (according to 'tracemem') by this construction. Thank you very much Simon ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
