See rowMedians() of the matrixStats package for replacing apply(x, MARGIN=1, FUN=median). /Henrik
On Tue, May 22, 2012 at 12:34 PM, Preeti <pre...@sci.utah.edu> wrote: > Hi, > > I have a 250,000 by 300 matrix. I am trying to calculate the median of > those columns (by row) with column names that are identical. I would like > this to be efficient since apply(x,1,median) where x is created by choosing > only those columns with same column name and looping on this is taking a > really long time. Is there an efficient way to do this? > > Thanks! > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.