I presume it's related to the fact that the X coordinate is duplciated
in the two records, and the grid generated by adehabitatHR is a single
column,

Here's a test:
require(adehabitatHR)
m <- matrix(c(5419574  ,    390051, 5419490   ,  390051), ncol = 2,
byrow = TRUE)
 tt <- as.POSIXct(c("2012-05-30 14:00:00", "2012-05-30 16:00:00"))
id <- c("Ade=5", "Ade-5")

x <- kernelbb(as.ltraj(m, date = tt, id = id, typeII=TRUE), sig1 =
4.5766, sig2 = 5, grid = 1000)

This degenerate Y dimension affects downstream methods (like image),
and I'd say this is worth reporting to the package author as an issue:

dim(x[[1]])
[1] 1000    1
 dim(x[[2]])
[1] 1000    1

The clue comes from points2grid in sp:
Warning messages:
1: In points2grid(points, tolerance, round) :
  cell size from constant coordinate 2 possibly taken from other coordinate


You could override the auto-generated grid by passing in your own,
probably something you will want anyway so that your collection share
the same extent and resolution. See ?kernelbb, the "grid" argument can
be a Spatial object rather than a pixel size.

I would really wonder about what is the point in generating summaries
from single line-segments, but that is off-topic I guess.

Cheers, Mike.


On Sat, May 18, 2013 at 4:47 AM, Rémi Lesmerises
<remilesmeri...@yahoo.ca> wrote:
> There was some mistakes in my previous sending. The following are correct.
>
> This is the problematic data, especially the line 43, but when I removed that 
> line, it bugs at line 62 and so on.
>
>
>           sig1                    time                        id       
> UTMnorthin  UTMeasting
> 40      4.5766      2012.05.30 08:00:00     Ade-5   5419576     390052
> 41      4.5766      2012.05.30 10:00:00     Ade-5   5419581     390058
> 42      4.5766      2012.05.30 12:00:00     Ade-5   5419560     390045
> 43      4.5766      2012.05.30 14:00:00     Ade-5   5419574     390051
> 44      4.5766      2012.05.30 16:00:00     Ade-5   5419490     390051
> 45      4.5766      2012.05.30 18:00:00     Ade-5   5419435     390293
> 46      4.5766      2012.05.30 20:00:00     Ade-5   5419661     390876
> 47      4.5766      2012.05.30 22:00:00     Ade-5   5419934     390673
> 48      4.5766      2012.05.31 02:00:00     Ade-5   5420636     389777
> 49      4.5766      2012.06.05 02:00:00     Ade-7   5419275     391206
> 50      4.5766      2012.06.05 04:00:00     Ade-7   5419276     391202
>
> This is a data frame so before the loop (see commands in the previous mail 
> below), I transform with the following commands:
>
>>coordinates(fece)<-~UTMeasting+UTMnorthin
>>loc@data$time <- as.POSIXct(strptime(as.character(loc@data$time),"%Y.%m.%d 
>>%H:%M:%S"))
>
>
> Rémi Lesmerises, biol. M.Sc.,
> PH.D candidate
> Université du Québec à Rimouski
>
> ________________________________
> De : David Winsemius <dwinsem...@comcast.net>
> À : Rémi Lesmerises <remilesmeri...@yahoo.ca>
> Cc : "r-help@r-project.org" <r-help@r-project.org>
> Envoyé le : vendredi 17 mai 2013 13h53
> Objet : Re: [R] Error with adehabitatHR and kernelbb
>
>
>
> On May 17, 2013, at 7:44 AM, Rémi Lesmerises wrote:
>
>> Dear all,
>>
>> I'm trying to get a Brownian bridge kernel (kernelbb) for each combination 
>> of two consecutive animal locations (see commands below) and put them, with 
>> a loop, inside a list. It works well at the beginning but after 42 runs, it 
>> appears the following warning :
>>
>>
>>> Error in seq.default(yli[1], yli[2], by = diff(xg[1:2])) :
>>>  invalid (to - from)/by in seq(.)
>>
>> I looked at the coordinates, at the id, at the time of the run 43 and it's 
>> all good...
>>
>> I looked on the net and it happened to only one person and there was no 
>> answer to his post.
>
> I wonder if that posting (like yours)  had no data on which to display the 
> problem or to test potential solutions? I would think you would want to post 
> any setup objects and then data for items 40-45.
>
>>
>> Someone could help me?
>>
>> ## commands
>>
>> BBtraj <- list()
>> for (i in 1:(nrow(loc@data)-1)) {
>> BBtraj[[i]] <- kernelbb(as.ltraj(loc@coords[i:(i+1),], 
>> date=loc@data$time[i:(i+1)], id = as.character(loc@data$id[i:(i+1)]),
>> typeII = TRUE), sig1=as.numeric(as.character(loc@data$sig1[i])), sig2= 5, 
>> grid = 1000)
>> }
>>
> --
>
>
> David Winsemius
> Alameda, CA, USA
>     [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>         [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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>



-- 
Michael Sumner
Hobart, Australia
e-mail: mdsum...@gmail.com

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