Hi Jim,

Thank you a lot. Is it a FAQ concerning lattice or FOR loop in general?

Regards,

Xochitl C.


Le 05/06/2013 10:55, Jim Holtman a écrit :
This is an FAQ.  you have to explicitly 'print' the histogram:

print(histogram(~ Mpool[[2]]$LngtClas | Mpool[[2]]$SpCode, type = "count", col = "lightgrey", xlab= 
"LngtClas", main = paste("Length distribution per species for Mpool", "2", sep = "_")))

Sent from my iPad

On Jun 5, 2013, at 4:37, Xochitl CORMON<xochitl.cor...@ifremer.fr>  wrote:

Hi all,

I'm encountering a problem I do not understand on my data:

library (lattice)

Mpool1<- Table[Table$Subarea %in% c("52E9", "51E9"),]
Mpool2<- Table[Table$Subarea %in% c("53F0", "52F0"),]
Mpool3<- Table[Table$Subarea %in% c("51F0", "50F0"),]
Mpool4<- Table[Table$Subarea %in% c("51F1", "52F1"),]

Mpool<- list(Mpool1, Mpool2, Mpool3, Mpool4)


histogram(~ Mpool[[2]]$LngtClas | Mpool[[2]]$SpCode, type = "count", col = "lightgrey", xlab= "LngtClas", 
main = paste("Length distribution per species for Mpool", "2", sep = "_"))

#### This part works perfectly and I obtain the graph reprensenting Mpool2 
length class count per species.
#### Now when I want to automatize this with a "for" loop nothing is plotted.

for (i in c(2)){
windows()
histogram(~ Mpool[[i]]$LngtClas | Mpool[[i]]$SpCode, type = "count", col = "lightgrey", xlab= 
"LngtClas", main = paste("Length distribution per species for Mpool", i, sep = "_"))
print (i)
}

### Running this loop I obtained  windows filled grey (no plot drawn at all) but the 
print (i) print a "2" as expected. I really dont understand what's wrong with 
the loop. There is no error message and no notification in R. You can find enclosed my 
data in txt file.

Thank you very much for any help,

Xochitl C.

<><  <><  <><  <><

Xochitl CORMON
+33 (0)3 21 99 56 84

Doctorante en sciences halieutiques
PhD student in fishery sciences

<><  <><  <><  <><

IFREMER
Centre Manche Mer du Nord
150 quai Gambetta
62200 Boulogne-sur-Mer

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<Table.txt>
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