data.matrix() should do the job for you
Charles
On Thu, Oct 10, 2013 at 8:02 AM, arun <smartpink...@yahoo.com> wrote:
> Hi,
> It is not clear whether all the variables are factor or only a few are..
>
> dat<- read.table(text="a coef
> coef.l coef.h
> 1 1 0.005657825001254 0.00300612956318132 0.00830952043932667
> 2 2 0.00634505314577229 0.00334102345418614 0.00934908283735844
> 3 3 0.00368668099805019 0.000289702228748421 0.00708365976735195
> 4 4 0.0056200291035751 0.00209123538827368 0.00914882281887651
> 5 5 0.00636609791030242 0.00269683889899591
> 0.0100353569216089",sep="",colClasses=rep("factor",4))
> dat1<- dat
>
>
> dat[] <- lapply(dat,function(x) as.numeric(as.character(x)))
>
> str(dat)
> #'data.frame': 5 obs. of 4 variables:
> # $ a : num 1 2 3 4 5
> # $ coef : num 0.00566 0.00635 0.00369 0.00562 0.00637
> # $ coef.l: num 0.00301 0.00334 0.00029 0.00209 0.0027
> # $ coef.h: num 0.00831 0.00935 0.00708 0.00915 0.01004
>
>
> # With only a subset of variables in the dataset as factors
> dat1$a<- as.numeric(as.character(dat1$a))
>
>
> dat1[sapply(dat1,is.factor)]<-
> lapply(dat1[sapply(dat1,is.factor)],function(x) as.numeric(as.character(x)))
> str(dat1)
> #'data.frame': 5 obs. of 4 variables:
> # $ a : num 1 2 3 4 5
> # $ coef : num 0.00566 0.00635 0.00369 0.00562 0.00637
> # $ coef.l: num 0.00301 0.00334 0.00029 0.00209 0.0027
> # $ coef.h: num 0.00831 0.00935 0.00708 0.00915 0.01004
>
> A.K.
>
>
>
> I have a factor data frame which I want to convert to numeric without any
> change in contents. How could I do that?
>
>
> a coef coef.l coef.h
> 1 1 0.005657825001254 0.00300612956318132 0.00830952043932667
> 2 2 0.00634505314577229 0.00334102345418614 0.00934908283735844
> 3 3 0.00368668099805019 0.000289702228748421 0.00708365976735195
> 4 4 0.0056200291035751 0.00209123538827368 0.00914882281887651
> 5 5 0.00636609791030242 0.00269683889899591 0.0100353569216089
>
> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.
>
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