On 02 Dec 2013, at 16:35 , Bert Gunter <gunter.ber...@gene.com> wrote:
> Not true, Rich.
>
>> z <-factor(letters[1:3],lev=letters[3:1])
>> sort(z)
> [1] c b a
> Levels: c b a
>
> What you say is true only for the **default** sort order.
>
> (Although maybe the code author didn't realize this either)
The coding is certainly clunky (the phrase about writing FORTRAN in any
language springs to mind, only with SAS instead of FORTRAN):
>>>
>>> dodgers$ordered_day_of_week <- with(data=dodgers,
>>> ifelse ((day_of_week == "Monday"),1,
>>> ifelse ((day_of_week == "Tuesday"),2,
>>> ifelse ((day_of_week == "Wednesday"),3,
>>> ifelse ((day_of_week == "Thursday"),4,
>>> ifelse ((day_of_week == "Friday"),5,
>>> ifelse ((day_of_week == "Saturday"),6,7)))))))
>>> dodgers$ordered_day_of_week <- factor(dodgers$ordered_day_of_week,
>>> levels=1:7,
>>> labels=c("Mon", "Tue", "Wed", "Thur", "Fri", "Sat", "Sun"))
>>>
This'll do:
dodgers$ordered_day_of_week <- factor(dodgers$ordered_day_of_week,
levels=c("Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday",
"Sunday"),
labels=c("Mon", "Tue", "Wed", "Thur", "Fri", "Sat", "Sun"))
And BTW, it doesn't (and didn't) create an ordered factor, just a factor with a
different level ordering.
--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd....@cbs.dk Priv: pda...@gmail.com
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
