On Feb 5, 2014, at 10:05 AM, Simone <misen...@hotmail.com> wrote:

> Hi all,
> 
> I have performed a binomial test to verify if the number of males in a study 
> is significantly different from a null hypothesis (say, H0:p of being a male= 
> 0.5).
> For instancee:
> binom.test(10, 30, p=0.5, alternative="two.sided", conf.level=0.95)
> 
>    Exact binomial test
> 
> data:  10 and 30
> number of successes = 10, number of trials =
> 30, p-value = 0.09874
> alternative hypothesis: true probability of success is not equal to 0.5
> 95 percent confidence interval:
> 0.1728742 0.5281200
> sample estimates:
> probability of success 
>             0.3333333 
> 
> This way I get the estimated proportion of males (in this case p of success) 
> that is equal to 0.33 and an associated p-value (this is not significant at 
> alpha=0.05 with respect to the H0:P=0.5).
> 
> Now, I want to know, given a power of, say, 0.8, alpha=0.05 and the above 
> sample size (30), what is the minimum proportion of males as low or as high 
> (two sided) like to be significantly detected with respect to a H0 (not 
> necessarily H0:P=0.5 - I am interested also in other null hypotheses). In 
> other words, I would have been able to detect a significant deviation from 
> the H0 for a given power, alpha and sample size if the proportion of males 
> would have been more than Xhigh or less than Xlow.
> 
> I have had a look at the "pwr" package but it seems to me it doesn't allow to 
> calculate this.
> I would appreciate very much any suggestion.


Take a look at ?power.prop.test, where you can specify that one of the 
proportions is NULL, yielding the value you seek:


> power.prop.test(n = 30, p1 = 0.5, p2 = NULL, power = 0.8, sig.level = 0.05) 

     Two-sample comparison of proportions power calculation 

              n = 30
             p1 = 0.5
             p2 = 0.834231
      sig.level = 0.05
          power = 0.8
    alternative = two.sided

NOTE: n is number in *each* group


The value for 'p2' is your high value for the detectible difference from a 
proportion of 0.5, given the other parameters. 1 - p2 would be your low value.


Regards,

Marc Schwartz

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to