I am not sure it would do it since there is no reproducible example, but try names() instead of colnames().

HTH,
Ivan

--
Ivan Calandra, ATER
University of Reims Champagne-Ardenne
GEGENAA - EA 3795
CREA - 2 esplanade Roland Garros
51100 Reims, France
+33(0)3 26 77 36 89
ivan.calan...@univ-reims.fr
https://www.researchgate.net/profile/Ivan_Calandra

Le 30/03/15 15:54, Vikram Chhatre a écrit :
summary(mygenfreqt)
                   Length Class  Mode
dat1.str 59220  -none- numeric
dat2.str 59220  -none- numeric
dat3.str 59220  -none- numeric

head(mylist[[1]])
            1     2     3     4     5     6     7     8     9    10    11
  12
L0001.1 0.60 0.500 0.325 0.675 0.600 0.500 0.500 0.375 0.550 0.475 0.350
0.275
L0001.2 0.40 0.500 0.675 0.325 0.400 0.500 0.500 0.625 0.450 0.525 0.650
0.725

I want to change 1:12 to pop1:pop12

mylist<- lapply(mylist, function(e) colnames(e) <- paste0('pop',1:12))

What this is doing is replacing the data frames with just names
pop1:pop12.  I just want to replace the column labels.

Thanks for any suggestions.

        [[alternative HTML version deleted]]

______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to