> On Mar 24, 2017, at 10:12 AM, Qill Bel <qill...@gmail.com> wrote:
>
> Dear R-users,
>
> Imagine I have 3 vectors:
> *proc1<-0*
> *proc2<-0*
> *cpd<-c("proc1","proc2")*
The `cpd` vector has only character values in it, and has no relation to either
the `proc1` or `proc2` vectors. If you want it refer to them (or contain their
values), then omit the quotes. The values will not retain their names in this
instance. The R names `proc`` and `proc2` will be looked up and their values
places in an unnamed numeric vector. You could however make it so with:
cpd<-c("proc1"=proc1,"proc2"=proc2)
#The quotes are not needed and so this would be equivalent"
cpd<-c( proc1=proc1, proc2=proc2)
There is a `get`-function, but teaching you how to use it to solve the problem
is likely to be a disservice since it would allow you to continue using R as a
macro-processor.
>
> How can I change the value of proc1 to 1, based on vector cpd only?
> I tried with *as.factor(cpd[1])<-1*, but it produces an error.
Doesn't make much sense to me to use assignment to a factor in this instance,
but that's probably because we come from different programming backgrounds.
Neither your code nor mine would have produced a factor vector. You should say
in natural language what it is that you want to happen.
(Perhaps) Try this:
cpd[1] <- 1
Or:
cpd['proc1'] <- 1
>
> Any idea how could I achieve that?
>
> [[alternative HTML version deleted]]
And learn to post in plain text. Reading the Posting Guide will also be a good
idea. As would be studying a bit longer the "Introduction to R" that is shipped
with every installation.
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
David Winsemius
Alameda, CA, USA
______________________________________________
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