Hi all, this one left me a bit puzzled, as I don't seem to find a function to perform this easily. I must have overlooked the obvious, so sorry in advance.
I have a list of dates in numerical format (i.e. 34576), defined as the number of days that passed since january 1st 1900. So I apply the function : > MyDate <-as.Date(34576,origin="1900-01-01") > MyDate [1] "1994-09-01" But then I want to do something like : MyYear <- a.year.function(MyDate) MyYear should have the numerical value 1994. Alas, I don't find any function like that. I know I can take a substring of MyDate and convert to numeric, or even use the function "seq()" : > length ( seq ( as.Date("1900-01-01"), MyDate, "years" ) ) + 1900 - 1 [1] 1994 but that seems quite a way around. Can somebody tell me where the appropriate function is hiding? Thank you in advance. Joris ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.