On Feb 7, 2010, at 8:14 PM, David Winsemius wrote:
On Feb 7, 2010, at 7:51 PM, Vadlamani, Satish {FLNA} wrote:
Folks:
Good day. Please see the code below. three_wk_out is a dataframe
with columns wk1 through wk209. I want to change the format of the
columns. I am trying the code below but it does not work. I need
$week in the for loop interpreted as wk1, wk2, etc. Could you
please help? Thanks.
Satish
R code below
week_list <- paste("wk",c(1:209),sep="")
Or more "functionally":
three_wk_out <- as.data.frame( lapply(three_wk_out, some_function) )
Or if you wanted to just change the particular columns that matched
the "wk" pattern:
idx <- grep("wk", names(three_wk_out))
three_wk_out[, idx ] <- apply( three_wk_out[, idx ], 2, as.numeric)
(I probably should have used apply( ___ , 2, fn) in the prior effort
rather than coercing a list back to a dataframe.)
E.g.:
>
a b c x
1 1 0 0 1
2 2 3 2 4
3 1 2 1 5
4 2 0 3 2
> df <- as.data.frame(lapply(df, "^", 2))
> df
a b c x
1 1 0 0 1
2 16 81 16 256
3 1 16 1 625
4 16 0 81 16
for (week in week_list)
{
three_wk_out$week <- as.numeric(three_wk_out$week)
}
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
