Why are you adding as.integer before the factor statement? You are forcing
the variable to be an integer even tough you are passing factor within the
statement. Try
Lease$ID <-factor(Lease$EarlyTermination)
Cheers
Francisco
>From: Haibo Huang <[EMAIL PROTECTED]>
>To: [EMAIL PROTECTED]
>Subject: [R] Convert numeric to factor
>Date: Wed, 3 Aug 2005 13:52:13 -0700 (PDT)
>
>Hi,
>
>I tried to do a logistic regression with polr(MASS). I
>thought I already converted the response to factor,
>but obvious I was wrong. Could anyone tell me what I
>did wrong and how to correct it? Thank you very much!
>
> > Lease=read.csv("LeaseDummy.csv", header=TRUE)
> > Lease$ID <-
>as.integer(factor(Lease$EarlyTermination))
> >
> >
>RegA=polr(ID~1+MSA+SIC.Code+TenantOption+LLOption+TOExercised,
>
>+ data=Lease, method=c("logistic"))
>Error in polr(ID ~ 1 + MSA + SIC.Code + TenantOption +
>LLOption + TOExercised, :
> response must be a factor
> > summary(RegA)
>
>
>Best,
>Ed.
>
>
>
>
>--- Jean Eid <[EMAIL PROTECTED]> wrote:
>
> >
> > if labda is the elements of the vector and you know
> > what kexp is , you can
> > use apply
> >
> > apply(your_vector, 1, function(x) 1-
> > exp^(kexp^(-x)))
> >
> >
> > HTH
> >
> > Jean
> > On Wed, 3 Aug 2005, Rangesh Kunnavakkam wrote:
> >
> > > I have a large vector of around 12597 elements
> > and I wish to calculate
> > > p-value for each element using a formula of
> > something like:
> > > p-value= 1-
> > exp^(kexp^(-labda))
> > > I was wondering someone could give some ideas how
> > to implement for each element.
> > > thankyou very much
> > > Rangesh.K
> > >
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> >
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>
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