I don't know how to keep factors' levels with :
data.frame(mapply(function(x,y,z) ifelse(is.na(y), z, y),
names(D), D, D2, SIMPLIFY=FALSE))
but in that way it's ok :
data.frame(mapply(function(z,x,y) { y[is.na(y)] <- x[is.na(y)] ; y },
names(D), D, D2, SIMPLIFY=F))
(?)
Uwe Ligges a écrit :
t c wrote:
Uwe,
FYI:
I tried: "data3 <- ifelse(is.na(data1), data2, data1)"
It seems to me that data3 is an array of length 100.
I do NOT end up with a dataset of 5 columns and 20 rows.
I have not read carefully enough, for a data.frame you can generalize
the approach as follows:
data.frame(mapply(function(x,y,z) ifelse(is.na(y), z, y),
names(D), D, D2, SIMPLIFY=FALSE))
Uwe Ligges
Uwe Ligges <[EMAIL PROTECTED]> wrote:
Tom wrote:
On Tue, 10 Jan 2006 20:25:23 -0500, r user wrote:
I have 2 dataframes, each with 5 columns and 20 rows.
They are called data1 and data2.I wish to create a
third dataframe called data3, also with 5 columns and
20 rows.
I want data3 to contains the values in data1 when the
value in data1 is not NA. Otherwise it should contain
the values in data2.
I have tried afew methids, but they do not seem to
work as intended.:
data3<-ifelse(is.na(data1)=F,data1,data2)
and
data3[,]<-ifelse(is.na(data1[,])=F,data1[,],data2[,])
Please suggest the “best� way.
"Better" way is to have the Syntax correct:
data3 <- ifelse(is.na(data1), data2, data1)
Please check the archives for almost millions of posts asking more or
less this question...!
Not sure about the bast but...
a<-c(1,2,3,NA,5)
b<-c(4,4,4,4,4)
c<-a
c[which(is.na(a))]<-b[which(is.na(a))]
Why do you want to know which()?
na <- is.na(a)
c[na] <- b[na]
Uwe Ligges
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