Thanks Gabor! This does exactly what I wanted.
One follow-up question, how to extract the var names, in this case y, z, from
the expression? The subset function creates a new object and this may be
expensive when the data has a lot of irrelevant collumns. So I thougth that I
could reduce this to the columns I actually need.
Thanks,
Vadim
----- Original Message -----
From: "Gabor Grothendieck" <[EMAIL PROTECTED]>
To: "Vadim Ogranovich" <[EMAIL PROTECTED]>
Cc: r-help@stat.math.ethz.ch
Sent: Friday, May 18, 2007 9:19:49 AM (GMT-0600) America/Chicago
Subject: Re: [R] subset arg in (modified) evalq
Try this:
with(subset(data, x > 0), summary(y + z))
On 5/18/07, Vadim Ogranovich <[EMAIL PROTECTED]> wrote:
> Hi,
>
> When using evalq to evaluate expressions within a say data.frame context I
> often wish there was a 'subset' argument, much like in lm() or any ather
> advanced regression model. I would be grateful for a tip how to do this.
>
> Here is an illustration of what I want:
>
> n <- 100
> data <- data.frame(x=rnorm(n), y=rnorm(y), z=rnorm(z))
>
> # this works
> evalq({ i <- 0<x; summary(y[i] + z[i]) }, data)
>
> # I want to do the above w/o explicit subscripting, e.g.
> myevalq(summary(y + z), subset=0<x, data)
>
> Thanks,
> Vadim
>
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>
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