Just take advantage of R's vectorized calculations as x <- seq(1:600)
.8^x Harold > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of livia > Sent: Tuesday, July 03, 2007 12:05 PM > To: r-help@stat.math.ethz.ch > Subject: [R] sequences > > > Hi, I would like to generate a series in the following form > (0.8^1, 0.8^2, ..., 0.8^600) Could anyone tell me how can I > achieve that? I am really new to R. > -- > View this message in context: > http://www.nabble.com/sequences-tf4019146.html#a11414836 > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
