Meanwhile I have recognized, that the breaks-option enforces density as the default. But if I try to force frequencies (freq=TRUE) I get the following feedback:
Warning message: the AREAS in the plot are wrong -- rather use freq=FALSE in: plot.histogram(r, freq = freq, col = col, border = border, angle = angle, And the machine hasn't promised too much: the result IS wrong. Yours, Mag. Ferri Leberl Am Freitag, den 06.07.2007, 16:17 -0400 schrieb Sarah Goslee: > The default of hist() is counts rather than percentages. > > Sarah > > On 7/6/07, Mag. Ferri Leberl <[EMAIL PROTECTED]> wrote: > > Dear everybody! > > Is ist easily possible to make up a histogram with absolute numbers > > instead of percentages? > > Thank you in advance! > > Yours, Mag. Ferri Leberl > > > > ___________________ ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.