Hi Ivan.

Try this simple code:

## load packages
library(phytools)
library(phangorn)
## get tips descended from each node
dd<-Descendants(tree,node=1:tree$Nnode+Ntip(tree),
     type="tips")
names(dd)<-1:tree$Nnode+Ntip(tree)
## get the NUMBER of tips from each node
nn<-sapply(dd,length)
## get corresponding node indices
nodes<-as.numeric(names(nn[which(nn==2)]))
## compute their heights above root
heights<-setNames(sapply(nodes,nodeheight,
     tree=tree),nodes)

This scales well up to trees with 1,000 or more tips IME. It gives you 
the /heights/ above the root of each node with two descendants (cherry). 
If your tree is ultrametric, to get the /depth/ you would just subtract 
this value from the total height of the tree.

Let me know if it works!!

All the best, Liam

Liam J. Revell
Professor of Biology, University of Massachusetts Boston
Web: http://faculty.umb.edu/liam.revell/


On 1/9/2023 5:37 PM, Ivan Magalhaes wrote:
> CAUTION: EXTERNAL SENDER
>
> Hi all,
> Perhaps a dumb question, but is there an easy way to count the number of 
> cherries in a given tree, and fetch their ages? (i.e. all the nodes with 
> exactly two descendants)
> Thanks! Best,Ivan
> --
> Dr. Ivan L. F. Magalhaes
>
> Postdoctoral fellow — División AracnologíaMuseo Argentino de Ciencias 
> Naturales "Bernardino Rivadavia"
> Av. Ángel Gallardo 470, C1405DJR, Buenos Aires, Argentina+54 11 4982-8370 
> ext. 169Website | ResearchGate | Twitter |iNaturalist | Lattes | CV-Ar | 
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