The documentation of impersonate-procedure states that if it is invoked with wrapper-proc equals #f and that there are no props, then the result is proc "unimpersonated".
However, neither the impersonator wrapper-function nor the impersonator properties are removed in the following program, and the resulting function is still an impersonator?. What does "unimpersonated" mean then? (define-values (imp-prop:a imp-prop:a? imp-prop:a-get) (make-impersonator-property 'a)) (define (add8 n) (+ n 8)) (define impersonated (impersonate-procedure add8 (lambda (x) (+ x 1)) imp-prop:a "a value")) (define unimpersonated (impersonate-procedure impersonated #f)) (unimpersonated 10) ;=> 19 (impersonator? unimpersonated) ;=> #t (imp-prop:a? unimpersonated) ;=> #t (imp-prop:a-get unimpersonated) ;=> "a value" Best, Shu-Hung -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
