Actually, Gary, you are 180 degrees out. On a pass cavity, off frequency 
signals see a very high impedence path, an open not a short. If your version 
were true you could never use pass cans as a duplexer since both sets of cans 
together would show a "short" to EVERYTHING. 

The T connector is just an impedence bump to the radio equipment, nothing more. 
It is not an active device, like a preamp would be, that makes the rest of the 
feedline disappear.

He can use the T connector and any random length of cable to connect, as long 
as the whole feedline doesn't show up as a resonant length.

Dan N8DJP


    Posted 
by: "Gary Schafer" gascha...@comcast.net
 k4fmx
    Date: Wed Mar 10, 2010 10:47 am ((PST))

Well yes 
the T is sort of a magical device that makes the OTHER SIDE of the
T 
disappear electrically. Actually it is not the T itself that does the 
job
(that is just where IT happens) but it is the quarter wave length
 cables
that perform the magic!  

 

Without the quarter
 wave length cables between the T and each set of
cavities the 
duplexer would not work! That is what provides the 50 ohm
isolation 
between tx and rx cans so the feed line still sees 50 ohms.

The 
quarter wave cable effectively "disconnects" the transmitter from the
feed
 line at the T (at the receive frequency).

The quarter wave cable
 on the receive side of the T effectively disconnects
the receive 
side from the feed line (at the transmit frequency). 

Without 
doing this each would load the other down and there would not be 50
ohms
 at the antenna port of the T.

 

Once you are on the other
 side of the T (the antenna port) the feed line
length has no effect 
on the duplexer operation. All that the quarter wave
lines do on the 
duplexer side of the T are to give isolation to the opposite
side 
(tx-rx) so each does not short out the feed line.

 

A 
similar thing happens between can cables in a duplexer but rather than
using
 them for isolation they are used to enhance the notch of each can by
presenting
 a high impedance at each cans T from the previous cavity. Working
with
 a high impedance is easier to notch out than a low impedance.

 

The
 notch in the first cavity presents a short (low impedance) at the
unwanted 
 frequency and 50 ohms at the wanted frequency. By coupling the
next 
cavity with a quarter wave length cable (at the unwanted frequency)
that
 short is transformed to a quite high impedance at the next cavity while
at
 the same time the wanted signal being at 50 ohms is passed to the next
cavity
 where it sees 50 ohms and goes on its way unatenuated. But we are
left
 with the high impedance at the unwanted frequency that was transformed
by
 the quarter wave cable. The second cavity notch is also tuned to the
unwanted
 frequency which it pulls down to a short (low impedance) to give
further
 attenuation.

 

When I say the notch presents a "short" it
 is not really a short but a very
low impedance of say a few ohms. 
But by having the unwanted source impedance
high rather than at 50 
ohms it is much easier to pull the high impedance
down with the "few 
ohms" short circuit than it would be if we were working
at 50 ohms 
for the unwanted.

It works like a voltage divider between the two
 impedances. The higher the
source is (from previous cavity) to the 
short the more loss there will be
which is just what we are looking 
for.

 

In the case of the quarter wave cable to the T on 
the output of the duplexer
we want to transform the low impedance up 
to a very high impedance at the T
so that it does not load the 
circuit at that point on that frequency.

 

73


Gary 
 K4FMX



      

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