Oh that's why! Thank you because that is exactly the problem!
On Tue, Nov 14, 2023, 4:54 AM John H Palmieri <jhpalmier...@gmail.com>
wrote:
> Isn't log(log(x)^2) = 2 * log(log(x))? Is this your concern, or is it the
> absolute value?
>
> On Monday, November 13, 2023 at 1:32:11 PM UTC-8 Bùi Gia Nghĩa wrote:
>
>> Hi!
>> I have used Sage Cell Server to integrate the function (ln(x)^2 - 1) / (x
>> * ln(x)). It should resulted in (ln(x)^2) / 2 - |ln(ln(x))| + C, as noted
>> by my textbook and Wolfram|Alpha, but instead resulted in 1/2*log(x)^2 -
>> 1/2*log(log(x)^2).
>> (I do notice that SageMath use log(a) to denote natural logarithm, so
>> that's not the question here).
>> Anyone knows why it happen? I think that this is a bug from some system
>> SageMath use to calculate this, but I am new to SageMath so have zero
>> knowledge about the system.
>> Here is the exact code I input:
>> var("x")
>> f = (log(x)**2 - 1) / (x * log(x))
>> integral(f, x)
>>
>> Thanks in advance!
>>
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