Time::Local let me faint
Hello,lists, Please see these two lines' output: [$ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,8,2006)' Day '31' out of range 1..30 at -e line 1 $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,2006)' 1156953600 I translate the time of '2006-7-31 00:00:00' to unix timestamp,it's successful. But when I translate the time of '2006-8-31 00:00:00' to unix timestamp,it said '31 out of range'. I'm so faint that August doesn't have 31th day?Please tell me why this happen and how to resolve it. Thank you very much.
Re: Time::Local let me faint
Because SEPTEMBER only has thirty days. 0 - January; 1 - February; 2 - March; ... --L -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Time::Local let me faint
On 8/29/06, Practical Perl [EMAIL PROTECTED] wrote: But when I translate the time of '2006-8-31 00:00:00' to unix timestamp,it said '31 out of range'. I'm so faint that August doesn't have 31th day?Please tell me why this happen and how to resolve it. from perldoc Time::Local It is worth drawing particular attention to the expected ranges for the values provided. The value for the day of the month is the actual day (ie 1..31), while the month is the number of months since January (0..11). This is consistent with the values returned from localtime() and gmtime(). That means $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,8,2006)' Day '31' out of range 1..30 at -e line 1 is trying to get 31/Sep/2006 which does not exist $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,2006)' 1156953600 is getting 31/Aug/2006 which is alright. Regards, Adriano Ferreira. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Time::Local let me faint
Thank you,:-) For the intuition I treated '8' as August in Time::Local's method...A low-level mistake. 2006/8/30, Lawrence Statton XE1/N1GAK [EMAIL PROTECTED]: Because SEPTEMBER only has thirty days. 0 - January; 1 - February; 2 - March; ... --L -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Time::Local let me faint
Practical Perl wrote: Hello,lists, Please see these two lines' output: [$ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,8,2006)' Day '31' out of range 1..30 at -e line 1 $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,2006)' 1156953600 I translate the time of '2006-7-31 00:00:00' to unix timestamp,it's successful. But when I translate the time of '2006-8-31 00:00:00' to unix timestamp,it said '31 out of range'. I'm so faint that August doesn't have 31th day?Please tell me why this happen and how to resolve it. Thank you very much. I believe it is because the months are 0-indexed (0-11), so timelocal(0,0,0,31,8,2006) is 2006-7-31 *not* 2006-8-31. It also say so in the documentation. perldoc Time::Local Hope it helps. -- Flemming Greve SkovengaardThe killer's breed or the Demon's seed, a.k.a Greven, TuxPowerThe glamour, the fortune, the pain, [EMAIL PROTECTED] Go to war again, blood is freedom's stain, 4011.74 BogoMIPS Don't you pray for my soul anymore. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Time::Local let me faint
Practical Perl wrote: Hello,lists, Hello, Please see these two lines' output: [$ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,8,2006)' Day '31' out of range 1..30 at -e line 1 $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,2006)' 1156953600 I translate the time of '2006-7-31 00:00:00' to unix timestamp,it's successful. But when I translate the time of '2006-8-31 00:00:00' to unix timestamp,it said '31 out of range'. I'm so faint that August doesn't have 31th day?Please tell me why this happen and how to resolve it. localtime EXPR Converts a time as returned by the time function to a 9-element list with the time analyzed for the local time zone. Typically used as follows: # 012 3 45 6 7 8 ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time); All list elements are numeric, and come straight out of the C ‘struct tm’. $sec, $min, and $hour are the seconds, minutes, and hours of the specified time. $mday is the day of the month, and $mon is the month itself, in the range 0..11 with 0 indicating January and 11 indicating December. $year is the number of years since 1900. That is, $year is 123 in year 2023. $wday is the day of the week, with 0 indicating Sunday and 3 indicating Wednesday. $yday is the day of the year, in the range 0..364 (or 0..365 in leap years.) $isdst is true if the specified time occurs during daylight savings time, false otherwise. So if you want to translate 31 August 2006 you have to subtract one from the month and 1900 from the year: $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,106)' 1157007600 John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Time::Local let me faint
So if you want to translate 31 August 2006 you have to subtract one from the month and 1900 from the year: $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,106)' 1157007600 John, For the instance described by you,both '2006' and '106' are right. $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,106)' 1156953600 $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,2006)' 1156953600 -- Jeff Pang NetEase AntiSpam Team http://corp.netease.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Time::Local let me faint
Jeff Pang wrote: So if you want to translate 31 August 2006 you have to subtract one from the month and 1900 from the year: $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,106)' 1157007600 John, For the instance described by you,both '2006' and '106' are right. $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,106)' 1156953600 $ perl -Mstrict -MTime::Local -le 'print timelocal(0,0,0,31,7,2006)' 1156953600 The reason that '2006' works is because Time::Local makes a guess that '2006' actually means '106'. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
