Mike Frysinger wrote:
not sure if this is a bug or feature ... take this little snippet:
testit() {
local foo=$(false) ; echo $?
foo=$(false) ; echo $?
}
when we run the code, the output is:
0
1
rather than intuitive:
1
1
It's intentional.
`local' returns success if the variable is correctly assigned a value
(for instance, the variable is not read-only). The assignment statement
returns failure because that's how POSIX says assignment statements
behave. (export and readonly behave the same way as local.)
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
( ``Discere est Dolere'' -- chet )
Live Strong. No day but today.
Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://cnswww.cns.cwru.edu/~chet/
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