Re: Looping idiom
uau cutting the Gordian knot On 8 sep, 05:39, Timothy Pratley timothyprat...@gmail.com wrote: Yet another way :) user= (map + (rest a) a) (3 5 7 9 11) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
Re: Looping idiom
On Sep 8, 5:39 am, Timothy Pratley timothyprat...@gmail.com wrote: Yet another way :) user= (map + (rest a) a) (3 5 7 9 11) wow! i like your solution! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
Re: Looping idiom
Very very slick :) On Sep 7, 11:39 pm, Timothy Pratley timothyprat...@gmail.com wrote: Yet another way :) user= (map + (rest a) a) (3 5 7 9 11) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
Looping idiom
Very basic question. What's the idiom for producing a new seq wherein each val is based on pairs from an existing seq, e.g.: ; add together n0 n1, n1 n2, n2 n3, etc. [1 2 3 4 5 6] ; giving... [3 5 7 9 11] The verbose way would be something like: (loop [s origSeq n [ ]) (let [a (first origSeq) b (second origSeq)] (if (nil? b) n (recur (rest origSeq) (conj n (+ a b)) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
Re: Looping idiom
should read: (loop [s origSeq n [ ]) (let [a (first s b (second s)] (if (nil? b) n (recur (rest s) (conj n (+ a b)) On Sep 7, 6:51 pm, Brian Will brian.thomas.w...@gmail.com wrote: Very basic question. What's the idiom for producing a new seq wherein each val is based on pairs from an existing seq, e.g.: ; add together n0 n1, n1 n2, n2 n3, etc. [1 2 3 4 5 6] ; giving... [3 5 7 9 11] The verbose way would be something like: (loop [s origSeq n [ ]) (let [a (first origSeq) b (second origSeq)] (if (nil? b) n (recur (rest origSeq) (conj n (+ a b)) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
Re: Looping idiom
I'd use map, reduce, partial, and partition like so user=(map (partial reduce +) (partition 2 1 [1 2 3 4 5 6])) (3 5 7 9 11) On Sep 7, 9:53 pm, Brian Will brian.thomas.w...@gmail.com wrote: should read: (loop [s origSeq n [ ]) (let [a (first s b (second s)] (if (nil? b) n (recur (rest s) (conj n (+ a b)) On Sep 7, 6:51 pm, Brian Will brian.thomas.w...@gmail.com wrote: Very basic question. What's the idiom for producing a new seq wherein each val is based on pairs from an existing seq, e.g.: ; add together n0 n1, n1 n2, n2 n3, etc. [1 2 3 4 5 6] ; giving... [3 5 7 9 11] The verbose way would be something like: (loop [s origSeq n [ ]) (let [a (first origSeq) b (second origSeq)] (if (nil? b) n (recur (rest origSeq) (conj n (+ a b)) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
Re: Looping idiom
Yet another way :) user= (map + (rest a) a) (3 5 7 9 11) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~--~~~~--~~--~--~---
