Re: [CMake] ARGC != list(LENGTH ARGV) and ARGV0 != list(GET ARGV 0)
CMake will not expand a string into a list when passed as arguments. It
would do when using a variable:
While this is true, it's also not the whole truth (and I guess is that this is
bothering Clark). Consider the following two function calls:
foo1(a;b;c)
foo2(a;b c)
Of course cmake recognises foo1 as having one parameter, and foo2 as having 2
parameters. And if you do use names arguments in your function, or access the
function arguments by their positional arguments, it works as expected:
function(foo2)
message(Arg0: ${arg0}) # Arg0: a;b
message(${ARGC} arguments.) # 2 Arguments.
endfunction()
If, however you try to access the argument list as a whole, you fall in the
list of lists trap. CMake can not have lists as elements of other lists.
Trying to use the ARGV or ARGN lists in the above example will not achieve
what you are trying to do, because when cmake assembles the list of arguments,
the (for lack of a better word) list property is lost:
set(mylist)
list(ADD mylist a;b)
list(LENGTH mylist n)
message( length is ${n}) # length is 2
Cheers,
Johannes
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Re: [CMake] ARGC != list(LENGTH ARGV) and ARGV0 != list(GET ARGV 0)
Am Freitag, 11. Oktober 2013, 12:07:58 schrieb Clark WANG:
See following example:
$ cmake --version
cmake version 2.8.11.2
$ cat CMakeLists.txt
cmake_minimum_required(VERSION 2.8)
FUNCTION(foo)
list(LENGTH ARGV argc)
message(ARGC=${ARGC} list(LENGTH ARGV)=${argc})
list(GET ARGV 0 argv0)
message(ARGV0=${ARGV0} list(GET ARGV 0)=${argv0})
ENDFUNCTION()
foo(a;b;c)
$ cmake .
ARGC=1 list(LENGTH ARGV)=3
ARGV0=a;b;c list(GET ARGV 0)=a
-- Configuring done
-- Generating done
-- Build files have been written to: /root/tmp
$
I know ';' is special in cmake but it's counter-intuitive that ARGC !=
list(LENGTH ARGV). Is this a bug?
CMake will not expand a string into a list when passed as arguments. It would
do when using a variable:
set(foovar a;b;c)
foo(${foovar})
ARGC=3 list(LENGTH ARGV)=3
ARGV0=a list(GET ARGV 0)=a
Eike
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Re: [CMake] ARGC != list(LENGTH ARGV) and ARGV0 != list(GET ARGV 0)
On Fri, Oct 11, 2013 at 2:20 PM, Rolf Eike Beer e...@sf-mail.de wrote:
Am Freitag, 11. Oktober 2013, 12:07:58 schrieb Clark WANG:
See following example:
$ cmake --version
cmake version 2.8.11.2
$ cat CMakeLists.txt
cmake_minimum_required(VERSION 2.8)
FUNCTION(foo)
list(LENGTH ARGV argc)
message(ARGC=${ARGC} list(LENGTH ARGV)=${argc})
list(GET ARGV 0 argv0)
message(ARGV0=${ARGV0} list(GET ARGV 0)=${argv0})
ENDFUNCTION()
foo(a;b;c)
$ cmake .
ARGC=1 list(LENGTH ARGV)=3
ARGV0=a;b;c list(GET ARGV 0)=a
-- Configuring done
-- Generating done
-- Build files have been written to: /root/tmp
$
I know ';' is special in cmake but it's counter-intuitive that ARGC !=
list(LENGTH ARGV). Is this a bug?
CMake will not expand a string into a list when passed as arguments.
Yes I know this. But after the literal string is passed to the function, it
is broken into a list (ARGV). And the ARGC value is not consistent with the
length of of ARGV which I've never seen in other languages. And this
behavior makes it difficult to pass parameters around between cmake
functions.
It would
do when using a variable:
set(foovar a;b;c)
foo(${foovar})
ARGC=3 list(LENGTH ARGV)=3
ARGV0=a list(GET ARGV 0)=a
Eike
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Re: [CMake] ARGC != list(LENGTH ARGV) and ARGV0 != list(GET ARGV 0)
On Fri, Oct 11, 2013 at 2:20 PM, Rolf Eike Beer e...@sf-mail.de wrote:
Am Freitag, 11. Oktober 2013, 12:07:58 schrieb Clark WANG:
See following example:
$ cmake --version
cmake version 2.8.11.2
$ cat CMakeLists.txt
cmake_minimum_required(VERSION 2.8)
FUNCTION(foo)
list(LENGTH ARGV argc)
message(ARGC=${ARGC} list(LENGTH ARGV)=${argc})
list(GET ARGV 0 argv0)
message(ARGV0=${ARGV0} list(GET ARGV 0)=${argv0})
ENDFUNCTION()
foo(a;b;c)
$ cmake .
ARGC=1 list(LENGTH ARGV)=3
ARGV0=a;b;c list(GET ARGV 0)=a
-- Configuring done
-- Generating done
-- Build files have been written to: /root/tmp
$
I know ';' is special in cmake but it's counter-intuitive that ARGC !=
list(LENGTH ARGV). Is this a bug?
CMake will not expand a string into a list when passed as arguments. It
would
do when using a variable:
set(foovar a;b;c)
foo(${foovar})
It's not quite about using a variable or not. For your example,
foo(${foovar}) would give the same result as mine.
ARGC=3 list(LENGTH ARGV)=3
ARGV0=a list(GET ARGV 0)=a
Eike
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Re: [CMake] ARGC != list(LENGTH ARGV) and ARGV0 != list(GET ARGV 0)
Am Freitag, 11. Oktober 2013, 14:49:18 schrieb Clark WANG:
On Fri, Oct 11, 2013 at 2:20 PM, Rolf Eike Beer e...@sf-mail.de wrote:
Am Freitag, 11. Oktober 2013, 12:07:58 schrieb Clark WANG:
See following example:
$ cmake --version
cmake version 2.8.11.2
$ cat CMakeLists.txt
cmake_minimum_required(VERSION 2.8)
FUNCTION(foo)
list(LENGTH ARGV argc)
message(ARGC=${ARGC} list(LENGTH ARGV)=${argc})
list(GET ARGV 0 argv0)
message(ARGV0=${ARGV0} list(GET ARGV 0)=${argv0})
ENDFUNCTION()
foo(a;b;c)
$ cmake .
ARGC=1 list(LENGTH ARGV)=3
ARGV0=a;b;c list(GET ARGV 0)=a
-- Configuring done
-- Generating done
-- Build files have been written to: /root/tmp
$
I know ';' is special in cmake but it's counter-intuitive that ARGC !=
list(LENGTH ARGV). Is this a bug?
CMake will not expand a string into a list when passed as arguments. It
would
do when using a variable:
set(foovar a;b;c)
foo(${foovar})
It's not quite about using a variable or not. For your example,
foo(${foovar}) would give the same result as mine.
Yes, of course. And that's basically the whole point: by the quotes you tell
CMake to interpret the stuff as string at this point.
foo(a;b;c)
should give your expected result, too.
Eike
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