[jQuery] Deserialize array
I have some serialized data
stories[]={'link':'http://digg.com/videos_gaming/Just_how_different_IS_Wii_Madden_%28answer%3A_very%29','title':'Just
how different IS Wii Madden? (answer: very)','date':'19 Oct
2006','description':'I knew Wii Madden allowed for juking, passing, etc with
the Wii remote, but this new video is the first one that really shows how
sports games will be revolutionized. Includes interviews/demonstrations with
the developers
producers.'}stories[]={'link':'http://digg.com/general_sciences/Gravity_Measurements_Confirm_Greenland_s_Glaciers_Precipitous_Meltdown','title':'Gravity
Measurements Confirm Greenland's Glaciers Precipitous Meltdown','date':'19 Oct
2006','description':'Of late, the enormous glaciers that flowdown to the sea
from the interior of Greenland have been picking up speed. In the last few
years, enough ice has come off the northern landmass to sustain the average
flow of the Colorado River for six years or fill Lake Mead three times over or
cover the state of Maryland in 10 feet of water.'}
I have serialized data like this. How can I loop through this and deserialize
it putting it into forms using jQuery Form Deserialization Plugin
http://www.reach1to1.com/sandbox/jquery/testform.html
-TJ
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[jQuery] Ajax login
Hi I am really having trouble using ajax function to make a login form. Here is
what I have so far.
Any ideas?
script type=text/javascript language=JavaScript
$(document).ready(function(){
$('form').submit(function(){
$.ajax({
url: process.php,
type: POST,
data: $.param( $(#login).formdata()),
success: function(msg){ alert( Logged in: +
msg ); } });
});
});
});
/script
form
Username:input type=text name=user maxlength=30
br/ Password:input type=password name=pass maxlength=30
input type=submit value=Login
/form
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[jQuery] Ajax login
I added the login, sorry about that
When I execute I get the vars in the address bar
http://www.tjshafer.com/baintown/main.php?user=testpass=testsublogin=1
script type=text/javascript language=JavaScript
$(document).ready(function(){
$('form').submit(function(){
$.ajax({
url: process.php,
type: POST,
data: $.param( $(#login).formdata()),
success: function(msg){ alert( Data Saved: +
msg ); } });
});
});
});
/script
form id=login
Username:input type=text name=user maxlength=30
br/ Password:input type=password name=pass maxlength=30
input type=checkbox name=remember
!--font size=2Remember me next time nbsp;nbsp;nbsp;nbsp;--
input type=hidden name=sublogin value=1
input type=submit value=Login
!--brfont size=2[a href=forgotpass.phpForgot Password?/a]/font
brNot registered? a href=register.phpSign-Up!/a--
/form
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[jQuery] ajax login
I have updated to this with the return false. I am still getting the same error.
Any suggestions?
Thanks!
script type=text/javascript language=JavaScript
$(document).ready(function(){
$('form').submit(function(){
element = $('[EMAIL PROTECTED]').get(0);
myusername = element.value;
mypassword = $('[EMAIL PROTECTED]').get(0).value;
$.post('process.php', {username: myusername, name: mypassword});
element.value = '';
return false;
});
});
/script
form
Username:input type=text name=user maxlength=30
br/ Password:input type=password name=pass maxlength=30
input type=checkbox name=remember
!--font size=2Remember me next time nbsp;nbsp;nbsp;nbsp;--
input type=hidden name=sublogin value=1
input type=submit value=Login
!--brfont size=2[a href=forgotpass.phpForgot Password?/a]/font
brNot registered? a href=register.phpSign-Up!/a--
/form
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[jQuery] Drop down menu
Hi, I am trying to make a drop down menu. I have half of it but I need a sub
menu off to the left. I am using this jquery code.
$(document).ready(function(){
$(#nav-one li).hover(
function(){ $(ul, this).fadeIn(slow); },
function() { }
);
if (document.all) {
$(#nav-one li).hoverClass (sfHover);
}
$(#subnav li).hover(
function(){ $(ul, this).fadeIn(slow); },
function() { }
);
if (document.all) {
$(#subnav li).hoverClass (sfHover);
}
});
$.fn.hoverClass = function(c) {
return this.each(function(){
$(this).hover(
function() { $(this).addClass(c); },
function() { $(this).removeClass(c); }
);
});
};
Here is the page it is one.
http://www.tjshafer.com/cortek/
Any ideas?
Thanks, TJ
http://www.tjshafer.com/cortek/
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[jQuery] jq corner.js
Hi I am using the jq-corner.js written by Dave Methvin. I was wondering how I
could add a option for color when calling the corner.
$(#content).corner(round tl 10px color);
Heres the script
//
// jq-corner.js - JQuery method for creating corner effects
//
// If this works, it was written by Dave Methvin ([EMAIL PROTECTED]).
// If its broken, please fix it and send me a working copy.
//
$.fn.corner = function(o)
{
function hex2(s) {
var s = parseInt(s).toString(16);
if ( s.length 2 ) s = 0+s;
return s;
}
function gpc(node) {
for ( ; node node.nodeName.toLowerCase() != html; node =
node.parentNode ) {
var v = $.css(node,backgroundColor);
if ( v.indexOf(rgb) = 0 ) {
rgb = v.match(/\d+/g);
return #+ hex2(rgb[0]) + hex2(rgb[1]) +
hex2(rgb[2]);
}
if ( v v != transparent )
return v;
}
return #ff;
};
o = o || ;
var width = parseInt((o.match(/(\d+)px/)||[])[1]) || 10;
var fx = (o.match(/round|bevel|fold|notch/)||[round])[0];
var opts = {
TL: /top|tl/i.test(o), TR:
/top|tr/i.test(o),
BL: /bottom|bl/i.test(o), BR:
/bottom|br/i.test(o)//,
};
if ( !opts.TL !opts.TR !opts.BL !opts.BR )
opts = { TL:1, TR:1, BL:1, BR:1 };
var strip = document.createElement(div);
strip.style.overflow = hidden;
strip.style.height = 1px;
strip.style.backgroundColor = transparent;
strip.style.borderStyle = solid;
return this.each(function(){
var pad = {
T: parseInt($.css(this,paddingTop))||0,
R: parseInt($.css(this,paddingRight))||0,
B: parseInt($.css(this,paddingBottom))||0,
L: parseInt($.css(this,paddingLeft))||0
};
strip.style.borderColor = gpc(this.parentNode);
if ( opts.TL || opts.TR ) {
strip.style.borderStyle = none
+(opts.TR?solid:none)+ none +(opts.TL?solid:none);
var t=document.createElement(div);
t.style.margin = -+pad.T+px -+pad.R+px
+(pad.T-width)+px -+pad.L+px;
t.style.backgroundColor = transparent;
for ( var i=0; i width; i++ ) {
var w = fx==round ?
Math.round(width*(1-Math.cos(Math.asin(i/width : i+1;
var e = strip.cloneNode(false);
e.style.borderWidth = 0 +(opts.TR?w:0)+px 0
+(opts.TL?w:0)+px;
t.insertBefore(e, t.firstChild);
}
this.insertBefore(t, this.firstChild);
}
if ( opts.BL || opts.BR ) {
strip.style.borderStyle = none
+(opts.BR?solid:none)+ none +(opts.BL?solid:none);
var b=document.createElement(div);
b.style.margin = (pad.B-width)+px -+pad.R+px
-+pad.B+px -+pad.L+px;
b.style.backgroundColor = transparent;
for ( var i=0; i width; i++ ) {
var w = fx==round ?
Math.round(width*(1-Math.cos(Math.asin(i/width : i+1;
var e = strip.cloneNode(false);
e.style.borderWidth = 0 +(opts.BR?w:0)+px 0
+(opts.BL?w:0)+px;
b.appendChild(e);
}
this.appendChild(b);
}
});
};
Thanks for any help
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[jQuery] Rollover
Hi, I am trying to add a image rollover. I am applying it to a div before a li.
div id=navcontainer
ul
div id=roll/divlia href=index.phpHome/A/li
div id=roll/divlia href=news.phpNews/a/li
div id=roll/divlia href=news.php?mode=editEdit News/a/li
div id=roll/divlia href=index.php?page=newsorderNews Order/a/li
div id=roll/divlia href=frontpage_articles.phpFront Page
Articles/a/li
div id=roll/divlia href=minutes.phpMinutes Agendas/a/li
div id=roll/divlia href=forms.phpGeneral Forms/a/li
div id=roll/divlia href=special.phpSpecial Reports/a/li
div id=roll/divlia href=resource.php?mode=addLocal
Resources/a/li
div id=roll/divlia href=calendar.phpCalendar/a/li
div id=roll/divlia href=emaillist.phpEmail List/a/li
div id=roll/divlia href=siteoffline.phpTake Site Offline/a/li
div id=roll/divlia href=dbbackup.phpBack Up Database/a/li
/ul
/div
Here is the jquery I am trying.
script type=text/javascript
$(document).ready(function() {
$(a).hover(function(){
$(div#roll).addClass(over);
},
function(){
$(div#roll).addClass(out);
});
});
/script
Would this be right?
-TJ
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[jQuery] Jquery.com
What happened to the jquery.com site? ___ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
[jQuery] Suckerfish
Hi, I am using the suckerfish plugin. How can I make it so I can have a drop down menu from a drop down menu. -Menu | -menu 1 -menu 2 | - menu 2.1 - menu 2.2 -menu 3 -menu 4 Thanks -TJ ___ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
