Re: [Factor-talk] group-by word

2011-11-19 Thread P. 
Do it step by step - think about the steps you need to take.
I would first sort the array by length.
Then I would group them by length (look at the monotonic-split word for that).
That would be very close to what you want.

On Nov 19, 2011, at 12:49 PM, missingfaktor wrote:

 I want to write a word group-by that has following stack effect and 
 behavior:
 
 Signature: 
 
 : group-by ( seq quot -- alist ) (group-by-impl) ;
 
 Input: 
 
 { hello hola ball scala java factor python } [ length ] group-by
 
 Output:
 
 H{
   { 5 { hello scala } }
   { 4 { hola ball java } }
   { 6 { factor python } }
 }
 
 I tried this many times, but failed. Can someone please provide me an 
 implementation for this, preferably with an explanation?
 -- 
 Cheers,
 missingfaktor.
 
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Re: [Factor-talk] group-by word

2011-11-19 Thread Joe Groff 
You can look at math.statistics:collect-by as a reference:

USE: math.statistics

{ hello hola ball scala java factor python } [ length
] collect-by
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security threats, fraudulent activity, and more. Splunk takes this 
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Re: [Factor-talk] group-by word

2011-11-19 Thread John Benediktsson 
You might also be interested in this blog post, which walks through how to
build a group-by word:

http://re-factor.blogspot.com/2011/04/group-by.html



On Sat, Nov 19, 2011 at 10:19 AM, Joe Groff arc...@gmail.com wrote:

 You can look at math.statistics:collect-by as a reference:

 USE: math.statistics

 { hello hola ball scala java factor python } [ length
 ] collect-by


 --
 All the data continuously generated in your IT infrastructure
 contains a definitive record of customers, application performance,
 security threats, fraudulent activity, and more. Splunk takes this
 data and makes sense of it. IT sense. And common sense.
 http://p.sf.net/sfu/splunk-novd2d
 ___
 Factor-talk mailing list
 Factor-talk@lists.sourceforge.net
 https://lists.sourceforge.net/lists/listinfo/factor-talk


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