[Bug c++/102802] Selection of inherited operator contrary to `using` clause in C++ when using lambda type

[fchelnokov at gmail dot com via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=102802

Fedor Chelnokov  changed:

   What|Removed |Added

 Resolution|--- |WONTFIX
 Status|NEW |RESOLVED

--- Comment #4 from Fedor Chelnokov  ---
Thanks for TC's explanation! This is an equivalent code to the question, but
without lambdas: gcc.godbolt.org/z/38T35Yfvs 

GCC is correct in processing the original code, closing the issue.

[Bug c++/102802] Selection of inherited operator contrary to `using` clause in C++ when using lambda type

[rs2740 at gmail dot com via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=102802

TC  changed:

   What|Removed |Added

 CC||rs2740 at gmail dot com

--- Comment #3 from TC  ---
No, this is valid. B's operator() is not visible, but its conversion to
function pointer is, and that introduces a surrogate call function during the
overload resolution for the function call expression (and it's selected because
it is the only viable candidate).

[Bug c++/102802] Selection of inherited operator contrary to `using` clause in C++ when using lambda type

[pinskia at gcc dot gnu.org via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=102802

--- Comment #2 from Andrew Pinski  ---
ICC also rejects it.

[Bug c++/102802] Selection of inherited operator contrary to `using` clause in C++ when using lambda type

[pinskia at gcc dot gnu.org via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=102802

Andrew Pinski  changed:

   What|Removed |Added

 Status|UNCONFIRMED |NEW
 Ever confirmed|0   |1
   Last reconfirmed||2021-10-17
Summary|Selection of inherited  |Selection of inherited
   |operator contrary to|operator contrary to
   |`using` clause in C++   |`using` clause in C++ when
   ||using lambda type

--- Comment #1 from Andrew Pinski  ---
Confirmed.