Can someone explain why the one stack overflows and the other one doesn't?
iterateNTimes i f x = foldr (.) id (replicate i f) $ x tntIO :: IO Int -- same as replicateM (10^6) $ return 0 , and same as sequence . replicate (10^6) $ return 0 tntIO = iterateNTimes (10^6) (ap . liftM (:) . return $ ) (return []) -- produces output tntMb :: Maybe Int -- overflows tntMb = iterateNTimes (10^6) (ap . liftM (:) . return $ ) (return []) -- stack overflow _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
