Re: [mapguide-users] fusion error - searchStr.test is not a function
That's a good discussion, Jackie! I think 'test' is a method of the searchstr object that derives from Array.prototype.find. Testing, after Gordon's tips, on handling the versions in google api, I noticed that the latest version is assumed whenever no version is reported in the google api call. The last version in development is 3.32.8 and this searchstr.temp function does not exist in this context and for some reason, in the load of the google map, this routine that runs the searchStr.temp is executed and therefore gives the commented error. When we use any other version before that, in the map load, it simply does not pass through these lines in fusionSF.js, that is, it does not give an error, but it does not mean that it exists, but that simply in the previous versions of google api this routine is not called. Now why is running this now, only the google team could respond. Best Regards Sebafr -- Sent from: http://osgeo-org.1560.x6.nabble.com/MapGuide-Users-f4182607.html ___ mapguide-users mailing list mapguide-users@lists.osgeo.org https://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] fusion error - searchStr.test is not a function
Many thanks for your response GordonL! It worked, and now everything makes sense: google was the problem !!! I change as you said, and the version (v parameter) was the solution. The google api recommends putting only the main version and letting them choose the last released minor version for us, there I put only: v=3 and everything worked perfect. Thanks again for your time. Sebafr -- Sent from: http://osgeo-org.1560.x6.nabble.com/MapGuide-Users-f4182607.html ___ mapguide-users mailing list mapguide-users@lists.osgeo.org https://lists.osgeo.org/mailman/listinfo/mapguide-users
[mapguide-users] fusion error - searchStr.test is not a function
Today, all off ours mapguide servers (5 different places, 2 different versions) happened this error: fusionSF.js:132996 Uncaught TypeError: searchStr.test is not a function Looking at fusionSF,js i found this code: ... Array.prototype.find = function(searchStr) { var returnArray = null; for (i=0; i<this.length; i++) { if (typeof(searchStr) == 'function') { if (searchStr.test(this[i])) { if (!returnArray) { returnArray = [] } returnArray.push(i); } } else { if (this[i]===searchStr) { if (!returnArray) { returnArray = [] } returnArray.push(i); } } } return returnArray; }; Somebody knows whats happens ? I comment the lines below and everything works again, apparently well, but I wanted to know why? ... Array.prototype.find = function(searchStr) { var returnArray = null; for (i=0; i<this.length; i++) { if (typeof(searchStr) == 'function') { //if (searchStr.test(this[i])) { // if (!returnArray) { returnArray = [] } // returnArray.push(i); //} } else { if (this[i]===searchStr) { if (!returnArray) { returnArray = [] } returnArray.push(i); } } } return returnArray; }; thanks in advance sebafr -- Sent from: http://osgeo-org.1560.x6.nabble.com/MapGuide-Users-f4182607.html ___ mapguide-users mailing list mapguide-users@lists.osgeo.org https://lists.osgeo.org/mailman/listinfo/mapguide-users
[mapguide-users] new mapguide project on linux ubuntu
We are conducting initial studies for a project with Mapguide on a ubuntu Linux. We have a project running linux 12 with 32 bits, mapguide 2.6 and Postgresql 9.1 and now we would like to update it all and the first scenario was to use linux 14 with 64 bits and Mapguide 3.1 and Postgresql 9.4. Our current provider only supports 64-bit linux (14 or 16) and did not succeed in the initial tests. Has anyone ever used similar architecture? Thanks, Seba -- View this message in context: http://osgeo-org.1560.x6.nabble.com/new-mapguide-project-on-linux-ubuntu-tp5305975.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org https://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] Mapguide 3.0 Postgre view problem
solution 1: (for programers people !) note: '' is two Single quotation marks guide_generic_search_table('CASE when owner = 1 THEN ''one'' when owner = 2 then ''TWO'' END ', 'piping.pipe', 'pipe.dp_oid=' || symg.dp_oid) AS owner solution 2: (for normal people!) create a view vw_pipe with the field CASE when owner = 1 THEN 'one' when owner = 2 then 'TWO' END and use then on fuction: guide_generic_search_table('field_case', 'piping.vw_pipe', 'pipe.dp_oid=' || symg.dp_oid) AS owner -- View this message in context: http://osgeo-org.1560.x6.nabble.com/Mapguide-3-0-Postgre-view-problem-tp5298765p5299224.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] Mapguide 3.0 Postgre view problem
Hi Kajar, Yes for both issues. You have to keep in mind that the function requires 3 parameters 1) return field, which can be any valid expression, with when, other functions etc. But remember only one field (or expression) per function call 2) a table name, but can be a view for example 3) a filter expression, which can combine as many boolean expressions as necessary. Here the most important point, this expression should return only 1 line, or none. If you return more than one you will have an error of exception. The trick here is to combine the expression with the values you have from your main table. Knowing how to do this, the sky is the limit !!! ;-) Abs Seba -- View this message in context: http://osgeo-org.1560.x6.nabble.com/Mapguide-3-0-Postgre-view-problem-tp5298765p5299198.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] Mapguide 3.0 Postgre view problem
You should update the layer (recreate if need) and mapguide (if you need to stop and restart the service) Try and see if it works: 1) Try to create another view only from the main table (no join or function), remember to put the primary key in the view 2) Create a new layer for this new view 3) test the mapguide selection 4) If it works, please create a new layer for the view with the function and test again, remembering to include the primary key. The use of functions is not detected by mapguide as a join, so it should work! -- View this message in context: http://osgeo-org.1560.x6.nabble.com/Mapguide-3-0-Postgre-view-problem-tp5298765p5298852.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] Mapguide 3.0 Postgre view problem
Junction of two table for mapguide is already complex (a little ;-)) First you need to create this function in your postgres, then when creating the view you will only use a table in the "from" getting the second table or how many more are needed for use in the function. View example: Create view myview as Select cp1, cp2, guide_generic_search_table ('cp2_second_table', 'name_second_table', 'cp1_second_table_key =' || cp3_fk) as mypesq1 from mytable If you need help, please forward a your generic model view -- View this message in context: http://osgeo-org.1560.x6.nabble.com/Mapguide-3-0-Postgre-view-problem-tp5298765p5298817.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] Mapguide 3.0 Postgre view problem
Hi, I had the same problem here and really complex views do not work in the guide One solution is to use a function to get fields from the second table CREATE OR REPLACE FUNCTION public.guide_generic_search_table(vfield character varying, vNameTable character varying, vfilter character varying) RETURNS character varying AS $BODY$ DECLARE v_out character varying; cSQL character varying; BEGIN cSQL := 'SELECT '||vfield||' FROM '||vNameTable||' WHERE '||vfilter || ';'; EXECUTE cSQL INTO v_out; return (v_out); END; $BODY$ LANGUAGE plpgsql This way you cheat the mapguide, but it works! []s -- View this message in context: http://osgeo-org.1560.x6.nabble.com/Mapguide-3-0-Postgre-view-problem-tp5298765p5298792.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/mapguide-users
Re: [mapguide-users] Google Layers Not Showing - Fix to Open Layers
I have problem with google layers on mapguide. The big problem was everthing look fine when use SATELLITE option (G_SATELLITE_MAP), but if use another option (G_HYBRID_MAP or G_PHYSICAL_MAP etc) the map hangs and show nothing as base layer. This post solved this. Thanks a lot -- View this message in context: http://osgeo-org.1560.x6.nabble.com/Google-Layers-Not-Showing-Fix-to-Open-Layers-tp5268375p5270395.html Sent from the MapGuide Users mailing list archive at Nabble.com. ___ mapguide-users mailing list mapguide-users@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/mapguide-users