Am 22.03.2015 um 13:10 schrieb Fabrice Couvreur fabrice1.couvr...@gmail.com:
The alignment of the second item on the baseline is not correct if I use the
command \dfrac{}{}.
How to solve this problem without using the command \framed ?
Best regards,
Fabrice
\starttext
\startitemize[columns,A,joinedup,three][stopper={)},style=bold]
\item $f^{\prime}(x) = \dfrac{- 1}{(x + 1)^2}$
\item $f^{\prime}(x) = 1$
\item $f^{\prime}(x) = \dfrac{1}{x + 1}$
\stopitemize
\stoptext
1. You change your formulas.
\starttext
\startitemize[columns,A,joinedup,three][stopper={)},style=bold,grid=line]
\item $f^{\prime}(x) = - 1 / (x + 1)^2$
\item $f^{\prime}(x) = 1$
\item $f^{\prime}(x) = 1 / (x + 1)$
\stopitemize
\stoptext
2. You enable grid snapping for the columns in the itemize environment with the
grid key.
\starttext
\startitemize[columns,A,joinedup,three][stopper={)},style=bold,grid=line]
\item $f^{\prime}(x) = \dfrac{- 1}{(x + 1)^2}$
\item $f^{\prime}(x) = 1$
\item $f^{\prime}(x) = \dfrac{1}{x + 1}$
\stopitemize
\stoptext
3. You increase the line height for the columns in the itemize environment.
\setupmixedcolumns[itemgroupcolumns][before={\setupinterlinespace[big]}]
\starttext
\startitemize[columns,A,joinedup,three][stopper={)},style=bold]
\item $f^{\prime}(x) = \dfrac{- 1}{(x + 1)^2}$
\item $f^{\prime}(x) = 1$
\item $f^{\prime}(x) = \dfrac{1}{x + 1}$
\stopitemize
\stoptext
Wolfgang
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