El 26/08/2010, a las 20:29, Jerónimo Alaminos Prats escribió:
Hi all,
I've been following the examples in the garden to write the following table
\chardef\characteralignmentmode=1
\startTABLE
\setupTABLE[column][alignmentcharacter={,},aligncharacter=yes,align=middle]
\setupTABLE[frame=off]
\setupTABLE[row][first][bottomframe=on]
\NC \alpha \NC \beta \NC error absoluto\NC error relativo \NC \NR
\NC 2 \NC 2,1 \NC 0,1 \NC 0,05 \NC \NR
\NC 2\times 10\high{-4} \NC 2,1\times 10\high{-4} \NC 0,1\times
10\high{-4} \NC 0,05 \NC \NR
\NC 2\times 10\high{4}\NC 2,1\times 10\high{4} \NC 0,1\times
10\high{4} \NC 0,05 \NC\NR
\stopTABLE
Is there a way to have the entries of first row centered?
The obvious \setupTABLE[row][first][align=middle] do not have any effect.
Thanks,
Jeronimo.
I forgot about table. Sorry for the noise. The result that I was looking for
it's explained in the articles of Aditya on table macros.
\starttable[|l|cq1,5 |cq1,5 |cq1,2 |]
\NC\REF[cB]{\alpha} \NC \REF[cB]{$\alpha^{*}$} \NC \REF[cB]{error absoluto}\NC
\REF[cB]{error relativo} \NC \AR
\HL
\NC 2 \NC 2,1 \NC 0,1 \NC 0,05 \NC \AR
\NC 2\times 10\high{-4} \NC 2,1\times 10\high{-4} \NC 0,1\times 10\high{-4}
\NC 0,05 \NC \AR
\NC 2\times 10\high{4} \NC 2,1\times 10\high{4} \NC 0,1\times 10\high{4} \NC
0,05 \NC\AR
\HL
\stoptable
Best,
Jeronimo.
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