[NTG-context] how to get reference label from stacked itemize

2019-04-06 Thread Floris van Manen

> Did you try \item[myref] and \in[myref]?
> 

This will do the job indeed.

\starttext
\startitemize[n]
\item One
\item[refTwo] Two
\startitemize[a]
\item A
\item[refB] B Test
\stopitemize
\stopitemize

see (\in[refTwo].\in[refB]) for Test



Is there some construction to combine an item reference with its parent item?

\startitemize[n]
\item One
\item Two
\startitemize[a]
\item A
\item[refB] B Test
\stopitemize

see (\in[parent, refB].\in[refB]) for Test




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Re: [NTG-context] how to get reference label from stacked itemize

2019-04-06 Thread Henning Hraban Ramm
Am 2019-04-06 um 16:51 schrieb Floris van Manen :

> Could someone point me to the docs where to find the proper way to
> make a reference to some stacked itemize context?
> 
> 
> \startitemize[n]
> \item One
> \item Two
> \startitemize[a]
> \item A
> \item B Test
> \stopitemize
> \stopitemize
> 
> how to label / ref the generated label for item 2.b ?
> 
> see (2.b) Test

Did you try \item[myref] and \in[myref]?


Greetlings, Hraban
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[NTG-context] how to get reference label from stacked itemize

2019-04-06 Thread Floris van Manen
Could someone point me to the docs where to find the proper way to
make a reference to some stacked itemize context?


\startitemize[n]
\item One
\item Two
\startitemize[a]
\item A
\item B Test
\stopitemize
\stopitemize

how to label / ref the generated label for item 2.b ?

see (2.b) Test



Thanks!
.Floris van Manen




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