[perl #73460] [BUG] You can sneak a Block into a variable typed as a Whatever in Rakudo

2010-07-15 Thread jn...@jnthn.net via RT 
On Tue Mar 09 03:14:37 2010, masak wrote:
 moritz_ rakudo: my $x = *; say $x.WHAT
 p6eval rakudo de996e: OUTPUT«Block()␤»
 moritz_ now that's... confusing
 masak nod.

Now:

 my $x = *; say $x.WHAT
Whatever()

 moritz_ rakudo: say *.WHAT
 p6eval rakudo de996e: OUTPUT«Whatever()␤»

 say *.WHAT
Whatever()

 masak rakudo: say Block ~~ Whatever
 p6eval rakudo de996e: OUTPUT«0␤»

Still works as expected.

 masak rakudo: my Whatever $x = *; say $x.WHAT
 p6eval rakudo de996e: OUTPUT«Block()␤»

 my Whatever $x = *; say $x.WHAT
Whatever()

Given to moritz++ for test coverage of these.

Thanks,

Jonathan

[perl #73460] [BUG] You can sneak a Block into a variable typed as a Whatever in Rakudo

2010-03-10 Thread Carl Mäsak 
# New Ticket Created by  Carl Mäsak 
# Please include the string:  [perl #73460]
# in the subject line of all future correspondence about this issue. 
# URL: http://rt.perl.org/rt3/Ticket/Display.html?id=73460 


moritz_ rakudo: my $x = *; say $x.WHAT
p6eval rakudo de996e: OUTPUT«Block()␤»
moritz_ now that's... confusing
masak nod.
moritz_ rakudo: say *.WHAT
p6eval rakudo de996e: OUTPUT«Whatever()␤»
masak rakudo: say Block ~~ Whatever
p6eval rakudo de996e: OUTPUT«0␤»
masak rakudo: my Whatever $x = *; say $x.WHAT
p6eval rakudo de996e: OUTPUT«Block()␤»
* masak submits rakudobug