Re: r28061 - docs/Perl6/Spec

2009-08-25 Thread Richard Hainsworth

Suggest
s/right argument/right-hand argument/

Also suggest
s/** 2/** $y/
since it seems strange to be referring to a right-hand argument which, 
in the example, is a constant.


pugs-comm...@feather.perl6.nl wrote:

Author: carlin
Date: 2009-08-25 08:48:35 +0200 (Tue, 25 Aug 2009)
New Revision: 28061

Modified:
   docs/Perl6/Spec/S03-operators.pod
Log:
[S03] Don't not use no double negatives

Modified: docs/Perl6/Spec/S03-operators.pod
===
--- docs/Perl6/Spec/S03-operators.pod   2009-08-25 00:26:56 UTC (rev 28060)
+++ docs/Perl6/Spec/S03-operators.pod   2009-08-25 06:48:35 UTC (rev 28061)
@@ -569,7 +569,7 @@
 
 $x ** 2
 
-If the right argument is not a non-negative integer, the result is likely to

+Unless the right argument is a non-negative integer the result is likely to
 be an approximation.  If the right argument is of an integer type,
 exponentiation is at least as accurate as repeated multiplication on
 the left side's type.  (From which it can be deduced that CInt**UInt

  


r28061 - docs/Perl6/Spec

2009-08-25 Thread pugs-commits
Author: carlin
Date: 2009-08-25 08:48:35 +0200 (Tue, 25 Aug 2009)
New Revision: 28061

Modified:
   docs/Perl6/Spec/S03-operators.pod
Log:
[S03] Don't not use no double negatives

Modified: docs/Perl6/Spec/S03-operators.pod
===
--- docs/Perl6/Spec/S03-operators.pod   2009-08-25 00:26:56 UTC (rev 28060)
+++ docs/Perl6/Spec/S03-operators.pod   2009-08-25 06:48:35 UTC (rev 28061)
@@ -569,7 +569,7 @@
 
 $x ** 2
 
-If the right argument is not a non-negative integer, the result is likely to
+Unless the right argument is a non-negative integer the result is likely to
 be an approximation.  If the right argument is of an integer type,
 exponentiation is at least as accurate as repeated multiplication on
 the left side's type.  (From which it can be deduced that CInt**UInt