[R] how to use node info generated by rpart in mars?

2010-03-23 Thread vibha patel
I am working on rpart, mars and earth.
they all work fine individually.
but i want to use node information generated by rpart in earth or mars.
(mars is sensitive to outliers. CART deals effectively with outliers.)

is there any way to perform this?

Thanks.

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Re: [R] Error while trying to save summary() output as csv

2010-03-23 Thread Kamil Sijko
Thank you David, thank you Ista - as.matrix solves the problem.

Best regards,
Kamil Sijko
+48.790.818.212



2010/3/22 David Winsemius dwinsem...@comcast.net:

 On Mar 22, 2010, at 3:06 PM, Ista Zahn wrote:

 Hi Kamil,
 You can use something like
 write.csv(t(as.matrix(object)), file=name.csv)

 -Ista
 On Mon, Mar 22, 2010 at 2:54 PM, Kamil Sijko kamil.si...@swps.edu.pl
 wrote:

 Hi,

 I need to save output of summary() procedure to a csv file. It's all
 OK when it's applied to a 'factor' class variable, but when I try to
 save a 'integer' class summary to csv it gives me :

 summary(rnorm(100, 10)) - object
 write.csv2(object, file='name.csv')

 Error in do.call(expand.grid, c(dimnames(x), stringsAsFactors =
 stringsAsFactors)) :
  second argument must be a list

 It's the same when I use write.csv instead of write.csv2

 summary() produces a very simple table:

 structure(c(7.803, 9.633, 10.15, 10.17, 10.75, 12.41), .Names = c(Min.,
 1st Qu., Median, Mean, 3rd Qu., Max.), class = table)

 I have no idea, what to do... So Group, please help me: what does this
 error mean, and how to cope with it?

 Not sure why you got that error but if you convert that table into a matrix
 the writing proceeds as expected:

  write.csv(as.matrix(structure(c(7.803, 9.633, 10.15, 10.17, 10.75, 12.41),
 .Names = c(Min., 1st Qu., Median, Mean, 3rd Qu., Max.), class =
 table) ), file=test.csv)


 --
 David.

 Thanks for your help.
 Kamil

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 --
 Ista Zahn
 Graduate student
 University of Rochester
 Department of Clinical and Social Psychology
 http://yourpsyche.org

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[R] package precedence question

2010-03-23 Thread step...@mnemosyne.co.uk
Dear R help

I am writing a package where I am intending to extend the png function of the 
grDevices package. When I load my package, my png function indeed substitutes 
the grDevices function, and everything seems OK. I am a little confused though 
at how function precedence is determined. I am concerned that when the package 
moves into production on a webserver that instances may occur when the 
precedence breaks and the grDevices function becomes the version. I wish to 
avoid the need for the explicit calling of the myPackage:::png function, is 
there a way to encourage or coerce the precedence with which packages are 
loaded and in which functions are evaluated.

Some pointers as to where I might find the solution (or a more appropriate 
nomenclature) would be very gratefully received.

Thanks

Stephen
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[R] Problem installing package

2010-03-23 Thread Craig Woodward
Dear r-help users,

 

I have just downloaded the package vegan and I have problems accessing
the data to go through the examples in the tutorial. I can see the data
when I type data() but I am told that the data doesn't exist when I
type the name of one of the variables e.g.:

 varespec

Error: object 'varespec' not found

 

I suspect this could be a way I have my files organised or that I have
not set a working directory? I am new to R so I suspect I have probably
made a simple mistake. 

 

Thanks for your help,

 

Craig.

___






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[R] If else statements

2010-03-23 Thread tj

Hi everyone! 
May I request again for your help? 
I need to make some codes using if else statements...
Can I do an if-else statement inside an if-else statement? Is this the
correct form of writing it? 
Thank you.=)

Example:

for (v in 1:6) {
for (i in 2:200) {
if (v==1)
(if max(x*v-y*v)1 break())

if (v==2)
(if max(x*v-y*v)1.8 break())

if (v==3)
(if max(x*v-y*v)2 break())
}
}
-- 
View this message in context: 
http://n4.nabble.com/If-else-statements-tp1678705p1678705.html
Sent from the R help mailing list archive at Nabble.com.

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Re: [R] R script From PHP

2010-03-23 Thread sanchow

Hello,

I am having the same problem. My webmaster is not ready to install R on the
web server.

Is there a way to run R on a remote linux cluster and POST results from the
remote server to my website?

I am sorry if this is more of a PHP question.

Thank you and Any help appreciated.
S
-- 
View this message in context: 
http://n4.nabble.com/R-script-From-PHP-tp931996p1678627.html
Sent from the R help mailing list archive at Nabble.com.

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[R] how to use node info generated by rpart in mars?

2010-03-23 Thread vibha patel
I am working on rpart, mars and earth.
they all work fine individually.
but i want to use node information generated by rpart in earth or mars.
(mars is sensitive to outliers. CART deals effectively with outliers.)

is there any way to perform this?

Thanks.

[[alternative HTML version deleted]]

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[R] Linear Discriminant Analysis

2010-03-23 Thread L L

Hi,

I was wondering if you can show me how to plot the discriminant boundary lines 
for an LD analysis in R.  I am curious as to perform this on a larger scale, so 
I was wondering if you can provide me an example on the infamous 'iris' data.

Here's what I have so far:
iris.lda=lda(Species ~., data=iris)
iris.lda
plot(iris.lda)

col - rep(c(red, black, blue), each=50)
pch - rep(1:3, each=50)
plot(iris.lda, col=col, pch=pch)


% This will not  work to plot the coefficients.

abline(lda(Species~.,data=iris)$scaling, col=black)  

Thanks,

Lee
  
_


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[R] Author R books- Packt Publishing.

2010-03-23 Thread Kshipra Singh
Hi All, 

I am writing to you for Packt Publishing, the publishers of computer related 
books. 

We are planning to extend our catalogue of books based on Scientific Computing 
Tools and are currently inviting authors interested in writing for Packt. This 
doesn't need any previous writing experience. Just an expert knowledge of your 
subject and a passion to share it with others is all that we require. 

So, if you love R and are interested in authoring a book, here's an 
opportunity knocking your door. Write to us with your book ideas at 
aut...@packtpub.com. Even if you don't have a book idea and are simply 
interested in authoring a book, we are still keen to hear from you. 

More details about the opportunity are available at: 
http://authors.packtpub.com/content/scientific-compting-tools-write-Packt

Thanks
Kshipra Singh
Author Relationship Manager
Packt Publishing
www.PacktPub.com
 
Skype: kshiprasingh15
Twitter: http://twitter.com/kshipras
 
Interested in becoming an author? Visit http://authors.packtpub.com for all the 
information you need about writing for Packt.

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[R] printing text within if functions inside a for loop

2010-03-23 Thread Tian Pan
Hi

I am having a problem with outputting text inside an if function. I have the
following code:

for (j in 20:length(bb.up))
{
 if (up[j]==1  up[j-1]==0)
 {
  sprintf(Long on %s at a price of %f,dates[j],data[j])
 }
 if (down[j]==1  down[j-1]==0)
 {
  sprintf(Short on %s at a price of %f,dates[j],data[j])
 }
}

The loop runs fine and the sprintf function runs fine on its own, but the
problem I am having is that there is no output if I run the loop with the
sprintf inside it. Does anyone know what could be wrong? Is there a way for
the code to output data within this loop? I can't seem to find anything on
the internet for this problem.

Thanks in advance.
-- 
Tian Pan
Tel: +27 (0)21 670 5295

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Re: [R] printing text within if functions inside a for loop

2010-03-23 Thread Mario Valle
Use:
cat(sprintf(Long on %s at a price of %f\n,dates[j],data[j]))

Hope it helps
mario

Tian Pan wrote:
 Hi
 
 I am having a problem with outputting text inside an if function. I have the
 following code:
 
 for (j in 20:length(bb.up))
 {
  if (up[j]==1  up[j-1]==0)
  {
   sprintf(Long on %s at a price of %f,dates[j],data[j])
  }
  if (down[j]==1  down[j-1]==0)
  {
   sprintf(Short on %s at a price of %f,dates[j],data[j])
  }
 }
 
 The loop runs fine and the sprintf function runs fine on its own, but the
 problem I am having is that there is no output if I run the loop with the
 sprintf inside it. Does anyone know what could be wrong? Is there a way for
 the code to output data within this loop? I can't seem to find anything on
 the internet for this problem.
 
 Thanks in advance.

-- 
Ing. Mario Valle
Data Analysis and Visualization Group| http://www.cscs.ch/~mvalle
Swiss National Supercomputing Centre (CSCS)  | Tel:  +41 (91) 610.82.60
v. Cantonale Galleria 2, 6928 Manno, Switzerland | Fax:  +41 (91) 610.82.82

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Re: [R] maxNR - Error in p(a, b) : element 1 is empty; the part of the args list of '*' being evaluated was: (b, t)

2010-03-23 Thread Arne Henningsen
On 22 March 2010 16:31, 4-real danielkjae...@gmail.com wrote:

 Hello everyone...
 We were trying to implement the Newton-Raphson method in R, and estimate the
 parameters a and b, of a function, F, however we can't seem to implement
 this the right way. Hope you can show me the right way to do this. I think
 what we want R to do is to read the data from the website and then peform
 maxNR on the function, F. Btw the version of R being used is RGui for
 Windows if it helps to know this.

 R-code below:

  library(maxLik)
 require(maxLik)

 x -
 read.table('http://www.math.ku.dk/kurser/2008-09/blok4/stat2/doku/data/Eksempel_6_3.txt',
 header = TRUE);
 t - log(x$Koncentration);
 X - x$Status;

 p - function(a,b) exp(a+b*t)/(1+exp(a+b*t));
 S - sum(X);
 SP - sum(t*X);

 F - function(a,b) {
 +     c(sum(p(a,b)) - S,
 +       sum(t*p(a,b)) - SP)
 + }


 z - maxNR(F, start=1, print.level=2)
 Error in p(a, b) : element 1 is empty;
   the part of the args list of '*' being evaluated was:
   (b, t)

You forgot to provide argument b for function F:

R z - maxNR(F, start=1, b=1, print.level=2)
- Initial parameters: -
fcn value: -15.42843
parameter initial gradient free
[1,] 1-22.490161
Condition number of the (active) hessian: 1
-Iteration 1 -
-Iteration 2 -
-Iteration 3 -
-Iteration 4 -
-Iteration 5 -
-Iteration 6 -
--
gradient close to zero. May be a solution
6  iterations
estimate: -0.6288598
Function value: -1.536789


/Arne


-- 
Arne Henningsen
http://www.arne-henningsen.name

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Re: [R] R script From PHP

2010-03-23 Thread Romain Francois


Hello,

You might like the php client to Rserve that is part of the next version 
of Rserve. see http://www.rforge.net/Rserve/svn.html


install the last snapshot, and check the client/php/simple.php file

If you decide to go this way, then I'd suggest you use the 
stats-rosuda-devel mailing list for further questions.


Romain

Le 23/03/10 04:27, sanchow a écrit :

Hello,

I am having the same problem. My webmaster is not ready to install R on the
web server.

Is there a way to run R on a remote linux cluster and POST results from the
remote server to my website?

I am sorry if this is more of a PHP question.

Thank you and Any help appreciated.
S



--
Romain Francois
Professional R Enthusiast
+33(0) 6 28 91 30 30
http://romainfrancois.blog.free.fr
|- http://tr.im/OIXN : raster images and RImageJ
|- http://tr.im/OcQe : Rcpp 0.7.7
`- http://tr.im/O1wO : highlight 0.1-5

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[R] Log linear model - Showing non-deviation form in glm()

2010-03-23 Thread Christoffer Karlsson
Hey,

Whenever I set up a log linear model using glm(Y~. , data=data,
family=poisson) I get the parameters in the form of deviation from the first
cell kombination.

I find this to be hard to interpret when I for instance want to know if
there is a difference between two factors in the first category since those
parameters are not shown directly.
Is there any way to get the summary() command, or equivalent, to show me all
of the parameters in the model in non-deviation form?

I can use loglin() to get the parameters, but it doesnt show significance of
the parameters from what I can tell.

Alternatively, can anyone give a brief explanation of how to interpret the
model in deviation form? For example here I have the factors Gamla and
Nya and the categories 0, 1-10, 11-50, 51-100 and 101+
The interpretation of the shown interaction terms are no problem, but how do
I figure if there is a difference between Gamla and Nya when it comes to
category 0?

(Intercept)7.747600.02078 372.852   2e-16 ***
typNya-2.349430.07040 -33.371   2e-16 ***
kategori1-10  -1.889660.05735 -32.950   2e-16 ***
kategori101+  -4.058720.15947 -25.451   2e-16 ***
kategori11-50 -2.635610.08035 -32.802   2e-16 ***
kategori51-100-4.612100.20955 -22.010   2e-16 ***
typNya:kategori1-100.725610.14935   4.858 1.18e-06 ***
typNya:kategori101+   -1.339451.01486  -1.3200.187
typNya:kategori11-50   0.181890.25221   0.7210.471
typNya:kategori51-100 -0.092910.74056  -0.1250.900


Thanks for any help, and sorry for the supposedly basic question!
Chris

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[R] S4: Multiple inheritance

2010-03-23 Thread Christophe Genolini

Hi all,

Working with S4 object, I definine two class foo1 and foo2. I define '[' 
(resp. '[-') for the two classes.

Then I define a third class foo3 that inherit from both foo1 and foo2.
Is there a way to make '[' (resp. '[-') for foo3 inherit from '[' 
(resp. '[-')  for foo1 and foo2?


Thanks
Christophe

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[R] Changing content of column in data.frame + efficient join extraction between 2 data.frames

2010-03-23 Thread Corrado

Dear R users,

I have 2 SpatialPointsDataFrame's, pcs and East.

The column str_1 in the first (pcs) is:

 pcs[0:4,]
  coordinates cat   str_1  int_1  int_2dbl_1 dbl_2
1 (101000, 263000)   1 SM06B 101000 263000 4.978915 -4.293668
2 (101000, 265000)   2 SM06C 101000 265000 4.960478 -4.266742
3 (101000, 267000)   3 SM06D 101000 267000 4.912984 -4.246849
4 (101000, 269000)   4 SM06E 101000 269000 4.613309 -4.185405


The column str_1 in the second (East) is:

 East[0:4,]
  coordinates str_1
1 (489000, 215000) sp81x
2 (489000, 217000) sp81y
3 (493000, 209000) sp90j
4 (495000, 209000) sp90p


I would like to do 2 things:

1) I would like to change the format of the column str_1
in the first to be the same that it is in the second,
that is I need to remove the inverted commas  and I need to
make it lower case.

2) I would like to extract the rows from the first one (pcs) where 
pcs$str_1

is the same as East$str_1.

I have even tried regexp, but cannot modify
the content of pcs$str_1 to remove
the inveretd commas  and change the case to lowercase.

How do I do that?

Regards
--

Corrado Topi
PhD Researcher
Global Climate Change and Biodiversity
Area 18,Department of Biology
University of York, York, YO10 5YW, UK
Phone: + 44 (0) 1904 328645, E-mail: ct...@york.ac.uk

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Re: [R] S4: Multiple inheritance

2010-03-23 Thread Corrado

Dear Christophe,

Could you please post some example code of what you are trying to achieve?

Christophe Genolini wrote:

Hi all,

Working with S4 object, I definine two class foo1 and foo2. I define 
'[' (resp. '[-') for the two classes.

Then I define a third class foo3 that inherit from both foo1 and foo2.
Is there a way to make '[' (resp. '[-') for foo3 inherit from '[' 
(resp. '[-')  for foo1 and foo2?


Thanks
Christophe

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http://www.R-project.org/posting-guide.html

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--
Corrado Topi
PhD Researcher
Global Climate Change and Biodiversity
Area 18,Department of Biology
University of York, York, YO10 5YW, UK
Phone: + 44 (0) 1904 328645, E-mail: ct...@york.ac.uk

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[R] help with survival package

2010-03-23 Thread Shankavaram, Uma (NIH/NCI) [E]

I am trying use survfit function in survival package, but getting an error that
Error in survfit:  could not find function survfit.km

This package was working fine previously. I am using  R version 2.9.2 on 
Windows.

Can anyone tell me if this is a bug in the function code or something is 
missing in the newer version of R.

I appreciate any help regarding this.

Thanks

Uma

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Re: [R] Changing content of column in data.frame + efficient join extraction between 2 data.frames

2010-03-23 Thread Bernardo Rangel Tura
On Tue, 2010-03-23 at 09:37 +, Corrado wrote:
 Dear R users,
 
 I have 2 SpatialPointsDataFrame's, pcs and East.
 
 The column str_1 in the first (pcs) is:
 
   pcs[0:4,]
coordinates cat   str_1  int_1  int_2dbl_1 dbl_2
 1 (101000, 263000)   1 SM06B 101000 263000 4.978915 -4.293668
 2 (101000, 265000)   2 SM06C 101000 265000 4.960478 -4.266742
 3 (101000, 267000)   3 SM06D 101000 267000 4.912984 -4.246849
 4 (101000, 269000)   4 SM06E 101000 269000 4.613309 -4.185405
  
 
 The column str_1 in the second (East) is:
 
   East[0:4,]
coordinates str_1
 1 (489000, 215000) sp81x
 2 (489000, 217000) sp81y
 3 (493000, 209000) sp90j
 4 (495000, 209000) sp90p
  
 
 I would like to do 2 things:
 
 1) I would like to change the format of the column str_1
 in the first to be the same that it is in the second,
 that is I need to remove the inverted commas  and I need to
 make it lower case.
 
 2) I would like to extract the rows from the first one (pcs) where 
 pcs$str_1
 is the same as East$str_1.
 
 I have even tried regexp, but cannot modify
 the content of pcs$str_1 to remove
 the inveretd commas  and change the case to lowercase.
 
 How do I do that?
 
 Regards


Hi Corrado!

First: tolower(pcs$str_1) change to lower case
Second: try merge (East,pcs,by.x=str_1,by.y=str_1) to fusion data frames
Third: I don't recreate your database East in my computer do you give a
small part to I try solve your problem?

-- 
Bernardo Rangel Tura, M.D,MPH,Ph.D
National Institute of Cardiology
Brazil

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[R] Extracting all members with a specific similarity value from a large similarity matrix

2010-03-23 Thread Buergmann, Helmut
I have a large dataframe (1400x1400) containing a symmetric similarity matrix. 
Now I would like to extract subsets of elements where all elements have a 
specific similarity with all other elements of this subset. 
For example if the data looks like this

Spl1Spl2Spl3Spl4Spl5[...]
Spl11   0.125   0.000   0.000   0.125
Spl20.125   1   0.000   0.000   0.125
Spl30.000   0.000   1   0.000   0.500
Spl40.000   0.000   0.000   1   0.750
Spl50.125   0.125   0.500   0-750   1
[...]

I am looking for a way to either like to extract, all elements that are 
mutually 0, e.g:
Spl1Spl3Spl4[...]
Spl11   0.000   0.000
Spl30.000   1   0.000
Spl40.000   0.000   1
[...]

Or that mutually have similarity 0.125:

Spl1Spl2Spl5[...]
Spl11   0.125   0.125
Spl20.125   1   0.125
Spl50.125   0.125   1
[...]

Or alternatively to sort the table so that this info can easily be obtained by 
looking for blocks around the diagonal, like this:
Spl3Spl4Spl1Spl2Spl5[...]
Spl31   0.000   0.000   0.125   0.500
Spl40.000   1   0.000   0.000   0.750
Spl10.000   0.000   1   0.125   0.125
Spl20.000   0.000   0.125   1   0.125
Spl50.500   0.750   0.125   0.125   1
[...]

Any help is much appreciated!

Helmut Bürgmann, Switzerland

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[R] help

2010-03-23 Thread fredrick devadoss
Hello All,

I am new to R and tried to install R in Linux system (OS: Open SUSE).
After untar the source code, changed the directory, and typed the
command ./configure, it was checking a list...finally it gave an error
message. Here with i have enclosed the error message.

Check-list goes like this:

checking if g++ supports -c -o file.o... yes
checking if g++ supports -c -o file.o... (cached) yes
checking whether the g++ linker (/usr/i586-suse-linux/bin/ld) supports shared 
libraries... yes
checking dynamic linker characteristics... GNU/Linux ld.so
checking how to hardcode library paths into programs... immediate
checking if libtool supports shared libraries... yes
checking whether to build shared libraries... yes
checking whether to build static libraries... no
checking for gfortran option to produce PIC... -fPIC
checking if gfortran PIC flag -fPIC works... yes
checking if gfortran static flag -static works... yes
checking if gfortran supports -c -o file.o... yes
checking if gfortran supports -c -o file.o... (cached) yes
checking whether the gfortran linker (/usr/i586-suse-linux/bin/ld) supports 
shared libraries... yes
checking dynamic linker characteristics... GNU/Linux ld.so
checking how to hardcode library paths into programs... immediate
checking for cos in -lm... yes
checking for sin in -lm... yes
checking for dlopen in -ldl... yes
checking readline/history.h usability... no
checking readline/history.h presence... no
checking for readline/history.h... no
checking readline/readline.h usability... no
checking readline/readline.h presence... no
checking for readline/readline.h... no
checking for rl_callback_read_char in -lreadline... no
checking for main in -lncurses... yes
checking for rl_callback_read_char in -lreadline... no
checking for history_truncate_file... no
configure: error: --with-readline=yes (default) and headers/libs are not 
available

Can anyone help me in this regard?

Expecting your reply and thanks in advance.

Warm regards
Fredrick.

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] help

2010-03-23 Thread Ista Zahn
Hi Fredrick,
Is there a reason you need to compile the source code? If not, I
recommend following the instillation instructions on CRAN. OpenSuse
instructions are at http://cran.r-project.org/bin/linux/suse/

Best,
Ista

On Tue, Mar 23, 2010 at 7:43 AM, fredrick devadoss
fredrick_i...@yahoo.com wrote:
 Hello All,

 I am new to R and tried to install R in Linux system (OS: Open SUSE).
 After untar the source code, changed the directory, and typed the
 command ./configure, it was checking a list...finally it gave an error
 message. Here with i have enclosed the error message.

 Check-list goes like this:

 checking if g++ supports -c -o file.o... yes
 checking if g++ supports -c -o file.o... (cached) yes
 checking whether the g++ linker (/usr/i586-suse-linux/bin/ld) supports shared 
 libraries... yes
 checking dynamic linker characteristics... GNU/Linux ld.so
 checking how to hardcode library paths into programs... immediate
 checking if libtool supports shared libraries... yes
 checking whether to build shared libraries... yes
 checking whether to build static libraries... no
 checking for gfortran option to produce PIC... -fPIC
 checking if gfortran PIC flag -fPIC works... yes
 checking if gfortran static flag -static works... yes
 checking if gfortran supports -c -o file.o... yes
 checking if gfortran supports -c -o file.o... (cached) yes
 checking whether the gfortran linker (/usr/i586-suse-linux/bin/ld) supports 
 shared libraries... yes
 checking dynamic linker characteristics... GNU/Linux ld.so
 checking how to hardcode library paths into programs... immediate
 checking for cos in -lm... yes
 checking for sin in -lm... yes
 checking for dlopen in -ldl... yes
 checking readline/history.h usability... no
 checking readline/history.h presence... no
 checking for readline/history.h... no
 checking readline/readline.h usability... no
 checking readline/readline.h presence... no
 checking for readline/readline.h... no
 checking for rl_callback_read_char in -lreadline... no
 checking for main in -lncurses... yes
 checking for rl_callback_read_char in -lreadline... no
 checking for history_truncate_file... no
 configure: error: --with-readline=yes (default) and headers/libs are not 
 available

 Can anyone help me in this regard?

 Expecting your reply and thanks in advance.

 Warm regards
 Fredrick.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Mosaic plots

2010-03-23 Thread Jay Emerson
As pointed out by others, vcd supports mosaic plots on top of the grid
engine (which is extremely helpful for those of us who love playing around
with grid).  The standard mosaicplot() function is directly available (it
isn't clear if you knew this).  The proper display of names is a real
challenge faced by all of us with these plots, so  you should try each
version.  I'm not sure what you intend to do with a legend, but if you want
the ability to customize and hack code, I suggest you look at grid and a
modification to vcd's version to suit your purposes.

Jay





 Subject: [R] Mosaic Plots
 Message-ID: 1269256874432-1677468.p...@n4.nabble.com
 Content-Type: text/plain; charset=us-ascii


 Hello Everyone

 I want to plot Moasic Plots, I have tried them using iplots package (using
 imosaic). The problem is the names dont get alligned properly, is there a
 way to a align the names and provide legend in Mosaic plots using R?

 Also I would like to know any other packages using which I can plot Mosaic
 Plots


 Thank you in advance
 Sunita
 --


 --
 John W. Emerson (Jay)
 Associate Professor of Statistics
 Department of Statistics
 Yale University
 http://www.stat.yale.edu/~jay http://www.stat.yale.edu/%7Ejay




-- 
John W. Emerson (Jay)
Associate Professor of Statistics
Department of Statistics
Yale University
http://www.stat.yale.edu/~jay

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and provide commented, minimal, self-contained, reproducible code.


[R] rdcomclient issue - member not found when using borders

2010-03-23 Thread Jason Baucom
I wrote a procedure to create a spreadsheet using rdcomclient. It uses a
function to do the writing and runs correctly in isolation. It gives
errors, but it continues to completion. The error I receive is Error:
Member not found. If I place it inside a for loop the loop fails after
the first iteration, once it reaches the error.

 

Has anyone had experience with this error? Here is the code that is
causing the problem.

 

 

library(RDCOMClient)

source(http://www.omegahat.org/RDCOMClient/examples/excelUtils3.R;)

xls - COMCreate(Excel.Application)

xls[[Visible]] - TRUE

wb = xls[[Workbooks]]$Add(1)

 

sh = wb[[Worksheets]]$Add()

sh[[Name]] - as.character(tabName)

 

 

 

AnalyzeExport - function(sh,Data,Cell,Title1,Title2) {

 
letters-c(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,
P,Q,R,S,T,U,V,W,X,Y,Z)

print(Cell)

exportDataFrame(Data, at = sh$Range(Cell))

 

B3R-sh$Range(Cell)

B3R[[Formula]] - Title1

#B3R[[HorizontalAlignment]]-xlRight

 

 
B3R-sh$Range(paste(letters[grep(substring(Cell,1,1),letters)+1],substri
ng(Cell,2),sep=))

B3R[[Formula]] - Title2

#B3R[[HorizontalAlignment]]-xlLeft

 

B3R-sh$Range(paste(substring(Cell,1,1),
as.integer(substring(Cell,2))+1+nrow(Data),sep=))

B3R[[Formula]] - Total

 

B3R-sh$Range(paste(letters[grep(substring(Cell,1,1),letters)+1],
as.integer(substring(Cell,2))+1+nrow(Data),sep=))

Cell1-paste(letters[grep(substring(Cell,1,1),letters)],
as.integer(substring(Cell,2))+1,sep=)

Cell2-paste(letters[grep(substring(Cell,1,1),letters)+1],
as.integer(substring(Cell,2))+nrow(Data),sep=)

MyCell=paste(Cell1,:,Cell2,sep=)

B3R[[Formula]] - paste(=sum(,MyCell,),sep=)

 

print(MyCell)

 

B3RB - sh$Range(MyCell)

B3RB[[Borders]][[LineStyle]]-as.integer(1)

#B3RB[[ColumnWidth]]-20

}

  

 

AnalyzeExport(sh,ExcelCopy,B2,NDC,Unique Pats)

 

The line that is causing the problem is :

B3RB[[Borders]][[LineStyle]]-as.integer(1)

 

On another note, I'd also love to learn how to change columnWidth and
HorizontalAligment properly (the code commented out).

 

Jason Baucom

Ateb, Inc. 

2600 Sumner Blvd. Suite 158

Raleigh, NC 27616

www.ateb.com http://www.ateb.com/ 


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and provide commented, minimal, self-contained, reproducible code.


Re: [R] If else statements

2010-03-23 Thread Matthew Dowle
Here are some references. Please read these first and post again if you are 
still stuck after reading them. If you do post again, we will need x and y.

1. Introduction to R : 9.2.1 Conditional execution: if statements.
2. R Language Definition : 3.2 Control structures.
3. R for beginners by E Paradis : 6.1 Loops and vectorization
4. Eric Raymond's essay How to Ask Questions The Smart Way 
http://www.catb.org/~esr/faqs/smart-questions.html.

HTH
Matthew


tj girlm...@yahoo.com wrote in message 
news:1269325933723-1678705.p...@n4.nabble.com...

 Hi everyone!
 May I request again for your help?
 I need to make some codes using if else statements...
 Can I do an if-else statement inside an if-else statement? Is this the
 correct form of writing it?
 Thank you.=)

 Example:

 for (v in 1:6) {
 for (i in 2:200) {
 if (v==1)
 (if max(x*v-y*v)1 break())

 if (v==2)
 (if max(x*v-y*v)1.8 break())

 if (v==3)
 (if max(x*v-y*v)2 break())
 }
 }
 -- 
 View this message in context: 
 http://n4.nabble.com/If-else-statements-tp1678705p1678705.html
 Sent from the R help mailing list archive at Nabble.com.


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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Problem installing package

2010-03-23 Thread David Winsemius
The inner components of object are not accessible by name. You need  
to use the proper functions to retrieve or modify them. You are asked  
by the PostingGuide to show your code and be more specific about  
problems. Until you do so, that is about all anyone will be able to  
say about your mistakes.


--
David.
On Mar 23, 2010, at 4:17 AM, Craig Woodward wrote:


Dear r-help users,



I have just downloaded the package vegan and I have problems accessing
the data to go through the examples in the tutorial. I can see the  
data

when I type data() but I am told that the data doesn't exist when I
type the name of one of the variables e.g.:


varespec


Error: object 'varespec' not found



I suspect this could be a way I have my files organised or that I have
not set a working directory? I am new to R so I suspect I have  
probably

made a simple mistake.


--
David Winsemius, MD
West Hartford, CT

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[R] caret package, how can I deal with RFE+SVM wrong message?

2010-03-23 Thread bbslover

Hello, 
   
I am learning caret package, and I want to use the RFE to reduce the
feature. I want to use RFE coupled Random Forest (RFE+FR) to complete this
task. As we know, there are a number of pre-defined sets of functions, like
random Forest(rfFuncs), however,I want to tune the parameters (mtr) when
RFE, and then I write code below, but there is something wrong message, How
can I deal with it?  
 rfGrid-expand.grid(.mtry=c(1:2))
 rfectrl-rfeControl(functions=caretFuncs,method=cv,verbose=F,returnResamp=final,number=10)
 subsets-c(3,4)
 set.seed(2)
 rf.RFE-rfe(trx,try,sizes=subsets,rfeControl=rfectrl,method=rf,tuneGrid=rfGrid)
Loading required package: class

Attaching package: 'class'


The following object(s) are masked from package:reshape :

 condense 

Fitting: mtry=1 
Fitting: mtry=2 
Error in varImp.randomForest(object$finalModel, ...) : 
  subscript out of bounds
In addition: Warning message:
package 'e1071' was built under R version 2.10.1 


At the same time, If I want to  use RFE+SVM,  RFE+nnet, and so on ,how can I
do? I have try RFE+SVM, also wrong message: set.seed(1)
 svmProfile-rfe(trx,try,sizes=c(1:3),
+ rfeControl=rfeControl(functions=caretFuncs,method=cv,
+ verbose=F,returnResamp=final,number=10),
+ method=svmRadial,tuneLength=5)
Fitting: sigma=0.009246713, C=0.1 
Fitting: sigma=0.009246713, C=1 
Fitting: sigma=0.009246713, C=10 
Fitting: sigma=0.009246713, C=100 
Fitting: sigma=0.009246713, C=1000 
Error in rfeControl$functions$rank(fitObject, .x, y) : 
  need importance columns for each class

thank you!
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[R] Transform data set

2010-03-23 Thread Thomas Jensen
Dear R Experts,

I am having some trouble creating a variable in R. I have data on
self-placement of voters, their placement of parties, and which party
they feel closest to. The data is structured like this:

 Party_Closelrplaceself lrplaceParty1   lrplaceParty2 ...   
   party1   2   4   5 
   party2   5   6   4
   party1   6   2   1

etc...

I want to format the data set so it looks like this:

Party_Close lrplacepartyclose   lrplaceself
  party14   2
  party24   5
  party12   6

Any help is greatly appreciated!

With kind regards,
Thomas

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and provide commented, minimal, self-contained, reproducible code.


[R] information module Wilks' lambda criterion

2010-03-23 Thread Catherine ENG
Hi everybody,

I was wondering if you can help me about a module. In fact, I'm looking for
a package or module about Wilks' lambda criterion in R environment. I didn't
find it in R website (
http://cran.cict.fr/web/packages/index.html#available-packages-W or
http://search.cpan.org/faq.html).
If this module exists, could you show me the command line.

Thank you very much for your help,
Miss Catherine ENG


-
Laboratoire de Génétique et Microbiologie UMR INRA 1128 - IFR 110
Université Henri Poincaré - Faculté des Sciences BP 239
54506 Vandoeuvre-lès-Nancy
Tél. : 06.58.25.37.66

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] estimation of parameters with grofit

2010-03-23 Thread alexander russell
Hello again about grofit:
I've been looking at the grofit explanatory pdf, but it seems to me that
it's missing a little bit of commentary as to the multiplicity of
'experiments'. For example, what is the minimum number of data points(not
time points) to obtain a model? Would it be similar to the approximately 12
that we read will give us a basic regression?
regards,
shfets

On Mon, Mar 22, 2010 at 2:43 PM, alexander russell ssv...@gmail.com wrote:

 Hello,
 I'm trying to understand grofit's estimation of models, and fairly new to
 growth models generally. The data used by grofit consists of the vector of
 experiments, that is the growth values for a vector of individuals
 measured at different times. Can I understand correctly that the program
 estimates parameters for the growth model based on a regression(linear or
 non linear) analysis of the data at time 1 to time 2, then time 2 to time 3,
 building a curve piecewise?
 regards,
 shfets


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Re: [R] Embed R code in C++

2010-03-23 Thread mans

No, I didnt install Rcpp but i have R 2.10.1 already installed.
What's the difference with Rinside and Rcpp?

Do i need both to embed R code in C++ file or just one of them ?

Could you tell me where can i get Rcpp pkg?
How can i Install it because i dont know how to compile a source file on the
terminal.

Thanks very much for your help.

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and provide commented, minimal, self-contained, reproducible code.


[R] R-installation regarding.

2010-03-23 Thread fredrick devadoss
Hello All,

I am new to R and tried to install R in Linux system (OS: Open SUSE). After 
untar the source code, changed the directory, and typed the command 
./configure, it was checking a list...finally it gave an error message. Here 
with i have enclosed the error message.

Check-list goes like this:

checking if g++ supports -c -o file.o... yes
checking if g++ supports -c -o file.o... (cached) yes
checking whether the g++ linker (/usr/i586-suse-linux/bin/ld) supports shared 
libraries... yes
checking dynamic linker characteristics... GNU/Linux ld.so
checking how to hardcode library paths into programs... immediate
checking if libtool supports shared libraries... yes
checking whether to build shared libraries... yes
checking whether to build static libraries... no
checking for gfortran option to produce PIC... -fPIC
checking if gfortran PIC flag -fPIC works... yes
checking if gfortran static flag -static works... yes
checking if gfortran supports -c -o file.o... yes
checking if gfortran supports -c -o file.o... (cached) yes
checking whether the gfortran linker (/usr/i586-suse-linux/bin/ld) supports 
shared libraries... yes
checking dynamic linker characteristics... GNU/Linux ld.so
checking how to hardcode library paths into programs... immediate
checking for cos in -lm... yes
checking for sin in -lm... yes
checking for dlopen in -ldl... yes
checking readline/history.h usability... no
checking readline/history.h presence... no
checking for readline/history.h... no
checking readline/readline.h usability... no
checking readline/readline.h presence... no
checking for readline/readline.h... no
checking for rl_callback_read_char in -lreadline... no
checking for main in -lncurses... yes
checking for rl_callback_read_char in -lreadline... no
checking for history_truncate_file... no
configure: error: --with-readline=yes (default) and headers/libs are not 
available

Can anyone help me in this regard?

Expecting your reply and thanks in advance.

Warm regards
Fredrick.

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Re: [R] Calling R functions into C# or C++

2010-03-23 Thread ManInMoon

Fayssal,

This zip file appears to be corrupted - do you have another version?
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Transform data set

2010-03-23 Thread stephen sefick
I am not entirely sure what you are trying to do.  Are you wanting to
re-arrange the columns or apply some sort of transformation?

On Tue, Mar 23, 2010 at 4:47 AM, Thomas Jensen
thomas.jen...@eup.gess.ethz.ch wrote:
 Dear R Experts,

 I am having some trouble creating a variable in R. I have data on
 self-placement of voters, their placement of parties, and which party
 they feel closest to. The data is structured like this:

  Party_Close    lrplaceself     lrplaceParty1   lrplaceParty2 ...
   party1               2               4               5
   party2               5               6               4
   party1               6               2               1

 etc...

 I want to format the data set so it looks like this:

 Party_Close     lrplacepartyclose           lrplaceself
  party1                4                       2
  party2                4                       5
  party1                2                       6

 Any help is greatly appreciated!

 With kind regards,
 Thomas

 __
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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-- 
Stephen Sefick

Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like gods.  We are mammals, and have not exhausted the
annoying little problems of being mammals.

-K. Mullis

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Re: [R] help with survival package

2010-03-23 Thread Shankavaram, Uma (NIH/NCI) [E]
I am trying use survfit function in survival package, but getting an error that
Error in survfit:  could not find function survfit.km

This package was working fine previously. I am using  R version 2.9.2 on 
Windows.

Can anyone tell me if this is a bug in the function code or something is 
missing in the newer version of R.

I appreciate any help regarding this.

Thanks

Uma

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Re: [R] Transform data set

2010-03-23 Thread Wincent
Looks like this way,

dat$lrplacepartyclose - NA

dat$lrplacepartyclose[dat$Party_Close==party1] -
dat$lrplaceParty1[dat$Party_Close==party1]

dat$lrplacepartyclose[dat$Party_Close==party2] -
dat$lrplaceParty2[dat$Party_Close==party2]

and goes on and on.


On 23 March 2010 17:47, Thomas Jensen thomas.jen...@eup.gess.ethz.ch wrote:
 Dear R Experts,

 I am having some trouble creating a variable in R. I have data on
 self-placement of voters, their placement of parties, and which party
 they feel closest to. The data is structured like this:

  Party_Close    lrplaceself     lrplaceParty1   lrplaceParty2 ...
   party1               2               4               5
   party2               5               6               4
   party1               6               2               1

 etc...

 I want to format the data set so it looks like this:

 Party_Close     lrplacepartyclose           lrplaceself
  party1                4                       2
  party2                4                       5
  party1                2                       6

 Any help is greatly appreciated!

 With kind regards,
 Thomas

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Re: [R] help with survival package

2010-03-23 Thread David Winsemius


On Mar 23, 2010, at 6:13 AM, Shankavaram, Uma (NIH/NCI) [E] wrote:



I am trying use survfit function in survival package, but getting an  
error that

Error in survfit:  could not find function survfit.km

This package was working fine previously. I am using  R version  
2.9.2 on Windows.


If you are using the current version of package survival with the  
prior version of R it should not be a surprise if there are  
incompatibilities.




Can anyone tell me if this is a bug in the function code or  
something is missing in the newer version of R.


No code,  no comment.



I appreciate any help regarding this.

Thanks


See that message at the bottom of every posting? Please read for  
meaning.

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Re: [R] R-installation regarding.

2010-03-23 Thread Paul Hiemstra

Hi Frederick,

The development files for readline are not available. Install them to 
get this working. For debian/ubuntu the package to install is called 
libreadline-dev or something. SUSE's package manager might have a 
similar package. Alternatively you can skip installing R from source and 
use binary packages that are available in .dev, .rpm etc from CRAN [1]. 
This ensures you have the latest version of R and that upgrading is done 
through the package manager of SUSE, minimizing your work.


cheers,
Paul

[1] http://cran.r-project.org/bin/linux/suse/

fredrick devadoss wrote:

Hello All,

I am new to R and tried to install R in Linux system (OS: Open SUSE). After 
untar the source code, changed the directory, and typed the command 
./configure, it was checking a list...finally it gave an error message. Here 
with i have enclosed the error message.

Check-list goes like this:

checking if g++ supports -c -o file.o... yes
checking if g++ supports -c -o file.o... (cached) yes
checking whether the g++ linker (/usr/i586-suse-linux/bin/ld) supports shared 
libraries... yes
checking dynamic linker characteristics... GNU/Linux ld.so
checking how to hardcode library paths into programs... immediate
checking if libtool supports shared libraries... yes
checking whether to build shared libraries... yes
checking whether to build static libraries... no
checking for gfortran option to produce PIC... -fPIC
checking if gfortran PIC flag -fPIC works... yes
checking if gfortran static flag -static works... yes
checking if gfortran supports -c -o file.o... yes
checking if gfortran supports -c -o file.o... (cached) yes
checking whether the gfortran linker (/usr/i586-suse-linux/bin/ld) supports 
shared libraries... yes
checking dynamic linker characteristics... GNU/Linux ld.so
checking how to hardcode library paths into programs... immediate
checking for cos in -lm... yes
checking for sin in -lm... yes
checking for dlopen in -ldl... yes
checking readline/history.h usability... no
checking readline/history.h presence... no
checking for readline/history.h... no
checking readline/readline.h usability... no
checking readline/readline.h presence... no
checking for readline/readline.h... no
checking for rl_callback_read_char in -lreadline... no
checking for main in -lncurses... yes
checking for rl_callback_read_char in -lreadline... no
checking for history_truncate_file... no
configure: error: --with-readline=yes (default) and headers/libs are not 
available

Can anyone help me in this regard?

Expecting your reply and thanks in advance.

Warm regards
Fredrick.

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Re: [R] Embed R code in C++

2010-03-23 Thread Romain Francois

Le 23/03/10 13:34, mans a écrit :

No, I didnt install Rcpp but i have R 2.10.1 already installed.


If you want to use RInside, you need Rcpp. This is what dependencies are 
for. you can install Rcpp from R :


install.packages( Rcpp )


What's the difference with Rinside and Rcpp?


Rcpp defines a set of classes to ease writing C++ code in R packages. 
you can think it as c++ inside R.


RInside facilitates embedding R in a c++ application, you can think it 
as R inside c++.



Do i need both to embed R code in C++ file or just one of them ?


You don't __need__ any of them, but thy will make the process easier.


Could you tell me where can i get Rcpp pkg?


cran, but google knows and would have given you the answer more quickly.


How can i Install it because i dont know how to compile a source file on the
terminal.
Thanks very much for your help.



--
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Professional R Enthusiast
+33(0) 6 28 91 30 30
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Re: [R] If else statements

2010-03-23 Thread tj

Thanks Matthew... I will read your suggested articles/files.
I hope, i will be able to figure out what should be done with this. 
=)

~tj

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Re: [R] If else statements

2010-03-23 Thread R Help
The short answer is yes, you can, but your syntax is wrong.  You need
to make sure you wrap your conditions inside brackets, and use {, not
(, to delineate your if statements.

 for (v in 1:6) {
 for (i in 2:200) {
 if (v==1){
   if (max(x*v-y*v)1)
 break()
  }
  }
  }
 et cetera

On Tue, Mar 23, 2010 at 3:32 AM, tj girlm...@yahoo.com wrote:

 Hi everyone!
 May I request again for your help?
 I need to make some codes using if else statements...
 Can I do an if-else statement inside an if-else statement? Is this the
 correct form of writing it?
 Thank you.=)

 Example:

 for (v in 1:6) {
 for (i in 2:200) {
 if (v==1)
 (if max(x*v-y*v)1 break())

 if (v==2)
 (if max(x*v-y*v)1.8 break())

 if (v==3)
 (if max(x*v-y*v)2 break())
 }
 }
 --
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 http://n4.nabble.com/If-else-statements-tp1678705p1678705.html
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[R] Converting date format

2010-03-23 Thread Hosack, Michael
R community:

Hello, I would to like to convert a character date variable from %m/%d/%Y to 
%m/%d/%y. Any advice would be greatly appreciated. I have tried functions for 
changing the formatting and removing the unnecessary digits without success.

Mike

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[R] no predict function in lme4 ?

2010-03-23 Thread Markus Loecher
Dear mixed effects modelers,
I seem unable to find a predict method for mer objects in the package lme4.
Am I not seeing the forest for the trees ?

Any pointer would be very helpful.
Thanks,
Markus

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Re: [R] Converting date format

2010-03-23 Thread Nutter, Benjamin
If x is your vector of character date variables:

orig.date - as.Date(x, format=c(%m/%d/%Y))
new.date - format(x, format=c(%m/%d/%y))

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Hosack, Michael
Sent: Tuesday, March 23, 2010 10:11 AM
To: R-help@r-project.org
Subject: [R] Converting date format

R community:

Hello, I would to like to convert a character date variable from
%m/%d/%Y to %m/%d/%y. Any advice would be greatly appreciated. I have
tried functions for changing the formatting and removing the unnecessary
digits without success.

Mike

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[R] Solutions for memory problems (packages ff, bigmemory)?

2010-03-23 Thread hhafner
Hello,

I want to impute missing values using the package mi. My file has around 
28 MB (50.000 observations, 120 variables). My computer is a Windows XP 
32-bit machine, 4 GB Duo Core processor.
When I run mi, already after some minutes during iteration 1, I get the 
message that a vector allocation fails. Even with a 10% sample of the 
dataset, it doesn't work.

I've read about the packages ff and bigmemory. Can they help me that the 
mi package doesn't use the RAM for temporary files but the hard drive 
instead? Since I'm not a R expert, I don't understand completely how these 
packages work. Or are there other packages for a better memory management? 
Or is really a 64-bit OS the only solution for this problem? I hope that 
there are some suggestions for my problem since many R procedures seem to 
be very promising but they don't work on my machine because of the memory 
limitation.

Thanks,
Hans-Peter

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[R] multi-stage sampling and hierarchical models: which packages?

2010-03-23 Thread Steve Powell
Dear wizaRds,
I have a dataset to analyse which is causing me problems. It is a sample of
parents in schools. First we had a population table of the schools in the
country in question divided into five regions, and in each region we have an
urban/rural split. The population Ns in these ten cells are known. Then
three schools were drawn from each cell according to the Lahirie method, i.e
with probability of being selected depending on school size. Students were
then drawn randomly from the schools, again with probability proportional to
school size. Details of this are below in case this is important. I have
calculated the weights.

So I have a weighting problem and a mixed levels problem at the same time.
Even if I just use the survey package I am not sure how to specify the
model, because I have clusters within strata rather than strata within
clusters.

I guess it would look something like
dstrat-svydesign(id=~schoolC,strata=~region+urbanrural, weights=~newweight,
data=mydataset,nest=T),
but this gives the same results as
dstrat-svydesign(id=~schoolC,strata=~region, weights=~newweight,
data=mydataset,nest=T)

And I can't see any way to look at the mixed levels effects using that
package. Perhaps I am better advised to use nlme; I guess I can just use the
weights as a covariate?

My ultimate aims are to conduct various regressions in which I expect the
school- and region-level effects to be strong. Ideally I would like to use
sem as well, but then I am really stuck.
If someone could put me on the right track I could be more specific with
reproducible examples etc


Best Wishes
Steve Powell
**details of Lahirie method as we used it: the schools were
put into a list in order of ascending size (student population) and this
list was divided into three bands containing 25%, 35% and 40% of all the
students in the cell, respectively; and three schools were chosen randomly
from each size band. Then samples of students were drawn randomly from lists
of students at each school, so that more students were chosen from the
larger schools: 20, 30 and 40 from each of the smaller, medium and large
schools. So we have (20+30+40)*3 students per cell, for 10 cells = 2700
students in this country.

www.promente.org | skype stevepowell99 | Thailand +66 8 4438 2667

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[R] glmpath and coxpath variables

2010-03-23 Thread Antoni Picornell
Hi,

I am analyzing a set of variables in order to create a survival model for a
set of patients. I have checked the reference manual for glm path and
coxpath in order to achieve it. However I have a doubt about the class of
the covariates I can use with the last mentioned package.

In the example, the package loads a list called lung.data. This object has
a matrix with the covariate information x and two vectors about the
censoring and the time to the event. The information in the x matrix seems
to be numeric, but some of the covariates could be categorical (1st and 2nd
columns) because they only have 2 or 4 different values. If we check their
class they are numeric.

Thus, the question is: can I use categorical and continuous covariates in
this matrix (x)?

Thanks a lot,
Antoni.

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[R] using a list to index elements of a list

2010-03-23 Thread Pj253

I have a list of vectors, x, with x[[1]]=1:5, say.

And I need to go through each element of each vector in a for loop.
Something like:

for (v in x[[1]])
print(v)

However, I need to store this index v for later, and I have lots of other
indices which we range over later in the code so thought I'd make a list of
these indices, v-list(). But then when I try:

for( v[[1]] in x[[1]] )
print(v[[1]])

I get errors:

 x-list()
 x[[1]]=1:5
 v-list()
 for(v[[1]] in x[[1]])
Error: unexpected '[[' in for(v[[
 print v[[1]]
Error: unexpected symbol in print v

Can you not use a list in this way, i.e. to store variables to range over in
a for loop? Can anyone offer a solution?

Thanks for any help!

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Re: [R] using a list to index elements of a list

2010-03-23 Thread Benilton Carvalho
if this was to work, wouldn't the object 'v' be identical to 'x'?...
so, why not use 'x' itself?
b

On Tue, Mar 23, 2010 at 2:53 PM, Pj253 pj...@cam.ac.uk wrote:

 I have a list of vectors, x, with x[[1]]=1:5, say.

 And I need to go through each element of each vector in a for loop.
 Something like:

 for (v in x[[1]])
 print(v)

 However, I need to store this index v for later, and I have lots of other
 indices which we range over later in the code so thought I'd make a list of
 these indices, v-list(). But then when I try:

 for( v[[1]] in x[[1]] )
 print(v[[1]])

 I get errors:

 x-list()
 x[[1]]=1:5
 v-list()
 for(v[[1]] in x[[1]])
 Error: unexpected '[[' in for(v[[
 print v[[1]]
 Error: unexpected symbol in print v

 Can you not use a list in this way, i.e. to store variables to range over in
 a for loop? Can anyone offer a solution?

 Thanks for any help!

 --
 View this message in context: 
 http://n4.nabble.com/using-a-list-to-index-elements-of-a-list-tp1679184p1679184.html
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Re: [R] using a list to index elements of a list

2010-03-23 Thread Pj253

Thanks for your reply Ben!

I don't think I want v to be identical to x... I guess I haven't put the
question in the right context. What I'm actually trying to do is... (*
indicates extra information, not necessarily relevant for my question, but
to help put it in context)

A, some  matrix (*a traceless, symmetric matrix of 0's, 1's (representing a
graph)*)

x-list()
x[[1]]-1:nrow(A)
for (i in x[[1]]){
if (A[1,i]==1) {
x[[2]]-x[[1]][!(x[[1]]==1)]
for (j in x[[2]]){
if (A[i,j]==1){
path-c(1,i,j)
print(path)
}
}
}
}

So, here I have used i and j to range over the elements of x[[1]], x[[2]]
respectively.
(*This prints all the paths of length 2 starting at vertex 1. But I'm trying
to generalise this for a path of length nrow(A), i.e. a Hamiltonian path)*)
I want to iterate this process a certain number of times, so instead of i,j
I thought to use a list of scalars, v.
I don't want v to be identical to x... I want v to be a list of scalars
which range (inside a for loop) over an elements of the list x. (so instead
of for (i in x[[k]]) I have for (v[[k]] in x[[k]])).

I can see how they look similar, but I do think they're different objects.
Hope this is clear. If you still think using 'x' itself would work, can you
explain how so?
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Re: [R] using a list to index elements of a list

2010-03-23 Thread Benilton Carvalho
can you also post an example of A and an example of the expected result?

On Tue, Mar 23, 2010 at 3:36 PM, Pj253 pj...@cam.ac.uk wrote:

 Thanks for your reply Ben!

 I don't think I want v to be identical to x... I guess I haven't put the
 question in the right context. What I'm actually trying to do is... (*
 indicates extra information, not necessarily relevant for my question, but
 to help put it in context)

 A, some  matrix (*a traceless, symmetric matrix of 0's, 1's (representing a
 graph)*)

 x-list()
 x[[1]]-1:nrow(A)
 for (i in x[[1]]){
        if (A[1,i]==1) {
            x[[2]]-x[[1]][!(x[[1]]==1)]
            for (j in x[[2]]){
                    if (A[i,j]==1){
                        path-c(1,i,j)
                        print(path)
                        }
                    }
        }
 }

 So, here I have used i and j to range over the elements of x[[1]], x[[2]]
 respectively.
 (*This prints all the paths of length 2 starting at vertex 1. But I'm trying
 to generalise this for a path of length nrow(A), i.e. a Hamiltonian path)*)
 I want to iterate this process a certain number of times, so instead of i,j
 I thought to use a list of scalars, v.
 I don't want v to be identical to x... I want v to be a list of scalars
 which range (inside a for loop) over an elements of the list x. (so instead
 of for (i in x[[k]]) I have for (v[[k]] in x[[k]])).

 I can see how they look similar, but I do think they're different objects.
 Hope this is clear. If you still think using 'x' itself would work, can you
 explain how so?
 --
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Re: [R] If else statements

2010-03-23 Thread tj

Thanks Sam for the short but very helpful answer. That's what I only want to 
know.
Thanks.=)

~tj


  
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Re: [R] using a list to index elements of a list

2010-03-23 Thread William Dunlap
 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of Pj253
 Sent: Tuesday, March 23, 2010 7:54 AM
 To: r-help@r-project.org
 Subject: [R] using a list to index elements of a list
 
 
 I have a list of vectors, x, with x[[1]]=1:5, say.
 
 And I need to go through each element of each vector in a for loop.
 Something like:
 
 for (v in x[[1]])
 print(v)
 
 However, I need to store this index v for later, and I have 
 lots of other
 indices which we range over later in the code so thought I'd 
 make a list of
 these indices, v-list(). But then when I try:
 
 for( v[[1]] in x[[1]] )
 print(v[[1]])
 
 I get errors:
 
  x-list()
  x[[1]]=1:5
  v-list()
  for(v[[1]] in x[[1]])
 Error: unexpected '[[' in for(v[[

The syntax of the for statement is
   for(name in values) expr
where name must be a name object, not
a call like v[[i]] or anything else.

Will your code work as you wish if you
replace the for(v[[1]] in x[[1]]) { ... }
with the following?
   for(i in x[[1]]) {
  v[[2]] - i
  ...
   }

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com  

  print v[[1]]
 Error: unexpected symbol in print v
 
 Can you not use a list in this way, i.e. to store variables 
 to range over in
 a for loop? Can anyone offer a solution?
 
 Thanks for any help!
 
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Re: [R] Converting date format

2010-03-23 Thread jim holtman
try this:

 x - c('1/1/1970','12/13/2010', '2/3/2001')
 gsub((\\d+/\\d+/)\\d\\d(\\d\\d file://d+///d+/)//d//d(//d//d), 
 \\1\\2file://0.0.0.1//2,
x)
[1] 1/1/70   12/13/10 2/3/01


On Tue, Mar 23, 2010 at 10:10 AM, Hosack, Michael mhos...@state.pa.uswrote:

 R community:

 Hello, I would to like to convert a character date variable from %m/%d/%Y
 to %m/%d/%y. Any advice would be greatly appreciated. I have tried functions
 for changing the formatting and removing the unnecessary digits without
 success.

 Mike

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[R] barplot (stacked)

2010-03-23 Thread koj

Dear all,

I want to draw a barplot with the following data:


 [,1] [,2]   [,3]   [,4] [,5] [,6] [,7]   
[,8] [,9]
[1,] 110.0675 118.4167 117.16 109.735416 101.6312 104.0312 101.8263
99.38541670 114.2613
[2,]   0.   0.   0.00   1.658333   0.   0.6250   0. 
0.05208333   0.

 [,10][,11][,12][,13][,14]   [,15][,16][,17]
[,18]
[1,] 46.597917 108.5312 99.85833 104.3137 99.07917 95.5975 92.07292 108.6338
104.82917
[2,]  2.458333   0.  2.62500   0.  0.18750  0.  0.0   0.  
0.40625

[,19] [,20]
[1,] 48.90625  47.5
[2,]  0.0   0.0

The problem is: I want to group the data. I want to have ten groups. The
first two bars should be [1,1] and [2,1] together in one bar and in the
second bar of the first obervation should be [1,2] and [2,2] (stacked with
beside =TRUE). Therefore the first observation is [1,1],[1,2],[2,1] and
[2,2].

For a better understanding: I want to split the darkblue bar into a green
and a blue bar (please see picture) per observation.

Has anyone a suggestion how I can do this? Thank you very much in advane.


http://n4.nabble.com/file/n1679227/Pic.jpg 
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Re: [R] caret package, how can I deal with RFE+SVM wrong message?

2010-03-23 Thread Max Kuhn
Kevin!

I've sent 5 replies to your questions already off-list.

The first question is easy (see below). The others will need more
information on your data (via str(trx) abd str(try)) and you versions
(sessionInfo()) as previously asked off-list.

Sorry to out you, but this is bad form.

Max

 I am learning caret package, and I want to use the RFE to reduce the
 feature. I want to use RFE coupled Random Forest (RFE+FR) to complete this
 task. As we know, there are a number of pre-defined sets of functions, like
 random Forest(rfFuncs), however,I want to tune the parameters (mtr) when
 RFE, and then I write code below, but there is something wrong message, How
 can I deal with it?
 rfGrid-expand.grid(.mtry=c(1:2))
 rfectrl-rfeControl(functions=caretFuncs,method=cv,verbose=F,returnResamp=final,number=10)
 subsets-c(3,4)
 set.seed(2)
 rf.RFE-rfe(trx,try,sizes=subsets,rfeControl=rfectrl,method=rf,tuneGrid=rfGrid)
 Loading required package: class

 Attaching package: 'class'


        The following object(s) are masked from package:reshape :

         condense

 Fitting: mtry=1
 Fitting: mtry=2
 Error in varImp.randomForest(object$finalModel, ...) :
  subscript out of bounds
 In addition: Warning message:
 package 'e1071' was built under R version 2.10.1

You didn't pass importance = TRUE to randomForest


 At the same time, If I want to  use RFE+SVM,  RFE+nnet, and so on ,how can I
 do? I have try RFE+SVM, also wrong message: set.seed(1)
 svmProfile-rfe(trx,try,sizes=c(1:3),
 +             rfeControl=rfeControl(functions=caretFuncs,method=cv,
 +             verbose=F,returnResamp=final,number=10),
 +             method=svmRadial,tuneLength=5)
 Fitting: sigma=0.009246713, C=0.1
 Fitting: sigma=0.009246713, C=1
 Fitting: sigma=0.009246713, C=10
 Fitting: sigma=0.009246713, C=100
 Fitting: sigma=0.009246713, C=1000
 Error in rfeControl$functions$rank(fitObject, .x, y) :
  need importance columns for each class


-- 

Max

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[R] Sample size for proportion, not binomial

2010-03-23 Thread Prew, Paul
Hello,  I am looking for a sample size function for samples sizes, to test 
proportions that are not binomial proportions.  The proportions represent a 
ratio of (final measure) / (baseline measure) on the same experimental unit.  
Searches using RSeek and such bring multiple hits for binomial proportions, but 
that doesn't seem to fit my situation.  Perhaps there's some standard 
terminology from a different field that would provide better hits than deeming 
this a 'rate' or a 'proportion'.

Of course, most sample size functions assume a normal distribution, while this 
data will be bounded between 0 and 1.  The scientist I'm working with feels 
it's important to make fair comparisons, any weight loss must account for the 
baseline weight.  A logistic transformation seems appropriate, but that term 
also didn't yield hits I recognized as useful.

Loss of weight --- compare treatments:
Treatment A:  1 - Final weight / Initial weight
Treatment B:  1 - Final weight / Initial weight

This appears to be a situation that would be common, but I'm not framing it in 
a way that matches an R package.  Any guidance is appreciated.

Regards, Paul


Paul Prew   ▪  Statistician
651-795-5942   ▪   fax 651-204-7504 
Ecolab Research Center   ▪  Mail Stop ESC-F4412-A 
655 Lone Oak Drive   ▪   Eagan, MN 55121-1560 



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Re: [R] using a list to index elements of a list

2010-03-23 Thread Pj253

Thanks Bill, that sorted it out! And thank you too Ben!

Bill and Ben. Are you familiar with the flowerpot men by any chance!?

Thanks again!

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Re: [R] using a list to index elements of a list

2010-03-23 Thread Benilton Carvalho
and in addition to bill's suggestion, you may want to consider not
growing a list.

Instead of 'v - list()', use:

v - vector(list, nrow(A))

b

 Will your code work as you wish if you
 replace the for(v[[1]] in x[[1]]) { ... }
 with the following?
   for(i in x[[1]]) {
      v[[2]] - i
      ...
   }

 Bill Dunlap
 Spotfire, TIBCO Software
 wdunlap tibco.com

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Re: [R] filled.contour formatting questions

2010-03-23 Thread John K. Williams
Hmm yes that is what I'm looking for in terms of color scale control, but I
need it for contoured plots.  John.

On Mon, Mar 22, 2010 at 10:32 PM, Jim Lemon j...@bitwrit.com.au wrote:

 On 03/23/2010 12:48 PM, John K. Williams wrote:

 Hello, I'm having some trouble getting things to look as I want with
 filled.contour.

 1.  My first issue is that I am unable to add line segments to my plot
 where
 I want them.  Using the rug pattern example:
 x- y- seq(-4*pi, 4*pi, len = 27);
 r- sqrt(outer(x^2, y^2, +));
 filled.contour(cos(r^2)*exp(-r/(2*pi)));
 segments(0.2,0.2,1,0.2);
 The line segment is not found in relation to the x-axis but is seemingly
 squished over by the color bar.

 If I try to achieve the line this way:

 filled.contour(cos(r^2)*exp(-r/(2*pi)),plot.axes={lines(c(0.2,1),c(0.2,0.2))})
 Now when I add the axis back it is misaligned.
 axis(1).

 2. Secondly I'm finding the literature difficult to understand on how to
 make a nice color scheme.  Below is a nice scheme I found from an example,
 except I don't understand why the scale seems to cycle into blue again for
 larger values, even though I think I am setting the number of levels of
 colors and contour levels to be equal.  Basically I want reds for the
 highest values and blues for the lowest:

 filled.contour(cos(r^2)*exp(-r/(2*pi)),nlevels=25,col=hsv(h=seq(from=.7,to=0,length=25)))

 3.  I'm used to working with matlab where it was simple to make the color
 scale the same on multiple figures using caxis().  However I don't see
 this
 option for filled.contour (possibly it exists for levelplot() but I was
 having even less success understanding that one).  I only see the option
 to
 set the number of levels which doesn't really accomplish what I want for
 plots that are going to have widely varying limits.

  Hi John,
 I'm not sure that this is what you want, but the examples for the barp
 function in the plotrix package include one for a color scale that extends
 beyond the values that are to be plotted. That is, you can specify the range
 of the color scale regardless of the actual values.

 Jim



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Re: [R] Changing global variables from functions

2010-03-23 Thread jtouyz

Thanks for the help, I've fixed the problem.
-Josh Elliott
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[R] Optim() Help, Unusual Error

2010-03-23 Thread ApproxGaussian

Hello all, any help with the following would be appreciated.

I am attempting to maximize 28 parameters similtaneously in Optim().  The
follwoing is my code:

Y-comp[,9]
n-length(Y)


e.1-.5
e.2-.5
e.3-.5
e.4-.5
e.5-.5
e.6-.5
e.7-.5
e.8-.5
e.9-.5
e.10-.5
e.11-.5
e.12-.5
e.13-.5
e.14-.5
e.15-.5
e.16-.5
e.17-.5
e.18-.5
e.19-.5
e.20-.5
e.21-.5
e.21-.5
e.22-.5
e.23-.5
e.24-.5
e.25-.5
e.26-.5
e.27-.5
e.28-.5
par-(e.1,e.2,e.3,e.4,e.5,e.6,e.7,e.8,e.9,e.10,e.11,e.12,e.13,e.14,e.15,e.16,e.17,e.18,e.19,e.20,e.21,e.22,e.23,e.24,e.25,e.26,e.27,e.28)


# Define the objective function:
objective.function - function(par,comp,Y,n) {
e.1-par[1]
e.2-par[2]
e.3-par[3]
e.4-par[4]
e.5-par[5]
e.6-par[6]
e.7-par[7]
e.8-par[8]
e.9-par[9]
e.10-par[10]
e.11-par[11]
e.12-par[12]
e.13-par[13]
e.14-par[14]
e.15-par[15]
e.16-par[16]
e.17-par[17]
e.18-par[18]
e.19-par[19]
e.20-par[20]
e.21-par[21]
e.22-par[22]
e.23-par[23]
e.24-par[24]
e.25-par[25]
e.26-par[26]
e.27-par[27]
e.28-par[28]

residuals.squared - c()

for (i in 1:n) residuals.squared[i] - (Y[i] - (
((e.26^comp[i,3])*(e.27^(comp[i,7]-mean(comp[,7])))*(e.28^comp[i,6])*(comp[i,65]^comp[i,5]))*
(e.1*comp[i,10]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.21)
+
e.2*comp[i,11]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.21)
+
e.3*comp[i,12]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.21)
+
e.4*comp[i,13]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.22)
+
e.5*comp[i,14]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.22)
+
e.6*comp[i,15]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.22)
+
e.7*comp[i,16]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.23)
+
e.8*comp[i,17]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.24)
+
e.9*comp[i,18]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.24)
+
e.10*comp[i,19]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.24)
+
e.11*comp[i,20]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.24)
+
e.12*comp[i,21]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.13*comp[i,22]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.14*comp[i,23]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.15*comp[i,24]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.15*comp[i,25]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.16*comp[i,26]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.15*comp[i,27]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.12*comp[i,28]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25)
+
e.8*comp[i,29]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.24)
+
e.14*comp[i,30]*comp[i,34]+comp[i,35])+(e.17*(comp[i,36]+comp[i,37]+comp[i,38]))+(e.18*comp[i,41])+(e.19*comp[i,39])+(e.20*comp[i,42]))/(comp[i,31]+comp[i,32]+comp[i,33]))^e.25))^2)
)

[R] R Participation in the Google Summer of Code 2010

2010-03-23 Thread Dirk Eddelbuettel

Dear R Users,

We would like to highlight that R has once again been selected to participate
in the Google Summer of Code.  Suggested projects can be found in the R-Wiki:
http://rwiki.sciviews.org/doku.php?id=developers:projects:gsoc2010.  The GSoC
is a program from Google that offers student developers stipends to write
code for various open source software projects (more information can be found
here: http://code.google.com/soc/).

All discussion related to R and the Google Summer of Code should preferably
tak place on the respective google group:
http://groups.google.com/group/gsoc-r (gso...@googlegroups.com).
 
We are currently in a time period during which interested students can
discuss an idea from the wiki with the respective project mentor, or contact
the gsoc-r group to propose a new one and find a mentor.  Please note that
some projects on the R-Wiki also provide test questions, so please read these
pages thoroughly before contacting a project mentor. The student application
period opens on March 29th.

Best regards,

the R Project GSoC mentors

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[R] qplot(ggplo2): axis label sizes/colors

2010-03-23 Thread milton ruser
Dear all,

How can I change the size and the color of axis?
I would like that the xlab to be larger, xvalues to be
larger, and xvalues in black instead of grey.

x=runif(10)
y=runif(10)
require(ggplo2)
qplot(x,y)

cheers

milton

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Re: [R] qplot(ggplo2): axis label sizes/colors

2010-03-23 Thread Xie Chao
http://had.co.nz/stat405/lectures/21-themes.pdf

On Wed, Mar 24, 2010 at 1:22 AM, milton ruser milton.ru...@gmail.com wrote:
 Dear all,

 How can I change the size and the color of axis?
 I would like that the xlab to be larger, xvalues to be
 larger, and xvalues in black instead of grey.

 x=runif(10)
 y=runif(10)
 require(ggplo2)
 qplot(x,y)

 cheers

 milton

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and provide commented, minimal, self-contained, reproducible code.


[R] Displaying equations from .Rd files

2010-03-23 Thread AC Del Re
Hi All,

I am reading through section 2.6 (Mathematics) of  the Writing R
Extensions manuscript and am wondering where I can find more
examples/documentation on the \deqn{ } function. I would like to learn how
to display equations using this function but am not sure how to go about
doing it. The one example provided in section 2.6 doesn't give me much of a
sense on how to do this.

Thank you,

 AC

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[R] Operator overloading for custom classes

2010-03-23 Thread Chidambaram Annamalai
Hi,

I need some help to get some of the object orientation, specifically the
methods that overload the basic arithmetic operations, from sample C++
code to R. I don't have experience with such advanced language features
inside of R. So I was wondering if some of you could help me out in this
regard.

I have written a simple demonstration of a forward mode automatic
differentiator in C++ and it is currently hosted on github:
http://github.com/quantumelixir/ad-demo/blob/master/simple.cpp. It uses
simple operator overloading techniques to modify the meaning of the
basic arithmetic operations (+, -, *, /) for the derivative type Dual
number class that I have defined. Could you show me how this could be
equivalently done in R? I want to know how to define custom classes and
define the meaning of arithmetic for them.

I had checked for operator overloading in R but could only find the
equivalence of a + b and '+'(a, b) in the R language definition. Could
you show how I could extend the simple object oriented-ness in the C++
code neatly to R?

Thanks a bunch!
Chillu

PS: Sorry that I had mistakenly sent the email to the r-devel list earlier,
instead of the intended r-help list. This is a copy of the same email.

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Re: [R] information module Wilks' lambda criterion

2010-03-23 Thread Charles C. Berry

On Tue, 23 Mar 2010, Catherine ENG wrote:


Hi everybody,

I was wondering if you can help me about a module. In fact, I'm looking for
a package or module about Wilks' lambda criterion in R environment. I didn't
find it in R website (


See

?summary.manova

HTH,

Chuck


http://cran.cict.fr/web/packages/index.html#available-packages-W or
http://search.cpan.org/faq.html).
If this module exists, could you show me the command line.

Thank you very much for your help,
Miss Catherine ENG


-
Laboratoire de G?n?tique et Microbiologie UMR INRA 1128 - IFR 110
Universit? Henri Poincar? - Facult? des Sciences BP 239
54506 Vandoeuvre-l?s-Nancy
T?l. : 06.58.25.37.66

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Charles C. Berry(858) 534-2098
Dept of Family/Preventive Medicine
E mailto:cbe...@tajo.ucsd.edu   UC San Diego
http://famprevmed.ucsd.edu/faculty/cberry/  La Jolla, San Diego 92093-0901

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[R] Creating pdfs using qplot in qqplot2

2010-03-23 Thread Bos, Roger
I am trying to create plots within a for loop and output them to a pdf.
Here is a working example using plot:

  gg - data.frame(datadate=1:4, spread=5:8)
  pdf()
  for (i in 1:3) {
  plot(gg$datadate, gg$spread, main=i)
  }
  dev.off()

I am trying to learn more about ggplot2 so I try a slight modification
and it doesn't work.  Anyone know how to do this using qplot in ggplot2?


   gg - data.frame(datadate=1:4, spread=5:8)
  pdf()
  for (i in 1:3) {
  qplot(gg$datadate, gg$spread, geom=line, main=i)
  }
  dev.off()

***

This message is for the named person's use only. It may\...{{dropped:20}}

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Re: [R] Creating pdfs using qplot in qqplot2

2010-03-23 Thread stephen sefick
you have to print the object

gg - data.frame(datadate=1:4, spread=5:8)
   pdf()
   for (i in 1:3) {
+   d - qplot(gg$datadate, gg$spread, geom=line, main=i)
+   print(d)}
   dev.off()

On Tue, Mar 23, 2010 at 1:14 PM, Bos, Roger roger@rothschild.com wrote:
 I am trying to create plots within a for loop and output them to a pdf.
 Here is a working example using plot:

          gg - data.frame(datadate=1:4, spread=5:8)
          pdf()
          for (i in 1:3) {
              plot(gg$datadate, gg$spread, main=i)
          }
          dev.off()

 I am trying to learn more about ggplot2 so I try a slight modification
 and it doesn't work.  Anyone know how to do this using qplot in ggplot2?


           gg - data.frame(datadate=1:4, spread=5:8)
          pdf()
          for (i in 1:3) {
              qplot(gg$datadate, gg$spread, geom=line, main=i)
          }
          dev.off()

 ***

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-- 
Stephen Sefick

Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like gods.  We are mammals, and have not exhausted the
annoying little problems of being mammals.

-K. Mullis

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[R] Conditional replacement of NA depending on value in the previous column

2010-03-23 Thread Mark Na
Dear R-helpers,

I have a dataframe like this:

ID  X1  X2  X3  X4  X5  X6
49  1   1   1   0   NA  NA
50  1   1   1   1   NA  1

I would like to convert a missing value (NA) that follows a 0 (zero) or
another missing value (NA) into a 0 (zero).

So, the above lines would be converted to:

ID  X1  X2  X3  X4  X5  X6
49  1   1   1   0   0   0
50  1   1   1   1   NA  1

I have been struggling with this all morning, so any help you could provide
would be much appreciated.

Thank you!

Mark Na

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Re: [R] Conditional replacement of NA depending on value in the previous column

2010-03-23 Thread Phil Spector

Mark -
   Does this do what you want?

dat = data.frame(X1=c(1,1),X2=c(1,1),X3=c(1,1),
 X4=c(0,1),X5=c(NA,NA),x6=c(NA,1))

fixit = function(x){
 y = c(x[-1],0)
 x[is.na(y)  is.na(x)] = 0
 x}

t(apply(dat,1,fixit))

 X1 X2 X3 X4 X5 x6
[1,]  1  1  1  0  0  0
[2,]  1  1  1  1 NA  1


- Phil Spector
 Statistical Computing Facility
 Department of Statistics
 UC Berkeley
 spec...@stat.berkeley.edu



On Tue, 23 Mar 2010, Mark Na wrote:


Dear R-helpers,

I have a dataframe like this:

ID  X1  X2  X3  X4  X5  X6
49  1   1   1   0   NA  NA
50  1   1   1   1   NA  1

I would like to convert a missing value (NA) that follows a 0 (zero) or
another missing value (NA) into a 0 (zero).

So, the above lines would be converted to:

ID  X1  X2  X3  X4  X5  X6
49  1   1   1   0   0   0
50  1   1   1   1   NA  1

I have been struggling with this all morning, so any help you could provide
would be much appreciated.

Thank you!

Mark Na

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Re: [R] Creating pdfs using qplot in qqplot2

2010-03-23 Thread Sharpie


Bos, Roger-2 wrote:
 
 I am trying to create plots within a for loop and output them to a pdf.
 Here is a working example using plot:
 
   gg - data.frame(datadate=1:4, spread=5:8)
   pdf()
   for (i in 1:3) {
   plot(gg$datadate, gg$spread, main=i)
   }
   dev.off()
 
 I am trying to learn more about ggplot2 so I try a slight modification
 and it doesn't work.  Anyone know how to do this using qplot in ggplot2?
 
 
  gg - data.frame(datadate=1:4, spread=5:8)
   pdf()
   for (i in 1:3) {
   qplot(gg$datadate, gg$spread, geom=line, main=i)
   }
   dev.off()
 

This question gets asked many, many times and is answered in FAQ 7.22:

 
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-do-lattice_002ftrellis-graphics-not-work_003f


Basically, old-school functions like plot() execute plotting commands
directly when they are called.  With Lattice-based graphics, like ggplot2,
the composition of the plot and the execution of the plotting commands are
separated into two steps.  qplot() returns an object that contains the
composition of the plot, the print() method performs the actual execution of
plotting commands to a graphics device.

When functions are called interactively in the top-level environment, an
implicit call to print() is executed to display the results.  When these
same functions are used inside another function or for() loop, you will need
to explicitly add the call to print() in order to get the same effect.

Hope this helps!

-Charlie


-
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Undergraduate-- Environmental Resources Engineering
Humboldt State University
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Re: [R] If else statements

2010-03-23 Thread Sharpie


tj wrote:
 
 Thanks Sam for the short but very helpful answer. That's what I only want
 to know.
 Thanks.=)
 
 ~tj 
 

Even though you got the answer you were looking for, I would still browse
the material Matthew posted.  The Introduction to R is a standard R manual
that helped me greatly when I was learning the R language.  The question you
asked is answered in this manual and Eric Raymond's essay explains why
asking questions that are answered in the manual can be socially risky on
software mailing lists.

You don't want the last reply you ever get from a list to be RTFM!

-Charlie

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Undergraduate-- Environmental Resources Engineering
Humboldt State University
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[R] rpad ?

2010-03-23 Thread sjaffe

Is anyone using rpad? Is there any documentation or examples beyond that in
the 'man' directory of the source? 

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Re: [R] Operator overloading for custom classes

2010-03-23 Thread Sharpie


Chidambaram Annamalai wrote:
 
 Hi,
 
 I need some help to get some of the object orientation, specifically the
 methods that overload the basic arithmetic operations, from sample C++
 code to R. I don't have experience with such advanced language features
 inside of R. So I was wondering if some of you could help me out in this
 regard.
 
 {snip}
 
 

For S3 objects:

  ?base::Ops

  http://n4.nabble.com/Operator-overloading-td854452.html#a854452
  http://n4.nabble.com/Overloading-td850827.html#a850828

For S4 objects:

  ?methods::Ops

  http://n4.nabble.com/How-to-define-new-operators-td974842.html#a974842


A good resource for reading material on S4 classes, which are more formally
defined than S3 classes, can be found in the R wiki:

  http://rwiki.sciviews.org/doku.php?id=tips:classes-s4


Hope this can get you started!

-Charlie

-
Charlie Sharpsteen
Undergraduate-- Environmental Resources Engineering
Humboldt State University
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Re: [R] Optim() Help, Unusual Error

2010-03-23 Thread Nikhil Kaza

missed a c(...) here,
therefore no par defined.


On Mar 23, 2010, at 12:58 PM, ApproxGaussian wrote:

par-(e.1,e.2,e.3,e.4,e.5,e.6,e.7,e.8,e.9,e.10,e.11,e.12,e.13,e.14,e. 
15,e.16,e.17,e.18,e.19,e.20,e.21,e.22,e.23,e.24,e.25,e.26,e.27,e.28)


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Re: [R] Optim() Help, Unusual Error

2010-03-23 Thread ApproxGaussian

I apologize, the c is in the original coding; I merely misprinted (copy and
paste).

I have edited the orginal post to reflect this.
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Re: [R] rpad ?

2010-03-23 Thread sjaffe

Based on a private response, it seems that rpad is no longer being maintained
and in fact no longer works with the latest R release.  I noticed that the
web site listed in the FAQ no longer works, the code is being hosted by
google code but it appears no one is working on it. 

Looking at the R Web Interfaces section of the R FAQ I don't really see
anything comparable -- does anyone have a suggestion for a similar web-based
front-end to R? 

From the FAQ:

Rpad, developed and actively maintained by Tom Short, provides a
sophisticated environment which combines some of the features of the
previous approaches with quite a bit of JavaScript, allowing for a GUI-like
behavior (with sortable tables, clickable graphics, editable output), etc. 
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Re: [R] no predict function in lme4 ?

2010-03-23 Thread Douglas Bates
It is not easy to decide what predict should return for a linear
mixed model, let alone the more complicated cases.  Do you want
predictions based on the fixed-effects only or based on a combination
of the fixed-effects and the random-effects?  For the lme function in
the nlme package we allowed levels of predictions but that won't
work for all models that can be fit with lme4.

On Tue, Mar 23, 2010 at 9:18 AM, Markus Loecher
markus.loec...@gmail.com wrote:
 Dear mixed effects modelers,
 I seem unable to find a predict method for mer objects in the package lme4.
 Am I not seeing the forest for the trees ?

 Any pointer would be very helpful.
 Thanks,
 Markus

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Re: [R] help needed with boxplot

2010-03-23 Thread kathy_BJ

Thank you so much for help, Jim. But I didn't get any plot after I submit the
job except below, which indicating the number of lines for the two inputs.
What's the problem?

Read 3360 records
Read 3360 records

I know I didn't confuse you. 
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Re: [R] rpad ?

2010-03-23 Thread Sharpie


sjaffe wrote:
 
 Based on a private response, it seems that rpad is no longer being
 maintained and in fact no longer works with the latest R release.  I
 noticed that the web site listed in the FAQ no longer works, the code is
 being hosted by google code but it appears no one is working on it. 
 
 Looking at the R Web Interfaces section of the R FAQ I don't really see
 anything comparable -- does anyone have a suggestion for a similar
 web-based front-end to R? 
 

You could try Sage:

  http://www.sagemath.org

You can get a notebook account at:

  http://www.sagenb.org

Sage uses python to integrate several open-source and closed-source
mathmatics/computation packages and R is among one of the options available. 
It provides a nice Mathematica-like notebook interface where you can mix
computations and annotations.  If you don't want to type Sage code, just
choose 'r' from the drop-down menu at the top of the worksheet next to the
Typeset checkbox and the contents of every cell you enter will be passed
directly to R for evaluation.

Hope this helps!

-Charlie



-
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Undergraduate-- Environmental Resources Engineering
Humboldt State University
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Re: [R] rpad ?

2010-03-23 Thread sjaffe


Sharpie wrote:
 
 You could try Sage:
 
   http://www.sagemath.org
 

Yes, I've tried Sage (briefly) and it is very interesting. But what I'm
looking for here is a client-server system that allows multiple users to
access the results of R without exposing the details.
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Re: [R] rpad ?

2010-03-23 Thread Sharpie


sjaffe wrote:
 
 Yes, I've tried Sage (briefly) and it is very interesting. But what I'm
 looking for here is a client-server system that allows multiple users to
 access the results of R without exposing the details.
 

Maybe you're looking for something similar to this webapp:

  http://rweb.stat.ucla.edu/ggplot2/

The author's website is at:

  http://www.stat.ucla.edu/~jeroen/live.html

I believe he used RApache to drive the site, but I'm not positive.  The
widgets are done in ExtJS.

-Charlie

-
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Undergraduate-- Environmental Resources Engineering
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Re: [R] Operator overloading for custom classes

2010-03-23 Thread Chidambaram Annamalai
Thanks!


On Wed, Mar 24, 2010 at 1:01 AM, Sharpie ch...@sharpsteen.net wrote:



 Chidambaram Annamalai wrote:
 
  Hi,
 
  I need some help to get some of the object orientation, specifically the
  methods that overload the basic arithmetic operations, from sample C++
  code to R. I don't have experience with such advanced language features
  inside of R. So I was wondering if some of you could help me out in this
  regard.
 
  {snip}
 
 

 For S3 objects:

  ?base::Ops

  http://n4.nabble.com/Operator-overloading-td854452.html#a854452
  http://n4.nabble.com/Overloading-td850827.html#a850828

 For S4 objects:

  ?methods::Ops

  http://n4.nabble.com/How-to-define-new-operators-td974842.html#a974842


 A good resource for reading material on S4 classes, which are more formally
 defined than S3 classes, can be found in the R wiki:

  http://rwiki.sciviews.org/doku.php?id=tips:classes-s4


 Hope this can get you started!

 -Charlie

 -
 Charlie Sharpsteen
 Undergraduate-- Environmental Resources Engineering
 Humboldt State University
 --
 View this message in context:
 http://n4.nabble.com/Operator-overloading-for-custom-classes-tp1679467p1679573.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] rpad ?

2010-03-23 Thread Erich Neuwirth
We are using RPad for a teaching application here.
But we had to find many things the hard way,
and additionally, it did not survive the latest R release change.
There is a minimal repair, but the maintainer does not answer any email
any more. We did the repair and are giving a modified version to our
students, but we do not have enough resource to take over maintenance.



On 3/23/2010 8:00 PM, sjaffe wrote:
 
 Is anyone using rpad? Is there any documentation or examples beyond that in
 the 'man' directory of the source? 
 

-- 
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Faculty of Computer Science
Computer Supported Didactics Working Group
Visit our SunSITE at http://sunsite.univie.ac.at
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[R] Saving tab/csv delimited data with NaN's

2010-03-23 Thread shankar

Hello,
I am working multiple simulated data sets with missing values, I would  
like to store these data sets in either tab delimited format for .csv  
format with missing values marked as NaN's instead of NA's.


I read the import/export document which mentions that write.table  
command converts NaN's to NA. Is there any other way I can store the  
NaN's. I tried the write syntax it gives me error codes.

Each data files are of dimensions 1000 x 21 .

I would appreciate any help in this regard.

Many thanks

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Re: [R] Saving tab/csv delimited data with NaN's

2010-03-23 Thread Rolf Turner

On 24/03/2010, at 9:50 AM, shan...@bios.unc.edu wrote:

 Hello,
 I am working multiple simulated data sets with missing values, I would  
 like to store these data sets in either tab delimited format for .csv  
 format with missing values marked as NaN's instead of NA's.
 
 I read the import/export document which mentions that write.table  
 command converts NaN's to NA. Is there any other way I can store the  
 NaN's. I tried the write syntax it gives me error codes.
 Each data files are of dimensions 1000 x 21 .
 
 I would appreciate any help in this regard.

A feasible workaround is to convert your data to character before writing them.

Suppose that your data are in a data frame called ``clyde''.  Set

mung - as.data.frame(lapply(clyde,as.character))
write.csv(mung,mung.csv,row.names=FALSE,quote=FALSE)

# Check:
gorp - read.csv(mung.csv)
all.equal(gorp,clyde)
[1] TRUE

HTH

cheers,

Rolf Turner
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[R] Adding matrix rows that have the same name?

2010-03-23 Thread Sarah Berke
Does anyone know if there is an R function that will take a matrix like this

jim 1  0  0  0  0  0
jim 0  1  0  0  0  0
jim 0  0  1  0  0  0
bob1  0  0  0  0  0
bob0  0  1  0  0  0
harry  0  0  1  0  0  0
harry  0  0  0  1  0  0
harry  0  0  0  0  1  0
harry  0  0  0  0  0  1

and make it like this? (that is, add together rows that have the same name?)

jim1 1 1 0 0 0
bob   1 0 1 0 0 0
harry 0 0 1 1 1 1


here's the code I started with, if it helps

library (dummies)
a - c(1,1,1,2,2,3,3,3,3)
b- c(A,B,C,A,C,C,D,E,F)
name- c(jim, jim, jim, bob, bob, harry, harry, harry, harry)
MyMat - cbind (a, b)
rownames (MyMat) - name
dum.mat.temp - dummy (b, MyMat)
   #dum.mat.temp -cbind (name, dum.mat.temp) # if you want names
as a column
dum.mat.temp

Many thanks in advance!
--Sarah

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Re: [R] rpad ?

2010-03-23 Thread Philippe Grosjean

Hello,

You could try svSocket that creates a socket server where several 
clients can connect simultaneously. The server is restricted to local 
clients for obvious security reasons, but if you would like to access it 
though a network, you can use stunnel to transfer the data crypted with SSL.

Best,

Philippe Grosjean

..°}))
 ) ) ) ) )
( ( ( ( (Prof. Philippe Grosjean
 ) ) ) ) )
( ( ( ( (Numerical Ecology of Aquatic Systems
 ) ) ) ) )   Mons University, Belgium
( ( ( ( (
..

On 23/03/10 20:57, sjaffe wrote:



Sharpie wrote:


You could try Sage:

   http://www.sagemath.org



Yes, I've tried Sage (briefly) and it is very interesting. But what I'm
looking for here is a client-server system that allows multiple users to
access the results of R without exposing the details.


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Re: [R] Adding matrix rows that have the same name?

2010-03-23 Thread Henrique Dallazuanna
Try this:

aggregate(as.data.frame(dum.mat.temp), list(row.names(dum.mat.temp)), sum)

On Tue, Mar 23, 2010 at 6:15 PM, Sarah Berke skbe...@gmail.com wrote:
 Does anyone know if there is an R function that will take a matrix like this

 jim     1  0  0  0  0  0
 jim     0  1  0  0  0  0
 jim     0  0  1  0  0  0
 bob    1  0  0  0  0  0
 bob    0  0  1  0  0  0
 harry  0  0  1  0  0  0
 harry  0  0  0  1  0  0
 harry  0  0  0  0  1  0
 harry  0  0  0  0  0  1

 and make it like this? (that is, add together rows that have the same name?)

 jim    1 1 1 0 0 0
 bob   1 0 1 0 0 0
 harry 0 0 1 1 1 1


 here's the code I started with, if it helps

 library (dummies)
 a - c(1,1,1,2,2,3,3,3,3)
 b- c(A,B,C,A,C,C,D,E,F)
 name- c(jim, jim, jim, bob, bob, harry, harry, harry, 
 harry)
 MyMat - cbind (a, b)
 rownames (MyMat) - name
 dum.mat.temp - dummy (b, MyMat)
       #dum.mat.temp -cbind (name, dum.mat.temp) # if you want names
 as a column
 dum.mat.temp

 Many thanks in advance!
 --Sarah

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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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Re: [R] Setting breaks to data more appropriately

2010-03-23 Thread ROLL Josh F
David 
Thanks you for the guidance.  I am looking to drive the data into the 
intervals.  Problem now is that I have a few 0 values that are returning as NA 
(e.g - (0.1,0.2] (0.1,0.2] (0.1,0.2] NA  (0,0.1]  )
This is causing issues when I try and use the brks to inform a clorepleth map.  
I tried setting all na's to 0 but because the dataset is in factor form (I 
guess this is why) it wont allow me to do so. Thoughts about how to handle the 
zero values?  Thanks 
JR

-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net] 
Sent: Monday, March 22, 2010 12:46 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] Setting breaks to data more appropriately


On Mar 22, 2010, at 1:49 PM, LCOG1 wrote:


 Basic question.  For the below data, i would like to but each of the 
 values in a bin that represents their value.  So the below would 
 hopefully put .1 in the 0-.1 bin, .2 in the .11-.2 bin and so forth.  
 The outlying values would then be put into and outer category 
 representing everything
 1.  Im
 using the breaks to inform some code for making a clorepleth map that 
 represents probabilities, which in some cases IS greater than 1

... not if it's a quantile or a probability.

 and i need
 to identify those better.

Define better.

 As my code stands now, my real data is put put into this form when 
 brks is called:

0%10%20%30%40% 
 50%60%
 0. 0.05054675 0.07787235 0.11235238 0.14424786 0.18089360 
 0.21475990
   70%80%90%   100%
 0.26309899 0.30807771 0.39478573 0.67573483.

 But what i want is for the values to be placed in bins corresponding 
 to their value(0-.1, .11-.2, .21-.3 etc)

 Pct.SFD-c(.1,.2,.3,.4,.5,.6,.7,.8,.9,1,2,3)
 brks - quantile(Pct.SFD, )

 I think this is clear.

It's not. You need to decide whether you want the breaking to be driven by you 
or by the data. If you are doing the driving then use

cut(object, breaks=c(seq(0,1, by=0.1), Inf) , right=TRUE)

If the data is doing the driving then:

cut(object, breaks=quantile(object, probs= seq(0,1,1/10 ) ) ,
right=TRUE)

--
David.

 Thanks
 --
 View this message in context: 
 http://n4.nabble.com/Setting-breaks-to-data-more-appropriately-tp16780
 19p1678019.html Sent from the R help mailing list archive at 
 Nabble.com.

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
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Re: [R] rpad ?

2010-03-23 Thread j verzani
sjaffe sjaffe at riskspan.com writes:



 
 
 Sharpie wrote:
  
  You could try Sage:
  
http://www.sagemath.org
  
 
 Yes, I've tried Sage (briefly) and it is very interesting. But what I'm
 looking for here is a client-server system that allows multiple users to
 access the results of R without exposing the details.



You might find gWidgetsWWW able to do what you want. Some demos are here:

www.math.csi.cuny.edu/gWidgetsWWW

--John

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Re: [R] Sample size for proportion, not binomial

2010-03-23 Thread Marc Schwartz
On Mar 23, 2010, at 11:05 AM, Prew, Paul wrote:

 Hello,  I am looking for a sample size function for samples sizes, to test 
 proportions that are not binomial proportions.  The proportions represent a 
 ratio of (final measure) / (baseline measure) on the same experimental unit.  
 Searches using RSeek and such bring multiple hits for binomial proportions, 
 but that doesn't seem to fit my situation.  Perhaps there's some standard 
 terminology from a different field that would provide better hits than 
 deeming this a 'rate' or a 'proportion'.
 
 Of course, most sample size functions assume a normal distribution, while 
 this data will be bounded between 0 and 1.  The scientist I'm working with 
 feels it's important to make fair comparisons, any weight loss must account 
 for the baseline weight.  A logistic transformation seems appropriate, but 
 that term also didn't yield hits I recognized as useful.
 
 Loss of weight --- compare treatments:
 Treatment A:  1 - Final weight / Initial weight
 Treatment B:  1 - Final weight / Initial weight
 
 This appears to be a situation that would be common, but I'm not framing it 
 in a way that matches an R package.  Any guidance is appreciated.
 
 Regards, Paul


If you and the scientist are in a position of being open to better options of 
analyzing change from baseline data, I would recommend that you both read the 
following two papers:

 
Statistics notes: analysing controlled trials with baseline and follow up 
measurements. 
Vickers AJ, Altman DG.
BMJ 2001;323:1123–4.
http://www.bmj.com/cgi/content/full/323/7321/1123
http://www.ncbi.nlm.nih.gov/pmc/articles/PMC1121605/pdf/1123.pdf

 
The use of percentage change from baseline as an outcome in a controlled trial 
is statistically inefficient: a simulation study. 
Vickers AJ.
BMC Med Res Methodol 2001;1:6.
http://www.biomedcentral.com/1471-2288/1/6
http://www.biomedcentral.com/content/pdf/1471-2288-1-6.pdf


and review an additional web site:

  http://biostat.mc.vanderbilt.edu/wiki/Main/MeasureChange


Once you are hopefully in a position of adopting a regression based approach 
(eg. FinalWeight ~ BaseWeight + Treatment), there are various options for 
calculating sample sizes.  The key advantage of this approach is that you get 
the baseline adjusted between-group comparison (the regression beta coefficient 
and confidence intervals for Treatment) which is the key outcome of interest in 
comparing treatments in a parallel design.

The easiest, albeit conservative approach for sample size, is to use 
power.t.test() on your assumptions of the inter-group delta for actual weight 
change (not percent change), the std dev for actual change, desired power and 
target alpha. 

I am not aware off-hand of any power/sample size functions in R for regular 
linear regression, though they may exist. There are third party programs that 
do provide that functionality. 

If you are willing to code and experiment a bit, you could construct a monte 
carlo simulation with a linear model, using data generated with rnorm() based 
upon reasonable assumptions about the distribution of your data in each group 
for the baseline and final values.

Once you get your actual data collected and ready for analysis, you will also 
need to test for a baseline*treatment interaction (FinalWeight ~ BaseWeight * 
Treatment), which can make the interpretation of treatment effects more 
complicated, since the treatment effect will be conditional upon the baseline 
weight, rather than being able to report a mean treatment effect.

HTH,

Marc Schwartz

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Re: [R] Optim() Help, Unusual Error

2010-03-23 Thread Nikhil Kaza

I cannot replicate the error.

The following seem to work.

Y - runif(100)
comp - matrix(runif(6500),100,65)
par - rep(.5, 28)
optim.results - optim(par, fn=objective.function, method=Nelder- 
Mead,comp=comp, Y=Y, n=100) # Not sure why you are selecting the  
columns in the comp. That is probably the error


Nikhil

On Mar 23, 2010, at 3:38 PM, ApproxGaussian wrote:



I apologize, the c is in the original coding; I merely misprinted  
(copy and

paste).

I have edited the orginal post to reflect this.
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Re: [R] Setting breaks to data more appropriately

2010-03-23 Thread David Winsemius


On Mar 23, 2010, at 5:23 PM, ROLL Josh F wrote:


David
Thanks you for the guidance.  I am looking to drive the data into  
the intervals.  Problem now is that I have a few 0 values that are  
returning as NA (e.g - (0.1,0.2] (0.1,0.2] (0.1,0.2] NA   
(0,0.1]  )
This is causing issues when I try and use the brks to inform a  
clorepleth map.  I tried setting all na's to 0 but because the  
dataset is in factor form (I guess this is why) it wont allow me to  
do so. Thoughts about how to handle the zero values?  Thanks

JR



?cut

By default include.lowest is set to FALSE. Setting it to TRUE should  
cure your missing zeroes problem. (My own feeling is that was a very  
poor choice of defaults but I guess it is cast in stone now.)


You don't say how you tried setting NA's to zero (and doing so is not  
a good idea if there are real zeroes in the data), but the is.na and  
is.na- functions are often needed for that purpose.


--
David.

-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Monday, March 22, 2010 12:46 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] Setting breaks to data more appropriately


On Mar 22, 2010, at 1:49 PM, LCOG1 wrote:



Basic question.  For the below data, i would like to but each of the
values in a bin that represents their value.  So the below would
hopefully put .1 in the 0-.1 bin, .2 in the .11-.2 bin and so forth.
The outlying values would then be put into and outer category
representing everything

1.  Im

using the breaks to inform some code for making a clorepleth map that
represents probabilities, which in some cases IS greater than 1


... not if it's a quantile or a probability.


and i need
to identify those better.


Define better.


As my code stands now, my real data is put put into this form when
brks is called:

  0%10%20%30%40%
50%60%
0. 0.05054675 0.07787235 0.11235238 0.14424786 0.18089360
0.21475990
 70%80%90%   100%
0.26309899 0.30807771 0.39478573 0.67573483.

But what i want is for the values to be placed in bins corresponding
to their value(0-.1, .11-.2, .21-.3 etc)

Pct.SFD-c(.1,.2,.3,.4,.5,.6,.7,.8,.9,1,2,3)
brks - quantile(Pct.SFD, )

I think this is clear.


It's not. You need to decide whether you want the breaking to be  
driven by you or by the data. If you are doing the driving then use


cut(object, breaks=c(seq(0,1, by=0.1), Inf) , right=TRUE)

If the data is doing the driving then:

cut(object, breaks=quantile(object, probs= seq(0,1,1/10 ) ) ,
right=TRUE)

--
David.


Thanks
--
View this message in context:
http://n4.nabble.com/Setting-breaks-to-data-more-appropriately- 
tp16780

19p1678019.html Sent from the R help mailing list archive at
Nabble.com.

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David Winsemius, MD
West Hartford, CT

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[R] Bold greek letters using plotmath

2010-03-23 Thread Jim Price

I'm trying to annotate some graphics using plotmath and finding out that the
code I'm using isn't bolding the greek letters - it bolds the rest (once I
adjusted the numerics to characters), it's just failing on the greek
characters.

Any suggestions welcomed.

Jim Price.
Cardiome Pharma Corp.


Test code:


plot(1:5, type = 'n')


# The not bold version
text(2, 2:4, cex = 2, labels = do.call(expression, 
unlist(list('Placebo', lapply(c(3, 6), function(.x) substitute(.x ~~ mu 
* g
/ kg / hr, list(.x = .x, recur = F)))


# The bold version - note that the greek letter doesn't change
text(4, 2:4, cex = 2, labels = do.call(expression, 
unlist(list(substitute(bold(Placebo)), lapply(as.character(c(3, 6)),
function(.x) substitute(bold(.x ~~ mu * g / kg / hr), list(.x = .x,
recur = F)))






 sessionInfo()
R version 2.10.0 (2009-10-26) 
i386-pc-mingw32 

locale:
[1] LC_COLLATE=English_United States.1252  LC_CTYPE=English_United
States.1252   
[3] LC_MONETARY=English_United States.1252 LC_NUMERIC=C 
 
[5] LC_TIME=English_United States.1252

attached base packages:
[1] graphics  grDevices utils datasets  methods   stats base 

other attached packages:
[1] foreign_0.8-38 latticeExtra_0.6-1 RColorBrewer_1.0-2 lattice_0.17-26   

loaded via a namespace (and not attached):
[1] grid_2.10.0  tools_2.10.0


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[R] Diffusion entropy analysis

2010-03-23 Thread Andrew Rominger
Hello,

Does anyone know of an R implementation of diffusion entropy analysis (DEA)
as proposed by Scafetta dn Grigolini (2002)?  I was unable to find any
existing functions, so I attempted to write up my own, but cannot reproduce
known results, so obviously I'm doing something wrong.

If there does not appear to be any existing script, I'll send along my
attempts for your critique.  I'd also be happy for any leads on scripts
written in languages other than R.

Thanks very much in advance--
Andy Rominger

Scafetta N, and Grigolini P (2002) Scaling detection in time series:
Diffusion entropy analysis.  Phys. Rev. E 66:1:10.

[[alternative HTML version deleted]]

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Re: [R] Saving tab/csv delimited data with NaN's

2010-03-23 Thread Sharpie


shankar-17 wrote:
 
 Hello,
 I am working multiple simulated data sets with missing values, I would  
 like to store these data sets in either tab delimited format for .csv  
 format with missing values marked as NaN's instead of NA's.
 
 I read the import/export document which mentions that write.table  
 command converts NaN's to NA. Is there any other way I can store the  
 NaN's. I tried the write syntax it gives me error codes.
 Each data files are of dimensions 1000 x 21 .
 
 I would appreciate any help in this regard.
 
 Many thanks
 

 foo - matrix(0,nrow=3,ncol=3)
 foo
 [,1] [,2] [,3]
[1,]000
[2,]000
[3,]000

 foo[3,3] - NA
 foo
 [,1] [,2] [,3]
[1,]000
[2,]000
[3,]00   NA

 write.csv( foo, file='tst.csv', na = NaN, row.names = F )
 readLines( 'tst.csv' )
[1] \V1\,\V2\,\V3\ 0,0,00,0,0
[4] 0,0,NaN

Seems to work fine for me.  If you post a reproducible example, we could
probably figure out why it is not working for you.

-Charlie

-
Charlie Sharpsteen
Undergraduate-- Environmental Resources Engineering
Humboldt State University
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[R] Plot ``freezes''.

2010-03-23 Thread Rolf Turner

In an elderly version of ``plotSymbols'' (now in the cwhmisc package) that
I had lying around, there was the example

plot(1:10,xlab=\374)

which the comments said would give a u-umlaut as the x-axis label.

When I execute this plot

(a) I get no x-axis label at all, and

(b) the plot ``freezes'' in that further plotting commands
(e.g. plot(runif(42))) produce no results.  The plot window (X11)
remains as it was after the ``plot(1:10,xlab=\374)'' command.
No error message is given, but no new plot is produced.

If I do dev.off(), then normal plotting recommences.  Can anyone explain
to me what is going on here?  My session info is given below.  I run R
from the command line, from a terminal window.

cheers,

Rolf Turner

 sessionInfo()
R version 2.10.1 (2009-12-14) 
i386-apple-darwin8.11.1 

locale:
[1] en_NZ.UTF-8/en_NZ.UTF-8/C/C/en_NZ.UTF-8/en_NZ.UTF-8

attached base packages:
[1] datasets  utils stats graphics  grDevices methods   base 

other attached packages:
[1] misc_0.0-12fortunes_1.3-7 MASS_7.3-4




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