[R] qq-plot in R

2014-11-11 Thread Ron Michael
Hi,

I am some questions on qq-plot offered by R. Let say I have following qq-plot:

 qqplot(rt(300, df = 5), rt(300, df = 5))
However I want to get more controls to define the range of x-axis as well as 
y-axis. For example I want to define that, x-axis range will be -10 to 10 and 
y-axis range will be 0-10 (just an example on what I am looking for). 
Additionally I want to get the entire list of (x,y) coordinates for all plotted 
points.
Basically one my goals is to draw multiple different qq-plots onto same 
plot-window, with my optimally chosen range of x  y axes. 
Can somebody here guide me how to achieve that?
Appreciate your pointers and help.
Thanks,
[[alternative HTML version deleted]]

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[R] A basic statistics question

2014-08-12 Thread Ron Michael
Hi,

I would need to get a clarification on a quite fundamental statistics property, 
hope expeRts here would not mind if I post that here.

I leant that variance-covariance matrix of the standardized data is equal to 
the correlation matrix for the unstandardized data. So I used following data.

Data - structure(c(7L, 5L, 9L, 7L, 8L, 7L, 6L, 6L, 5L, 7L, 8L, 6L, 7L,  7L, 
6L, 7L, 7L, 6L, 8L, 6L, 7L, 7L, 7L, 8L, 7L, 9L, 8L, 7L, 7L,  0L, 10L, 10L, 10L, 
7L, 6L, 8L, 5L, 5L, 6L, 6L, 7L, 11L, 9L, 10L,  0L, 13L, 13L, 10L, 7L, 7L, 7L, 
10L, 7L, 5L, 8L, 7L, 10L, 10L,  10L, 6L, 7L, 6L, 6L, 8L, 8L, 7L, 7L, 7L, 7L, 
8L, 7L, 8L, 6L,  6L, 8L, 7L, 4L, 7L, 7L, 10L, 10L, 6L, 7L, 7L, 12L, 12L, 8L, 
5L,  5L, 5L, 5L, 6L, 6L, 6L, 6L, 6L, 7L, 7L, 5L, 4L, 5L, 5L, 5L, 6L,  7L, 5L, 
7L, 5L, 7L, 7L, 7L, 7L, 8L, 7L, 6L, 7L, 7L, 6L, 7L, 7L,  6L, 4L, 4L, 6L, 6L, 
7L, 8L, 7L, 11L, 10L, 8L, 7L, 6L, 6L, 11L,  5L, 4L, 6L, 6L, 6L, 7L, 8L, 7L, 
12L, 4L, 4L, 2L, 5L, 6L, 7L,  6L, 6L, 5L, 6L, 5L, 7L, 7L, 7L, 6L, 5L, 6L, 6L, 
5L, 5L, 6L, 6L,  4L, 4L, 5L, 10L, 10L, 7L, 7L, 6L, 4L, 6L, 10L, 7L, 4L, 6L, 6L, 
 6L, 8L, 8L, 8L, 7L, 8L, 9L, 10L, 7L, 6L, 6L, 8L, 6L, 8L, 3L,  3L, 4L, 5L, 5L, 
6L, 5L, 5L, 6L, 4L, 8L, 7L, 3L, 5L, 6L, 9L, 8L,  9L, 10L, 8L, 9L, 8L, 9L, 8L, 
8L, 9L, 11L, 10L, 9L, 9L, 13L,
 13L,  10L, 7L, 7L, 7L, 9L, 8L, 7L, 6L, 10L, 8L, 7L, 8L, 8L, 3L, 4L,  3L, 7L, 
6L, 6L, 6L, 6L, 5L, 6L, 6L, 6L, 2L, 5L, 7L, 9L, 8L, 9L,  10L, 8L, 8L, 9L, 9L, 
11L, 11L, 11L, 10L, 9L, 9L, 11L, 2L, 3L,  2L, 2L, 2L, 1L, 4L, 4L, 2L, 2L, 1L, 
1L, 1L, 3L, 3L, 4L, 6L, 4L,  5L, 2L, 3L, 5L, 4L, 4L, 2L, 4L, 4L, 5L, 4L, 2L, 
7L, 3L, 3L, 10L,  13L, 11L, 9L, 9L, 7L, 8L, 9L, 6L, 7L, 6L, 5L, 3L, 13L, 3L, 
3L,  0L, 1L, 4L, 5L, 3L, 3L, 0L, 2L, 20L, 3L, 2L, 6L, 5L, 5L, 5L,  2L, 2L, 5L, 
5L, 5L, 4L, 3L, 4L, 4L, 3L, 4L, 10L, 10L, 9L, 8L,  4L, 4L, 8L, 7L, 10L, 3L, 1L, 
9L, 5L, 11L, 9L), .Dim = c(45L,  8L), .Dimnames = list(NULL, c(V1, V7, 
V13, V19, V25,  V31, V37, V43))) 


Data_Normalized - apply(Data, 2, function(x) return((x - mean(x))/sd(x))) 

(t(Data_Normalized) %*% Data_Normalized)/dim(Data_Normalized)[1]



Point is that I am not getting exact CORR matrix. Can somebody point me what I 
am missing here?

Thanks for your pointer. 

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[R] Possible pair of 2 binary vectors

2014-08-09 Thread Ron Michael
Hi,

Let say I have 2 binary vectors of length 'd', therefore both these vectors can 
take only 0-1 values. Now I want to simulate all possible pairs of them. 
Theoretically there will be 4^d possible pairs.

Is there any R function to directly simulate them?

Thanks for your help.

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[R] A question on graphical representation

2014-03-01 Thread Ron Michael
Hi,

Let say I Have following data:

 Info - structure(list(Person = structure(1:6, .Label = c(A, B, C, 
+ D, E, F), class = factor), Attr1 = c(0.52, 0.14, 0.63, 
+ 0.43, 0.89, 18.46), Attr2 = c(0.06, 3.35, 0.62, 1.42, 1.96, 8.38
+ )), .Names = c(Person, Attr1, Attr2), row.names = c(NA, 
+ -6L), class = data.frame)
 Info
  Person Attr1 Attr2
1  A  0.52  0.06
2  B  0.14  3.35
3  C  0.63  0.62
4  D  0.43  1.42
5  E  0.89  1.96
6  F 18.46  8.38
 Diff - Info[, 'Attr1'] - Info[, 'Attr2']
 Diff
[1]  0.46 -3.21  0.01 -0.99 -1.07 10.08
 Overall_Diff - sum(Diff)
 Overall_Diff
[1] 5.28



Now we see that the overall difference between attribute-1 and attribute-2 for 
persons A-F is 5.28. Now I was asked this question: tell me out of that overall 
difference, how much is attributed to person A, person B, person F? In case 
the 'Diff' variable all have positive values, I probably consider making a 
pie-chart. However this is not possible (probably) in this present case, 
because some values are negative and some values are positive.

So my question is how to build a robust graphical representation to answer this 
question?

Your help will be highly appreciated.

Thanks for your pointer.

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[R] A calculation in data.frame

2014-01-07 Thread Ron Michael
Hi,

I have to perform some formula driven calculation in a data.frame (as defined 
below). Let say I have following DF:

 DF - data.frame(A1 = c('a', 'a', 'a', 'b', 'b', 'b', 'c', 'c', 'c'), A2 = 
 c('m', 'n', 'p', 'm', 'n', 'p', 'm', 'n', 'p'), A3 = c(1,2,3,4,5,6,7,8,9))
 DF
  A1 A2 A3
1  a  m  1
2  a  n  2
3  a  p  3
4  b  m  4
5  b  n  5
6  b  p  6
7  c  m  7
8  c  n  8
9  c  p  9


Now let say, user gives one formula which will be applied on the elements of A1 
column. Let say the formula looks like:

z = a + 2*b + c (infact the formula will be arbitrary like z = f(a, b, c))

Once such formula is given, the result will be like (for the columns A1, A2, A3 
respectively)

z m 16
z n 20
z p 24

the last column comes from the fact that 1 + 2*4 + 7 = 16, 2 + 2*5 + 8 = 20, 3 
+ 2*6 + 9 = 24

Given that the formula wil be user defined, and to be applied on some 
data.frame like DF, I am seeking some automated way to accomplice the task for 
really big DF of previous kind and fairly complex formula.

Can somebody suggest me for efficient way to perform this task in R?

Really appreciate your help.

Thanks, 

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[R] Extract part of string

2014-01-05 Thread Ron Michael
Hi,

I am struggling to extract a part of string using regular expression in R.

Let say, the string to be extracted is 'ron' from the expression 'my name is 
ron'. So I tried following:

 gsub([^(ron)], , 'my name is ron')
[1] nron


I was expecting to get 'ron', which is not the case.

Could someone please guide me what will be the right way for that?

Thanks for your help.

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[R] R function to locate Excel sheet?

2013-10-29 Thread Ron Michael
Hi,

I am looking for some R function which will tell me, whether a particular sheet 
in an Excel file (.xlsx/.xls) exists or not. I just need to get some TRUE/FALSE 
type of answer.

Can somebody give me any pointer if such function exists or not?

Thanks and regards,

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[R] Can not read Excel file correctly

2013-10-29 Thread Ron Michael
Hi,

I need to read an Excel file which can be available in following link:
http://www45.zippyshare.com/v/43626889/file.html

Now I wanted to read the 1st sheet of this Excel file. Below are my code so far 
(I saved that file in 'F:' drive):

 library(XLConnect)
Loading required package: rJava
XLConnect 0.2-5 by Mirai Solutions GmbH
http://www.mirai-solutions.com ,
http://miraisolutions.wordpress.com
 readWorksheetFromFile(f:/Dat1.xlsx, sheet = 1)
        Col1             Col2       Col3   Col4
1       NA               NA 2013-05-01   NA
2       NA               NA       NA   NA
3 1930-01-01               NA       NA   NA
4       NA 3127312736128730       NA   NA
5       NA               NA       NA   NA
6       NA               NA       NA SAsSag


What I saw that, the element in A1 cell is missing. Also the data in C1  A4 
are read in different format. In Excel file, it is Month-Year format, however 
what I see is Year-Month-Day format.

I have many such files, therefore I do not want to convert them to csv (or any 
other). Doing so will be cumbersome.

Can somebody here help me how to read that file in proper format?

Thanks for your time.

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[R] Finding solution for non-linear equations

2013-10-15 Thread Ron Michael
Hi,

I need to solve following simultaneous equations for A, B, Y1, Y2:

B * Phi(Y1 - A) + (1-B) * Phi(Y1 + A) = 0.05
B * Phi(Y2 - A) + (1-B) * Phi(Y2 + A) = 0.01

Y1 = -1.65
Y2 = -2.33

0 = B =1 

Phi is CDF for standard normal

If there is no unique solution, then I should be able to get some feassible 
solution(s)

Is there any way that using R I can achieve that?

Thanks for your time

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[R] Downloading data directly from internet

2013-09-15 Thread Ron Michael
Hi,
 
I need to download data from this site:
http://www.cmegroup.com/trading/agricultural/grain-and-oilseed/corn_quotes_globex.html
 
 
I tried with following set of codes:
 
 
library(RCurl) 
library(XML) 
 
aa - 
getURL(http://www.cmegroup.com/trading/agricultural/grain-and-oilseed/corn_quotes_globex.html;)
readHTMLTable(aa)
 
However not getting the required data.
 
Can someone please help me to point out how I can get that data?
 
Your help will be highly appreciated.
 
Thank you very much.

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[R] ifelse() applied on function

2013-08-11 Thread Ron Michael
Hi,
 
How can I apply ifelse function to chose appropriate function?
 
My goal is user will chose lapply() function if ChooseFn = T otherwise to 
chose sfLapply() from snowfall package.
 
I am basically trying to avoid repeatation to write all internal steps, if user 
choses lapply or sfLapply. For example, I am wondering if there is any 
posibility to write something like:
 
ifelse(ChooseFn, lapply, sfLapply)(MyList, function(x) {
 
...
..
return())
 
Really appreciate if someone helps me out.

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[R] Converting string to date

2013-08-04 Thread Ron Michael
Hi,
 
I want to convert following string to a Date format (mm/dd/):
 
MyString - c(Sun Sep 01 00:00:00 EDT 2013, Sun Dec 01 00:00:00 EST 2013)
 
Can somebody point me if it is possible to do that?
 
Thank you.

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Re: [R] How to download this data?

2013-08-03 Thread Ron Michael
Hello Duncan,
 
Thank you very much for your pointer.
 
However when I tried to run your code, I got following error:
  rawOrig = 
getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;)
 
Error in function (type, msg, asError = TRUE)  : 
  SSL certificate problem, verify that the CA cert is OK. Details:
error:14090086:SSL routines:SSL3_GET_SERVER_CERTIFICATE:certificate verify 
failed

Can someone help me to understand what could be the cause of this error?
 
Thank you.


- Original Message -
From: Duncan Temple Lang dtemplel...@ucdavis.edu
To: r-help@r-project.org
Cc: 
Sent: Saturday, 3 August 2013 4:33 AM
Subject: Re: [R] How to download this data?


That URL is an HTTPS (secure HTTP), not an HTTP.
The XML parser cannot retrieve the file.
Instead, use the RCurl package to get the file.

However, it is more complicated than that. If
you look at source of the HTML page in a browser,
you'll see a jsessionid and that is a session identifier.

The following retrieves the content of your URL and then
parses it and extracts the value of the jsessionid.
Then we create the full URL to the actual data page (which is actually in the 
HTML
content but in JavaScript code)

library(RCurl)
library(XML)

rawOrig = 
getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;)
rawDoc = htmlParse(rawOrig)
tmp = getNodeSet(rawDoc, //@href[contains(.,\040'jsessionid=')])[[1]]
jsession = gsub(.*jsessionid=([^?]+)?.*, \\1, tmp)

u = 
sprintf(https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;,
 jsession)

doc = htmlParse(getURLContent(u))
tbls = readHTMLTable(doc)
data = tbls[[1]]

dim(data)


I did this quickly so it may not be the best way or completely robust, but 
hopefully
it gets the point across and does get the data.

  D.

On 8/2/13 2:42 PM, Ron Michael wrote:
 Hi all,
  
 I need to download the data from this web page:
  
 https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry
  
 I used the function readHTMLTable() from package XML, however could not 
 download that.
  
 Can somebody help me how to get the data onto my R window?
  
 Thank you.
 
 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


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Re: [R] How to download this data?

2013-08-03 Thread Ron Michael
In the mean time I have this problem sorted out, hopefully I did it correctly. 
I have modified the line of your code as:
 
rawOrig = 
getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;,
 ssl.verifypeer = FALSE)
 
However next I faced with another problem to executing:
  u = sprintf(a 
href=https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;,
 jsession) 
Error: unexpected symbol in u = sprintf(a href=https

Can you or someone else help me to get out of this error?
 
Also, my another question is: from where you got the expression:
a 
href=https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;
 
I really appreciate if someone help me to understand that.
 
Thank you.


- Original Message -
From: Ron Michael ron_michae...@yahoo.com
To: Duncan Temple Lang dtemplel...@ucdavis.edu; r-help@r-project.org 
r-help@r-project.org
Cc: 
Sent: Saturday, 3 August 2013 12:58 PM
Subject: Re: [R] How to download this data?

Hello Duncan,
 
Thank you very much for your pointer.
 
However when I tried to run your code, I got following error:
  rawOrig = 
getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;)
 
Error in function (type, msg, asError = TRUE)  : 
  SSL certificate problem, verify that the CA cert is OK. Details:
error:14090086:SSL routines:SSL3_GET_SERVER_CERTIFICATE:certificate verify 
failed

Can someone help me to understand what could be the cause of this error?
 
Thank you.


- Original Message -
From: Duncan Temple Lang dtemplel...@ucdavis.edu
To: r-help@r-project.org
Cc: 
Sent: Saturday, 3 August 2013 4:33 AM
Subject: Re: [R] How to download this data?


That URL is an HTTPS (secure HTTP), not an HTTP.
The XML parser cannot retrieve the file.
Instead, use the RCurl package to get the file.

However, it is more complicated than that. If
you look at source of the HTML page in a browser,
you'll see a jsessionid and that is a session identifier.

The following retrieves the content of your URL and then
parses it and extracts the value of the jsessionid.
Then we create the full URL to the actual data page (which is actually in the 
HTML
content but in JavaScript code)

library(RCurl)
library(XML)

rawOrig = 
getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;)
rawDoc = htmlParse(rawOrig)
tmp = getNodeSet(rawDoc, //@href[contains(.,\040'jsessionid=')])[[1]]
jsession = gsub(.*jsessionid=([^?]+)?.*, \\1, tmp)

u = 
sprintf(https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;,
 jsession)

doc = htmlParse(getURLContent(u))
tbls = readHTMLTable(doc)
data = tbls[[1]]

dim(data)


I did this quickly so it may not be the best way or completely robust, but 
hopefully
it gets the point across and does get the data.

  D.

On 8/2/13 2:42 PM, Ron Michael wrote:
 Hi all,
  
 I need to download the data from this web page:
  
 https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry
  
 I used the function readHTMLTable() from package XML, however could not 
 download that.
  
 Can somebody help me how to get the data onto my R window?
  
 Thank you.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


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Re: [R] How to download this data?

2013-08-03 Thread Ron Michael
Hi Duncan,

Thank you very much for your prompt help. Now all worked very smoothly.

Thank you.


- Original Message -
From: Duncan Temple Lang dtemplel...@ucdavis.edu
To: Ron Michael ron_michae...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Saturday, 3 August 2013 7:43 PM
Subject: Re: [R] How to download this data?

Hi Ron

  Yes, you can use ssl.verifypeer = FALSE.  Or alternatively, you can use also 
use

  getURLContent(,  cainfo = system.file(CurlSSL, cacert.pem, 
package = RCurl))

to specify where libcurl can find the certificates to verify the SSL signature.


The error you are encountering appears to becoming from a garbled R expression. 
This may have
arisen as a result of an HTML mailer adding the a href= into the 
expression
where it found an https://...

What we want to do is end up with a string of the form

  
https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=adasdasdad?expiryData=specId=219

We have to substitute the text adasdasdad which  we assigned to jsession in a 
previous command.
So, take the literal text

  c(https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=;,
    jsession,
    ?expiryData=specId=219)

and combine it into a single string with paste0.

We need the literal strings as they appear when you view the mail for R to make 
sense of them, not what the mailer adds.


As to where I found this, it is in the source of the original HTML page in 
rawDoc

scripts = getNodeSet(rawDoc, //body//script)
scripts[[ length(scripts) ]]

and look at the text, specifically the app.urls and its 'expiry' field.


script type=text/javascript![CDATA[

        var app = {};

        app.isOption = false;

        app.urls = {

            
'spec':'/productguide/ProductSpec.shtml;jsessionid=22E9BE9DB19FC6F3446C9ED4AFF2BE3F?details=specId=219',

            
'data':'/productguide/ProductSpec.shtml;jsessionid=22E9BE9DB19FC6F3446C9ED4AFF2BE3F?data=specId=219',


'confirm':'/reports/dealreports/getSampleConfirm.do;jsessionid=22E9BE9DB19FC6F3446C9ED4AFF2BE3F?hubId=403productId=254',

            
'reports':'/productguide/ProductSpec.shtml;jsessionid=22E9BE9DB19FC6F3446C9ED4AFF2BE3F?reports=specId=219',


'expiry':'/productguide/ProductSpec.shtml;jsessionid=22E9BE9DB19FC6F3446C9ED4AFF2BE3F?expiryDates=specId=219'

        };

        app.Router = Backbone.Router.extend({

            routes:{

                spec:spec,

                data:data,

                confirm:confirm,


On 8/3/13 1:05 AM, Ron Michael wrote:
 In the mean time I have this problem sorted out, hopefully I did it 
 correctly. I have modified the line of your code as:
  
 rawOrig = 
 getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;,
  ssl.verifypeer = FALSE)
  
 However next I faced with another problem to executing:
   u = sprintf(a 
href=https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;,
 jsession) 
 Error: unexpected symbol in u = sprintf(a href=https
 
 Can you or someone else help me to get out of this error?
  
 Also, my another question is: from where you got the expression:
 a 
 href=https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;https://www.theice.com/productguide/ProductSpec.shtml;jsessionid=%s?expiryDates=specId=219;
  
 I really appreciate if someone help me to understand that.
  
 Thank you.
 
 
 - Original Message -
 From: Ron Michael ron_michae...@yahoo.com
 To: Duncan Temple Lang dtemplel...@ucdavis.edu; r-help@r-project.org 
 r-help@r-project.org
 Cc: 
 Sent: Saturday, 3 August 2013 12:58 PM
 Subject: Re: [R] How to download this data?
 
 Hello Duncan,
  
 Thank you very much for your pointer.
  
 However when I tried to run your code, I got following error:
   rawOrig = 
getURLContent(https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry;)
 
 Error in function (type, msg, asError = TRUE)  : 
  SSL certificate problem, verify that the CA cert is OK. Details:
 error:14090086:SSL routines:SSL3_GET_SERVER_CERTIFICATE:certificate verify 
 failed
 
 Can someone help me to understand what could be the cause of this error?
  
 Thank you.
 
 
 - Original Message -
 From: Duncan Temple Lang dtemplel...@ucdavis.edu
 To: r-help@r-project.org
 Cc: 
 Sent: Saturday, 3 August 2013 4:33 AM
 Subject: Re: [R] How to download this data?
 
 
 That URL is an HTTPS (secure HTTP), not an HTTP.
 The XML parser cannot retrieve the file.
 Instead, use the RCurl package to get the file.
 
 However, it is more complicated than that. If
 you look at source of the HTML page in a browser,
 you'll see a jsessionid and that is a session identifier.
 
 The following retrieves the content of your URL and then
 parses it and extracts the value of the jsessionid.
 Then we create the full URL to the actual data page (which

[R] How to download this data?

2013-08-02 Thread Ron Michael
Hi all,
 
I need to download the data from this web page:
 
https://www.theice.com/productguide/ProductSpec.shtml?specId=219#expiry
 
I used the function readHTMLTable() from package XML, however could not 
download that.
 
Can somebody help me how to get the data onto my R window?
 
Thank you.

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[R] Need help on window() function of the 'zoo' package

2013-06-08 Thread Ron Michael
Hi,
 
I observed that if I use window() function available with the 'zoo' package to 
extract a portion of my times series and if that time series data is stored in 
some 'zoo' object with only 1 column, then the resulting zoo object is becoming 
vector.
 
Here is my observation:
 
 library(zoo)
 Dat - matrix(1:3, nc = 1)
 Dat
 [,1]
[1,]    1
[2,]    2
[3,]    3
 Dat_zoo - zooreg(Dat, start = as.Date(2001-01-01), frequency = 1)
 Dat_zoo
    
2001-01-01 1
2001-01-02 2
2001-01-03 3
 window(Dat_zoo, start = as.Date(2001-01-02))   ### why it is becoming 
 vector? I want to retain it as matrix only
2001-01-02 2001-01-03 
 2  3 
 
Here you can see that, originally my 'Dat_zoo ' object was basically a matrix. 
However once I use window() function, it became vector.
 
Is there any possibility to retain the shape of the original object, 
particularly if that object is matrix with 1 column?
 
Thank you very much for your help.
[[alternative HTML version deleted]]

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[R] Need to download data from internet

2013-06-01 Thread Ron Michael
Hi,
 
I need to dowload a time series with arbitray start date and end date, from 
this site:
 
http://www.mcxindia.com/sitepages/SpotMarketHistory.aspx?sLinkPage=Y
 
While I can download my required data manually, I would like R to do that for 
me. I have tried 'quandl' package, however could not find any such data 
available to download. Can somebody point me some R function which can help me 
to download that data automatically?
 
Regards,
[[alternative HTML version deleted]]

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[R] Working with date

2012-12-26 Thread Ron Michael
Hi,

Let say I have a date variable:

  asd - as.Date(2012-01-03)
 asd
[1] 2012-01-03



Now, I want to express this date like 3/1/2012.

can somebody help me how to achieve that?

Thanks,

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Re: [R] Working with date

2012-12-26 Thread Ron Michael
Thanks Jim for your reply.

However I want 3/1/2012 not 03/01/2012

Any idea ?

Thanks


- Original Message -
From: jim holtman jholt...@gmail.com
To: Ron Michael ron_michae...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Thursday, 27 December 2012 1:01 AM
Subject: Re: [R] Working with date

forgot you were asking for mdy format

 # interchange day and month
 format(asd, format = '%d/%m/%Y')
[1] 03/01/2012



On Wed, Dec 26, 2012 at 2:14 PM, jim holtman jholt...@gmail.com wrote:
 try this:

 asd - as.Date(2012-01-03)
 asd
 [1] 2012-01-03
 format(asd, format = '%m/%d/%Y')
 [1] 01/03/2012




 On Wed, Dec 26, 2012 at 1:31 PM, Ron Michael ron_michae...@yahoo.com wrote:
 asd - as.Date(2012-01-03)



 --
 Jim Holtman
 Data Munger Guru

 What is the problem that you are trying to solve?
 Tell me what you want to do, not how you want to do it.



-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.


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[R] Wriritng to a CSV file

2012-02-08 Thread Ron Michael
Dear all, let say I want to write a vector to a CSV file. So I can have 
following syntax:
 
write.csv(rnorm(10), dat.csv)
 
Now I want to add one more column into that existing file. If I use the same 
code then existing file will be destroyed. Is there any functionality to add 
without destroying the existing file? I have tries with 'append = TRUE' however 
it is not working!
 
Any suggestion will be highly appreciated.

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Re: [R] Wriritng to a CSV file

2012-02-08 Thread Ron Michael
Okay, so I understood that appending can only happen row-wise. Therefore I 
tried with following code:
 
 write.csv(matrix(1:5, 1), dat.csv)
 write.csv(matrix(1:5, 1), dat.csv, append = TRUE)
Warning message:
In write.csv(matrix(1:5, 1), dat.csv, append = TRUE) :
  attempt to set 'append' ignored

It is destroying my previous file. Where I have done wrong?
 
Thanks,


- Original Message -
From: Uwe Ligges lig...@statistik.tu-dortmund.de
To: Ron Michael ron_michae...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Thursday, 9 February 2012 1:07 AM
Subject: Re: [R] Wriritng to a CSV file



On 08.02.2012 20:14, Ron Michael wrote:
 Dear all, let say I want to write a vector to a CSV file. So I can have 
 following syntax:

 write.csv(rnorm(10), dat.csv)

 Now I want to add one more column into that existing file. If I use the same 
 code then existing file will be destroyed. Is there any functionality to add 
 without destroying the existing file? I have tries with 'append = TRUE' 
 however it is not working!

 Any suggestion will be highly appreciated.

Since these text files are written line by line, you cannot add a column 
afterwards, you can just append rows.

Hence read the first column and write a two column data.frame afterwards.

Uwe Ligges


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[R] Drawing sample

2012-01-29 Thread Ron Michael
Dear all, here I need to draw all possible samples of size 2, from a 
population, which is characterized by c(1,4,56, 3). Sampling will be done with 
replacement. Is there any direct R function to faciliate this darwing?
 
Thanks for your help

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[R] Looking for a C function

2011-11-22 Thread Ron Michael
Dear all, I was looking for the C program found within approxfun() function. I 
already have a list of available C programs which are being used with R here, 
https://svn.r-project.org/R/trunk/src/main/. However this list does not contain 
above C function. Can somebody help me on where to find that?
 
Thanks,

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[R] A problem with chol() function

2011-10-23 Thread Ron Michael
I think I am missing something with the chol() function. Here is my calculation:
 
 mat
 [,1] [,2] [,3] [,4] [,5]
[1,]    1    3    0    0    0
[2,]    0    1    0    0    0
[3,]    0    0    1    0    0
[4,]    0    0    0    1    0
[5,]    0    0    0    0    1
 eigen(mat)
$values
[1] 1 1 1 1 1
$vectors
 [,1]  [,2] [,3] [,4] [,5]
[1,]    1 -1.00e+00    0    0    0
[2,]    0  7.401487e-17    0    0    0
[3,]    0  0.00e+00    1    0    0
[4,]    0  0.00e+00    0    1    0
[5,]    0  0.00e+00    0    0    1
 chol(mat)
Error in chol.default(mat) : 
  the leading minor of order 2 is not positive definite

As per the eigen values my matrix is PD (as all eigen values are positive). 
Then why still I can not get Cholesky factor of my matrix? Can somebody point 
mw where I am missing?
 
Thanks and regards,

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[R] Question on RNG

2011-08-05 Thread Ron Michael
Hi all, I have happened to work on MS .NET for sometime now, and I found that 
this language offers RNG what is called as Donald E. Knuth's subtractive random 
number generator algorithm (found here: 
http://msdn.microsoft.com/en-us/library/system.random.aspx#Y12).
 
Here I was wondering whether R also have same RNG in it's inventory, so looked 
at ?set.seed. There I found 2 related RNGs namely 'Knuth-TAOCP-2002', 
'Knuth-TAOCP'. Can somebody guide me what is the most related RNG with .Net's?
 
I also want to have R to draw random number from that RNG, given I set a seed. 
My goal is to have same set of random numbers in .Net  R, so that I can match 
and see and compare the performance for some further calculations, which are 
based on random numbers in both .Net  R.
 
It will be really great to me if somebody can help me out.
 
Thanks,

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Re: [R] Question on RNG

2011-08-05 Thread Ron Michael
Thanks Duncan for your reply. However I could not understand this: 'R provides 
ways to call its RNGs from C'. Can you be more detailed what I need to do here? 
 
Thanks,


- Original Message -
From: Duncan Murdoch murdoch.dun...@gmail.com
To: Ron Michael ron_michae...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Saturday, 6 August 2011 1:24 AM
Subject: Re: [R] Question on RNG

On 11-08-05 2:17 PM, Ron Michael wrote:
 Hi all, I have happened to work on MS .NET for sometime now, and I found that 
 this language offers RNG what is called as Donald E. Knuth's subtractive 
 random number generator algorithm (found here: 
 http://msdn.microsoft.com/en-us/library/system.random.aspx#Y12).
 
 Here I was wondering whether R also have same RNG in it's inventory, so 
 looked at ?set.seed. There I found 2 related RNGs namely 'Knuth-TAOCP-2002', 
 'Knuth-TAOCP'. Can somebody guide me what is the most related RNG with .Net's?
 
 I also want to have R to draw random number from that RNG, given I set a 
 seed. My goal is to have same set of random numbers in .Net  R, so that I 
 can match and see and compare the performance for some further calculations, 
 which are based on random numbers in both .Net  R.
 
 It will be really great to me if somebody can help me out.

As far as I know, Microsoft doesn't publish the code for their RNG. Naming it 
is not enough -- implementations that differ in subtle details will give 
different streams.

So I'd recommend that you call a known RNG from .NET, rather than whatever is 
built in.  R provides ways to call its RNGs from C, so it's probably possible 
to call it from .NET:  then you can be sure the two streams are identical.

Duncan Murdoch


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[R] A Calculation on list object

2011-06-06 Thread Ron Michael
Hello, I am into some calculation on a list object, therefore requesting the 
peers if there is any short cut way to so the same calculation.

Let say I have following list object:

 List - vector('list', length = 3)
 set.seed(1)
 List[[1]] - rnorm(5)
 List[[2]] - rnorm(2)
 List[[3]] - rnorm(7)
 List
[[1]]
[1] -0.6264538  0.1836433 -0.8356286  1.5952808  0.3295078

[[2]]
[1] -0.8204684  0.4874291

[[3]]
[1]  0.7383247  0.5757814 -0.3053884  1.5117812  0.3898432 -0.6212406 -2.2146999

 
 Vector - 3:5
 Vector
[1] 3 4 5

Now, what I want to do is, add List with Vector, element-by-element. Means I 
wanted to do:

 List[[1]] + Vector[1]
[1] 2.373546 3.183643 2.164371 4.595281 3.329508
 List[[2]] + Vector[2]
[1] 3.179532 4.487429
 List[[3]] + Vector[3]
[1] 5.738325 5.575781 4.694612 6.511781 5.389843 4.378759 2.785300

Till now I have done this calculation with for-loop. Therefore it would be 
interesting if there is any elegant way to do the same.

Thanks,

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[R] Vectorizing a function: what does it mean?

2011-05-09 Thread Ron Michael
Dear all, I would really appreciate if somebody can help me to understand what 
does the phrase Vectorize your function mean? And what is the job of 
Vectorize() function in doing that? I have read many threads where experts 
suggest to Vectorize the function, which will speed up entire calculation (and 
more elegant ofcourse.)

I used to think that vectorizing function means, to create a function such a 
way so that if input(s) are vector then this function will also return a vector 
output (without having any extra effort like use of 'for' loop etc.) Is this 
understanding correct?

Here I have tried 2 essentially similar functions:

 fn1 - function(x,y,z) return(x+y+z)
 fn2 - Vectorize(function(x,y,z) return(x+y+z), SIMPLIFY=TRUE)
 fn1(1:3, 4:6,5)
[1] 10 12 14
 fn2(1:3, 4:6,5)
[1] 10 12 14


You see that, fn1() and fn2() is giving same answer (vectorized?) despite of 
the fact that fn1() is not wrapped within Vectorize() function. Therefore I 
want to know: what additional thing this Vectorize() function brings on the 
table?

Thanks for your time.

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[R] lower.tri/upper.tri functions unable to make a matrix symmetric!

2011-02-01 Thread Ron Michael
Dear all, I have having a strange problem with upper.tri()/lower.tri() 
functions which I used to use to make a matrix symmetric. However for a 
specific large matrix, they seem not working. Initial I had following matrix:

 MyMatrix
  [,1] [,2]  [,3]  [,4]  [,5]   
   [,6]  [,7]  [,8]  [,9] [,10]
 [1,] 0.0002137831 1.791564e-06  1.308941e-06  1.320362e-06  1.576466e-06 
-2.090668e-06 -4.480179e-08  1.617517e-06  1.188307e-06 -6.592009e-06
 [2,]   NA 2.313636e-04 -2.028031e-06 -2.749156e-06 -4.670093e-07  
2.630111e-06  1.364227e-06 -5.065928e-06  9.069602e-07  7.034820e-07
 [3,]   NA   NA  2.800611e-04  2.530742e-06  1.237191e-06  
6.105895e-07 -2.095904e-06 -5.090979e-06  1.180013e-06  8.172282e-06
 [4,]   NA   NANA  3.219580e-04 -8.626130e-08  
2.877486e-06 -4.387613e-06  1.551715e-06  5.999397e-07 -4.047684e-06
 [5,]   NA   NANANA  2.343739e-04  
5.086490e-06  2.839762e-06 -5.081967e-07  1.121733e-07 -3.601529e-06
 [6,]   NA   NANANANA  
2.488756e-04  2.118398e-07 -1.879584e-06  7.186348e-07 -3.602057e-06
 [7,]   NA   NANANANA   
 NA  2.946481e-04  2.454685e-06 -2.310217e-07  2.787164e-06
 [8,]   NA   NANANANA   
 NANA  1.899915e-04  1.224963e-06 -1.533257e-07
 [9,]   NA   NANANANA   
 NANANA  2.009841e-04 -6.389595e-07
[10,]   NA   NANANANA   
 NANANANA  4.427314e-04
[11,]   NA   NANANANA   
 NANANANANA
[12,]   NA   NANANANA   
 NANANANANA
[13,]   NA   NANANANA   
 NANANANANA
[14,]   NA   NANANANA   
 NANANANANA
[15,]   NA   NANANANA   
 NANANANANA
[16,]   NA   NANANANA   
 NANANANANA
  [,11] [,12] [,13] [,14] [,15] 
[,16]
 [1,]  1.611978e-06  1.156455e-06  2.429236e-06 -6.371224e-07  3.092417e-07  
3.011528e-06
 [2,] -5.510187e-06 -8.998582e-07  9.614807e-07 -8.311204e-07 -8.974948e-07 
-3.812490e-08
 [3,] -1.373343e-06 -5.213719e-07 -1.775968e-06  1.206253e-06  6.585452e-07  
1.272045e-06
 [4,] -2.28e-07  2.386934e-06  2.966653e-06  2.694338e-06  2.838703e-06  
3.419373e-06
 [5,]  4.707156e-06  2.080091e-06 -1.449516e-06  2.091399e-07  1.564799e-06  
1.203982e-06
 [6,] -7.174750e-06 -1.016559e-06  3.679732e-07 -1.604075e-06  3.363196e-06 
-2.106617e-06
 [7,] -1.358783e-06 -2.298378e-06 -1.822507e-06  1.792765e-06  1.201043e-06 
-2.553821e-06
 [8,]  5.935161e-06 -3.651090e-07  2.112346e-06 -1.432126e-06 -3.692184e-07 
-2.214944e-06
 [9,]  3.847311e-07 -1.156356e-07  4.155777e-06 -1.627045e-06  1.789992e-07  
3.229348e-06
[10,]  3.123505e-06  3.504098e-06 -1.462336e-06  3.846515e-06 -2.693877e-08  
3.698078e-06
[11,]  3.421896e-04 -1.334050e-06 -4.764588e-06 -4.065790e-07  1.312966e-06  
1.531616e-06
[12,]NA  1.600832e-04  7.403796e-07  2.684925e-06  2.003153e-06  
1.217396e-06
[13,]NANA  3.573365e-04 -1.540675e-06  4.166715e-07  
1.457177e-06
[14,]NANANA  2.21e-04  1.856102e-06 
-1.513366e-06
[15,]NANANANA  2.065449e-04  
1.294455e-06
[16,]NANANANANA  
2.056605e-04
 MyMatrix[lower.tri(MyMatrix)] - MyMatrix[upper.tri(MyMatrix)]
 isSymmetric(MyMatrix)
[1] FALSE

Can somebody please tell me what is the problem with lower.tri/upper.tri 
functions? why they are not making my matrix symmetric?

Thanks



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[R] Writing diagonal matrix in opposite direction

2011-01-11 Thread Ron Michael
Hi, is there any direct R function to write an diagonal matrix in an opposite 
way? for example I want to get like:
 
 diag(rnorm(5))[,5:1]
   [,1]   [,2]   [,3]  [,4]   [,5]
[1,]  0.000  0.000  0.000  0.00 -0.1504687
[2,]  0.000  0.000  0.000 -2.139669  0.000
[3,]  0.000  0.000 -0.2102133  0.00  0.000
[4,]  0.000 -0.2609686  0.000  0.00  0.000
[5,] -0.6818889  0.000  0.000  0.00  0.000

Is there any typical name for this type of matrix?
 
Thanks,


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[R] Question on list objects

2011-01-08 Thread Ron Michael
Hi, I have 2 questions on list object:
 
1. Suppose I have a matrix like:
dat - matrix(1:9,3)
 
Now I want to replicate this entire matrix 3 times and put entire result in a 
list object. Means, if res is the resulting list then I should have:
 
res[[1]]=dat, res[[2]]=dat, res[[3]]=dat
 
How can I do that in the easilest manner?
 
2. Suppose I have 2 list objects:
list1 - list2 - vector(list, length=2)
for(i in 1:2) {
  list1[[i]] - matrix(rnorm(15), 3)
  list2[[i]] - matrix(rnorm(15), 3)
 }

How can I add these 2 list objects? I have tried with just list1+list2, however 
it is generating some error.
 
Would be grateful for any help.
 
Thanks,


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[R] A question to get all possible combinations

2010-12-22 Thread Ron Michael
Let say, I have a matrix with 8 rows and 6 columns: 

  df1  - matrix(NA, 8, 4) 
 df1 
     [,1] [,2] [,3] [,4] 
[1,]   NA   NA   NA   NA 
[2,]   NA   NA   NA   NA 
[3,]   NA   NA   NA   NA 
[4,]   NA   NA   NA   NA 
[5,]   NA   NA   NA   NA 
[6,]   NA   NA   NA   NA 
[7,]   NA   NA   NA   NA 
[8,]   NA   NA   NA   NA 

Now I want to get **all possible** ways to fetch 6 cells at a time. Is there 
any function to do that? 

Thanks,


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[R] Calculating weekly/bi-monthly average for time series data

2010-12-03 Thread Ron Michael
Dear all, given a daily time series data, I am able to calculate monthly 
average, quarterly average like:
 
library(zoo)
dat - zooreg(rnorm(500), start=as.Date(2000-01-01), frequency=1)
mo.ave - aggregate(dat, as.yearmon(index(dat)), mean)
head(dat)
head(mo.ave)

However is there any direct way like above to calculate the weekly average, 
bi-monthly average?
 
Thanks for your help


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[R] Priniting numerics

2010-11-27 Thread Ron Michael
Hi all, can somebody help me on my little problem? I want to print a number say 
10^10 is numerical format not in scientific notation. I ttied following:
 
 options(scipen = 1)
 print(10^10, 10)
[1] 1e+10

I am not getting my desired output in simple numerical format. How can I get 
that?
 
Thanks in advance.


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Re: [R] Priniting numerics

2010-11-27 Thread Ron Michael
I am not sure if I understood the help page. It says fixed notation will be 
preferred unless it is more than ‘scipen’ digits wider. If I understood 
correctly it says, the corresponding number needs to be less wider than 
'scipen' digit, to print it numerically. Let say:
 
 options(scipen = 5)
 10^10
[1] 1e+10
 options(scipen = 6)
 10^10
[1] 100

I both cases (10^10) is wider than scipen digit. Still why I am getting 
different representations? I am missing something?
 
Thanks,
 
 


--- On Sat, 27/11/10, Peter Ehlers ehl...@ucalgary.ca wrote:


From: Peter Ehlers ehl...@ucalgary.ca
Subject: Re: [R] Priniting numerics
To: Ron Michael ron_michae...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Date: Saturday, 27 November, 2010, 5:43 PM


On 2010-11-27 02:15, Ron Michael wrote:
 Hi all, can somebody help me on my little problem? I want to print a number 
 say 10^10 is numerical format not in scientific notation. I ttied following:

 options(scipen = 1)
 print(10^10, 10)
 [1] 1e+10

 I am not getting my desired output in simple numerical format. How can I get 
 that?


You'll need a greater penalty; see ?options.

Peter Ehlers

 Thanks in advance.


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[R] Seek some help on Statistics

2010-11-01 Thread Ron Michael
Hi friends, I would really appreciate if somebody helps me give 
better understanding on subject matter.
Suppose I have a set of Integrated variables (say max order is 1). I understand 
there may be some cases when there could be some linear combinations which are 
stationary and this phenomena is called as co-integration.
Now suppose I have a vector of Random walks (which is also integrated of order 
1 each), where error terms are not necessarily independent but of 
course uncorrelated over time i.e. error terms are WN. Here my question is 
still can we find some linear combinations (like co-integrated variables) which 
are stationary? And if not, why this is not.
Please forgive me if my question seems very naive. However 
although intuitively I feel that no such linear relationships exist for RWs, 
however I find hard to explain to 2nd person.
Any help please?
Thanks


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[R] quiry on paste() function

2010-10-29 Thread Ron Michael
Hi all, I want to club different objects (character type) to a single one and 
using paste() function that can be done happily. However the problem with paste 
function is the separator field is unique for all underlying objects. If I put 
separator as - then this will come in between all underlying objects which 
are to be clubbed.
 
Therefore I am wondering whether there is any mechanism to put different 
separators for different places. Trivially this can be done by applying paste() 
function repeatedly. However I feel there must be some single mechanism for 
doing that.
 
Here is one example, where I apply paste() function twice to incorporate 2 
different separators:
 paste(paste(a, b, sep=,), c, sep=:)
[1] a,b:c

Can the same thing be done using paste() function once? something like:
paste(a, b, c, sep=c(,, :)) # this put 1st separator everywhere which 
is not intended
 
Thanks,


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[R] Checking existance of a directory

2010-10-29 Thread Ron Michael
Hi all, I am wondering is there any way to check whether some Directory exists 
or not, given the parent path of that directory? After searching for a while I 
found that there is a function dir.create() to create some directory. However I 
need to know whether such directory already exists or not, otherwise I will 
create that.
 
Thanks,


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[R] Vector multiplication

2010-10-17 Thread Ron Michael
Is there any operator in R, which will multiply each possible combination of 
the elements of 2 vectors? Suppose I have 2 vectors (1,2) and (1,2,3). If I 
multiply those 2, I should get:(1,2,3,2,4,6)
Thanks,


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[R] Fw: Problem to create a matrix polynomial

2010-10-14 Thread Ron Michael
Awaiting some suggestion. Was my question not very understandable? Please let 
me know how can I offer more elaborate clarification.
Additionally, I would like to solve the determinant of p1 for the values of 
z (I am working with some multivariate time series modelling). When I use 
det() function, it am getting error that, that function is not for objects with 
class polynomial.
Any idea please?
Thanks,

--- On Wed, 13/10/10, Ron_M ron_michae...@yahoo.com wrote:

From: Ron_M ron_michae...@yahoo.com
Subject: [R] Problem to create a matrix polynomial
To: r-help@r-project.org
Date: Wednesday, 13 October, 2010, 4:31 PM


Dear all R users, I was trying to create a polymonial using the polynom() of
PolynomF package. My problem is, if I pass coefficients as simple
numerical values, it is working, but for matrix coefficient it is not. Here
is my try:

library(PolynomF)
z - polynom()

## following is working
p1 - 1- 4.5*z

## However following is not giving results as intended
p1 - diag(3)- matrix(1:9, 3,3)*z

In the 2nd example, I was expecting a matrix polynomial in z upto degree
1, which I did not get. Can anyone please correct me how to address this
problem?

Thanks,
-- 
View this message in context: 
http://r.789695.n4.nabble.com/Problem-to-create-a-matrix-polynomial-tp2993411p2993411.html
Sent from the R help mailing list archive at Nabble.com.

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[R] Generating weekdays only

2010-10-04 Thread Ron Michael
Dear all, can anyone please tell me how to generate a sequence of days 
continuously, however without considering weekends i.e. Saturday and Sunday? I 
am aware of following code:

 seq(as.Date(2010-01-01), as.Date(2010-02-01), by=1 day)
 [1] 2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 
2010-01-06 2010-01-07 2010-01-08
 [9] 2010-01-09 2010-01-10 2010-01-11 2010-01-12 2010-01-13 
2010-01-14 2010-01-15 2010-01-16
[17] 2010-01-17 2010-01-18 2010-01-19 2010-01-20 2010-01-21 
2010-01-22 2010-01-23 2010-01-24
[25] 2010-01-25 2010-01-26 2010-01-27 2010-01-28 2010-01-29 
2010-01-30 2010-01-31 2010-02-01

However this generates all days.
Thanks for your time.



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[R] Keyword to clear the screen

2010-09-15 Thread Ron Michael
Hi all, can anyone please tell me what is the key-word to clear the screen? I 
am aware of the cont+L, however I need some R-syntax, that can be typed into 
the console to clear the screen.
 
Thanks


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Re: [R] Keyword to clear the screen

2010-09-15 Thread Ron Michael
Thanks everyone who have looked into my problem. In the mean time I already 
found one tip here 
http://onertipaday.blogspot.com/2007/05/how-to-clear-screen-in-r.html to do 
that. I am yet to try it...perhaps it would solve me problem :)
 
Thanks,

--- On Wed, 15/9/10, Ron Michael ron_michae...@yahoo.com wrote:


From: Ron Michael ron_michae...@yahoo.com
Subject: [R] Keyword to clear the screen
To: r-h...@stat.math.ethz.ch
Date: Wednesday, 15 September, 2010, 8:27 PM


Hi all, can anyone please tell me what is the key-word to clear the screen? I 
am aware of the cont+L, however I need some R-syntax, that can be typed into 
the console to clear the screen.
 
Thanks


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[R] Matrix to list

2010-09-03 Thread Ron Michael
Dear all, suppose I have following matrix:
 
 mat - matrix(rnorm(25), 5)
 
 mat
    [,1]   [,2]    [,3]   [,4]   [,5]
[1,]  0.97056228 -1.3278509 -0.73511792  2.1650629 -0.4411997
[2,]  0.58613700 -0.2559899 -1.18334248 -1.4990907  1.8138846
[3,] -1.0313  2.0227887  0.89622681  0.6483973 -1.5523283
[4,]  0.38968833  0.2490004 -0.02301061 -0.2705150 -0.9237268
[5,]  0.03306289 -0.4022751 -0.44404905 -1.6810542 -0.1016683

Now from mat I would like to create a list object where i-th column of 
mat will represent i-th element of that list object.
 
I am looking for some way to avoid for loop. It will be really helpful if 
somebody points me on that.
 
Thanks,


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Re: [R] Matrix to list

2010-09-03 Thread Ron Michael
Thanks Henrique and Marc for your reply, both worked.
 
However I need one more suggestion on from list to matrix
 
dat - vector(list, 3)
dat[[1]] - rnorm(5)
dat[[2]] - rnorm(15)
dat[[3]] - rnorm(3)
 dat
[[1]]
[1] 0.7615421 0.4151374 0.6534402 1.5999338 1.4131837
[[2]]
 [1]  0.7364765  2.0786904 -1.1087768  1.5091391 -0.1448301  1.6015788  
1.8039138  1.1194863  1.4907951  0.5324749
[11]  0.6792318 -0.8328359 -1.8009706 -0.8523432  0.5314461
[[3]]
[1] -0.4350899 -0.2610924 -0.6489858

Now I want to convert dat to a matrix. I tried following:
 
 Reduce(cbind, dat)
   init  
 [1,] 0.7615421  0.7364765 -0.4350899
 [2,] 0.4151374  2.0786904 -0.2610924
 [3,] 0.6534402 -1.1087768 -0.6489858
 [4,] 1.5999338  1.5091391 -0.4350899
 [5,] 1.4131837 -0.1448301 -0.2610924
 [6,] 0.7615421  1.6015788 -0.6489858
 [7,] 0.4151374  1.8039138 -0.4350899
 [8,] 0.6534402  1.1194863 -0.2610924
 [9,] 1.5999338  1.4907951 -0.6489858
[10,] 1.4131837  0.5324749 -0.4350899
[11,] 0.7615421  0.6792318 -0.2610924
[12,] 0.4151374 -0.8328359 -0.6489858
[13,] 0.6534402 -1.8009706 -0.4350899
[14,] 1.5999338 -0.8523432 -0.2610924
[15,] 1.4131837  0.5314461 -0.6489858

 
Here you see values of vector with smaller length is getting repeated. Instead 
of repetition, I would like to fill those with NA (or possibly some 
predefined fixed value)
 
Would you please suggest me how to do that?
 
Thanks,


--- On Fri, 3/9/10, Henrique Dallazuanna www...@gmail.com wrote:


From: Henrique Dallazuanna www...@gmail.com
Subject: Re: [R] Matrix to list
To: Ron Michael ron_michae...@yahoo.com
Cc: r-h...@stat.math.ethz.ch
Date: Friday, 3 September, 2010, 8:07 PM


Try this:

unclass(as.data.frame(mat))



On Fri, Sep 3, 2010 at 9:48 AM, Ron Michael ron_michae...@yahoo.com wrote:

Dear all, suppose I have following matrix:
 
 mat - matrix(rnorm(25), 5)

 mat
    [,1]   [,2]    [,3]   [,4]   [,5]
[1,]  0.97056228 -1.3278509 -0.73511792  2.1650629 -0.4411997
[2,]  0.58613700 -0.2559899 -1.18334248 -1.4990907  1.8138846
[3,] -1.0313  2.0227887  0.89622681  0.6483973 -1.5523283
[4,]  0.38968833  0.2490004 -0.02301061 -0.2705150 -0.9237268
[5,]  0.03306289 -0.4022751 -0.44404905 -1.6810542 -0.1016683

Now from mat I would like to create a list object where i-th column of 
mat will represent i-th element of that list object.
 
I am looking for some way to avoid for loop. It will be really helpful if 
somebody points me on that.
 
Thanks,


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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O



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[R] Determining the length of unique items in a vector

2010-08-20 Thread Ron Michael
Dear all, let suppose I have following vector:
 
 dat1 - c(rep(asd, 5), rep(xyz, 12), rep(erd, 17))
 dat1 - dat1[sample(1:length(dat1), length(dat1), replace=F)]
 dat1
 [1] erd xyz erd asd asd erd xyz asd erd erd asd xyz 
erd asd xyz xyz erd xyz erd
[20] erd erd xyz xyz erd erd erd erd xyz xyz xyz erd 
xyz erd erd

 
Here I want to know the length of replications for each unique items viz asd, 
xyz, and erd. Is there any R function available to directly implement that?
 
Thanks,


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[R] Need help on upper.tri()

2010-08-03 Thread Ron Michael
HI, I am really messing up to make a symmetrical matrix using upper.tri()  
lower.tri() function. Here is my code:
 
 set.seed(1)
 mat = matrix(rnorm(25), 5, 5)
 mat
   [,1]   [,2]   [,3]    [,4]    [,5]
[1,] -0.6264538 -0.8204684  1.5117812 -0.04493361  0.91897737
[2,]  0.1836433  0.4874291  0.3898432 -0.01619026  0.78213630
[3,] -0.8356286  0.7383247 -0.6212406  0.94383621  0.07456498
[4,]  1.5952808  0.5757814 -2.2146999  0.82122120 -1.98935170
[5,]  0.3295078 -0.3053884  1.1249309  0.59390132  0.61982575
 mat[lower.tri(mat)] = mat[upper.tri(mat)]
 mat
    [,1]    [,2]    [,3]    [,4]    [,5]
[1,] -0.62645381 -0.82046838  1.51178117 -0.04493361  0.91897737
[2,] -0.82046838  0.48742905  0.38984324 -0.01619026  0.78213630
[3,]  1.51178117 -0.01619026 -0.62124058  0.94383621  0.07456498
[4,]  0.38984324  0.94383621  0.78213630  0.82122120 -1.98935170
[5,] -0.04493361  0.91897737  0.07456498 -1.98935170  0.61982575

 
Which is not coming as symmetrical function. Can anyone point me on the correct 
way of using upper, lower.try() function to get a symmetrical matrix?
 
Thanks,


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[R] Meaning of following function

2010-08-01 Thread Ron Michael
Hi friends, I am aware of the function -() which acts as minus in ordinary 
computations. For example:
 
 -(3, 1)
[1] 2

However what is the meaning of 
 -(3)
[1] -3

I was expecting R to generate some error as it does for *(3). What is the 
logic for that calculation?
 
Thanks,


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[R] Drawing sample from a circle

2010-06-18 Thread Ron Michael
Hi, I would like to draw 10 uniformly distributed sample points from a circle 
with redius one and centered at (0,0). Is there any R function to do that?
 
Thanks,


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Re: [R] [OOPS] Re: Drawing sample from a circle

2010-06-18 Thread Ron Michael
Thank you so much Teds for pviding this function. Would you please explain the 
theory behind that?
 
Thanks,

--- On Fri, 18/6/10, ted.hard...@manchester.ac.uk 
ted.hard...@manchester.ac.uk wrote:


From: ted.hard...@manchester.ac.uk ted.hard...@manchester.ac.uk
Subject: [OOPS] Re: [R] Drawing sample from a circle
To: r-h...@stat.math.ethz.ch
Cc: Ron Michael ron_michae...@yahoo.com
Date: Friday, 18 June, 2010, 4:48 PM


OOPS: AN error on the code below! See in-line.
Ted.

On 18-Jun-10 09:33:04, Ted Harding wrote:
 On 18-Jun-10 08:04:36, Ron Michael wrote:
 Hi, I would like to draw 10 uniformly distributed sample points from a
 circle with redius one and centered at (0,0). Is there any R function
 to do that?
 _
 Thanks,
 
 You can quite easily write one.
 
 [A]
 Sampling uniformly on the circumference of the circle:
 
   csamp - function(n,rad=1,centre=c(0,0)){
     x0 - centre[1] ; y0 - centre[2]
     u - 2*pi*runif(n)
     rad*cbind(x=cos(u)+x0, y=sin(u)+y0)
   }
 
# Returns an nx2 matrix whose two columns are the x and y coordinates
CORRECTION:

  csamp - function(n,rad=1,centre=c(0,0)){
    x0 - centre[1] ; y0 - centre[2]
    u - 2*pi*runif(n)
    cbind(x=rad*cos(u)+x0, y=rad*sin(u)+y0)
  }

# Returns an nx2 matrix whose two columns are the x and y coordinates

 [B]
 Sampling uniformaly within the circle
 
   Csamp - function(n,rad=1,centre=c(0,0)){
     x0 - centre[1] ; y0 - centre[2]
     u - 2*pi*runif(n)
     r - sqrt(runif(n))
     rad*cbind(x=r*cos(u)+x0, y=r*sin(u)+y0)
 }
 
# Returns an nx2 matrix whose two columns are the x and y coordinates
CORRECTION:

  Csamp - function(n,rad=1,centre=c(0,0)){
    x0 - centre[1] ; y0 - centre[2]
    u - 2*pi*runif(n)
    r - sqrt(runif(n))
    cbind(x=rad*r*cos(u)+x0, y=rad*r*sin(u)+y0)
}

# Returns an nx2 matrix whose two columns are the x and y coordinates


 [C]
 Examples:
 
   plot(csamp(100),asp=1)
 
   plot(Csamp(1000),asp=1)
 
 Ted.
 
 
 E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
 Fax-to-email: +44 (0)870 094 0861
 Date: 18-Jun-10                                       Time: 10:33:00
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E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
Fax-to-email: +44 (0)870 094 0861
Date: 18-Jun-10                                       Time: 10:48:14
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[R] Fw: Re: Why \\ instead of simple / to specify a file path [modified]

2010-03-22 Thread Ron Michael
Hi, I was following this thread and would like to ask is there any way to save 
and open a .RData file after using some Password. What I mean to say, how to 
make my workplace password-protected?
Also would like to know how same can be done for .R file.
Thanks for your time.
Thanks and regards,


--- On Tue, 23/3/10, David Winsemius dwinsem...@comcast.net wrote:

From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] Why \\ instead of simple / to specify a file path
To: Bogaso bogaso.christo...@gmail.com
Cc: r-help@r-project.org
Date: Tuesday, 23 March, 2010, 1:51 AM


On Mar 22, 2010, at 1:22 PM, Bogaso wrote:

 
 Hi all,
 
 I have saved my workplace in a .RData format. However if I want to open
 that, I need to use following code :
 
 load(C:\\..)
 
 Here my question is why \\. In all the time generally we use / like when
 we use read.delim() function etc. Is there any possibility to have some
 consistency there?

Depends what you mean by consistency. The same rule applies on all current 
supported OS platforms. Doubling the back-slashes is needed because \ is an 
escape character.

 Is there any other way to re-open the .RData file?

If your OS supports it you may be able to use drag-drop with file icons or you 
can use file.choose()


--David.
 
 Thanks,
 --View this message in context: 
 http://n4.nabble.com/Why-instead-of-simple-to-specify-a-file-path-tp1677973p1677973.html
 Sent from the R help mailing list archive at Nabble.com.
 
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[R] Creating list from matrix

2008-10-22 Thread Ron Michael
Hello everyone,
 
I have a matrix like :
 
mat - matrix(rnorm(12*3), 3)
 
Now I want to break that matrix in 4 parts each of them are matrix of (3x3) and 
put those 4 matrices in a list object of length 4
 
Can anyone please tell me how to do that?


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[R] Fw: MLE

2008-10-08 Thread Ron Michael
I made one typo in my previous mail.
 
May I ask one statistics related question please? I have one query on MLE 
itself. It's property says that, for large sample size it is normally 
distributed [i.e. asymptotically normal]. On the other hand it is Consistent 
as well. My doubt is, how this two asymptotic properties exist simultaneously? 
If it is consistent then asymptotically it should collapse to truth i.e. for 
large sample size, variance of MLE should be zero. However asymptotic normality 
says, MLE have some distribution and hence variance.
 
Can anyone please clarify me? Your help will be highly appreciated.


--- On Wed, 8/10/08, Ron Michael [EMAIL PROTECTED] wrote:

From: Ron Michael [EMAIL PROTECTED]
Subject: [R] MLE
To: [EMAIL PROTECTED]
Date: Wednesday, 8 October, 2008, 6:05 PM

May I ask one statistics related question please? I have one query on MLE
itself. It's property says that, for large sample size it is normally
distributed [i.e. asymptotically normal]. On the other hand it is Efficient as
well. My doubt is, how this two asymptotic properties exist simultaneously? If
it is consistent then asymptotically it should collapse to truth
i.e. for large sample size, variance of MLE should be zero. However asymptotic
normality says, MLE have some distribution and hence variance.
 
Can anyone please clarify me? Your help will be highly appreciated.
 


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[R] MLE

2008-10-08 Thread Ron Michael
May I ask one statistics related question please? I have one query on MLE 
itself. It's property says that, for large sample size it is normally 
distributed [i.e. asymptotically normal]. On the other hand it is Efficient as 
well. My doubt is, how this two asymptotic properties exist simultaneously? If 
it is consistent then asymptotically it should collapse to truth i.e. for 
large sample size, variance of MLE should be zero. However asymptotic normality 
says, MLE have some distribution and hence variance.
 
Can anyone please clarify me? Your help will be highly appreciated.
 


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[R] A Regression question

2008-09-20 Thread Ron Michael
Dear all,

I have statistics related question. What type of modeling technique to be
used when dependent variable (Y) is continuous but with 99% zero.The other
1% (+ve , don't have -ve values) values are huge.

If I take DGP of dependent variable as Pareto type distribution, will it be
ok? Your help will be highly appreciated.

Regards,

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[R] All possible pairs of two variables

2008-09-10 Thread Ron Michael
I have two variables (x,y) :

x : it takes all integer values from 0 to y and,
y : takes all values from 0, 10

I am looking for some R code to find all possible pairs of (x,y). Can anyone 
please help me?



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[R] as.Date() clarification

2008-07-03 Thread Ron Michael
When I use the code as.Date(0) the I get : 1970-01-01. My question is why it 
is like that? help file on as.Date seems to give no light on that. Can anyone 
clarify me?
 
Regards,

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Re: [R] A regression problem using dummy variables

2008-07-03 Thread Ron Michael
which group contrasts you want to look at can you clarify me on that 
statement?

--- On Thu, 3/7/08, Peter Dalgaard [EMAIL PROTECTED] wrote:

From: Peter Dalgaard [EMAIL PROTECTED]
Subject: Re: [R] A regression problem using dummy variables
To: rlearner309 [EMAIL PROTECTED]
Cc: r-help@r-project.org
Date: Thursday, 3 July, 2008, 2:57 PM

rlearner309 wrote:
 I think it is zero, because you have lots of zeros there.  It is not like
 continous variables.

   
Think again. The sum of products may be zero, but that is not the 
covariance. And don't dismiss Thomas, he is usually right.

Anyways, the coefs of dummy variables represent differences to the same 
base level, and chosing a poorly determined base level (essentially: 
whose mean is determined by only a few observations) will cause high 
parameter correlation. It should only affect those parameters though, 
and it is not really clear what VIF means for dummy variables. One often 
choses to relevel() to make the largest group the base level, but it 
really comes down to which group contrasts you want to look at.



 Thomas Lumley wrote:
   
 On Wed, 2 Jul 2008, rlearner309 wrote:

 
 I think the covariance between dummy variables or between dummy
variables
 and
 intercept should always be zero.  meaning: no sigularity problem??

   
 No.  You can easily check that this is not true using the cov()
function.
 Indicator variables for mutually exclusive groups are negatively
 correlated.

  -thomas



 
 rlearner309 wrote:
   
 This is actually more like a Statistics problem:
 I have a dataset with two dummy variables controlling three
levels.  The
 problem is, one level does not have many observations compared
with
 other
 two levels (a couple of data points compared with 1000+ points
on other
 levels).  When I run the regression, the result is bad.  I
have
 unbalanced
 SE and VIF.  Does this kind of problem also belong to
near sigularity
 problem?  Does it make any difference if I code the level that
lacks
 data
 (0,0) in stead of (0,1)?

 thanks a lot!

 
 --
 View this message in context:

http://www.nabble.com/A-regression-problem-using-dummy-variables-tp18214377p18237666.html
 Sent from the R help mailing list archive at Nabble.com.

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 Thomas LumleyAssoc. Professor, Biostatistics
 [EMAIL PROTECTED]University of Washington, Seattle

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-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] A regression problem using dummy variables

2008-07-03 Thread Ron Michael
VR's MASS book can you give the full name of that book

--- On Thu, 3/7/08, Bert Gunter [EMAIL PROTECTED] wrote:

From: Bert Gunter [EMAIL PROTECTED]
Subject: RE: [R] A regression problem using dummy variables
To: [EMAIL PROTECTED]
Cc: r-help@r-project.org
Date: Thursday, 3 July, 2008, 9:21 PM

Contrasts for categorical variables are a technical issue in linear models.
They are best understood (imo) as the choice of bases for the vector space
of the model matrix. So how good is your linear algebra? A terse but I think
very clear treatment of these issues can be found in the relevant chapter of
VR's MASS book.

FWIW, I have found that even statisticians get confused by these issues
(certainly I have!).

-- Bert Gunter

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Ron Michael
Sent: Thursday, July 03, 2008 2:19 AM
To: rlearner309; Peter Dalgaard
Cc: r-help@r-project.org
Subject: Re: [R] A regression problem using dummy variables

which group contrasts you want to look at can you clarify me on
that
statement?

--- On Thu, 3/7/08, Peter Dalgaard [EMAIL PROTECTED] wrote:

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Re: [R] Interactive plot

2008-06-29 Thread Ron Michael
Hi, whenever I try to load the playwith package I am getting following warning :
 
 library(playwith)
Loading required package: lattice
Loading required package: grid
Warning message:
In namespaceImportFrom(self, asNamespace(ns)) :
  replacing previous import: addhandler

Can anyone please tell me why I am getting that warning?

--- On Sun, 29/6/08, Gabor Grothendieck [EMAIL PROTECTED] wrote:

From: Gabor Grothendieck [EMAIL PROTECTED]
Subject: Re: [R] Interactive plot
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Date: Sunday, 29 June, 2008, 8:18 PM

Install the GTK runtime:

http://www.ggobi.org/rgtk2/

On Sun, Jun 29, 2008 at 9:06 AM, Ron Michael [EMAIL PROTECTED]
wrote:
 whenever I try to load playwith package I get following error
:

 library(playwith)
 Loading required package: lattice
 Loading required package: grid
 Error in inDL(x, as.logical(local), as.logical(now), ...) :
   unable to load shared library
'C:/PROGRA~1/R/R-27~1.1/library/RGtk2/libs/RGtk2.dll':
   LoadLibrary failure:  The specified module could not be found.

 Error: package/namespace load failed for 'playwith'

 What to do?

 --- On Sun, 29/6/08, Liviu Andronic [EMAIL PROTECTED] wrote:

 From: Liviu Andronic [EMAIL PROTECTED]
 Subject: Re: [R] Interactive plot
 To: Ron Michael [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Date: Sunday, 29 June, 2008, 7:46 PM

 On 6/29/08, Ron Michael [EMAIL PROTECTED] wrote:
  Now I want to present the plot in some interactive manner. I want to
put
 a slider in the plot where user move the slider for the 1st element of the
 vector vary and automatically this result will be reflected at
the
 plot window.

 playwith: A GUI for interactive plots using GTK+ ? [1]

 [1] http://cran.at.r-project.org/web/packages/playwith/index.html

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Re: [R] Interactive plot

2008-06-29 Thread Ron Michael
Hi all R users. I already done through some of the examples given with playwith 
packages and feel nowhere they are matching with my requirement. Can amyone 
please suggest me how to create my desired interactive plot with tkrplot ?
 
I want following. Let look at following codes :
 
mat = cbind(c(0.59710430,0.23057380), c(0.23057380, 0.5971089)) 
set.seed = 1000 vary = runif(dim(mat)[1], 2000, 3000) calc = function(mat, vary)
{
result = vector(length = (length(vary)+1))
result[1] = sqrt(t(vary) %*% vary)
for (i in 1 : length(vary))
{
result[(i+1)] = sum(vary)*sum(vary*mat[,i])
}
barplot(result)
return(result)
}
 
Now I want to put a slider in the plot where user move the slider for the 1st 
element of the vector vary and automatically this result will be reflected at 
the plot window. Can anyone please tell me how to do that with tkrplot or 
TeachingDemos ?
 
 


--- On Sun, 29/6/08, Ron Michael [EMAIL PROTECTED] wrote:

From: Ron Michael [EMAIL PROTECTED]
Subject: Re: [R] Interactive plot
To: Gabor Grothendieck [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Date: Sunday, 29 June, 2008, 11:48 PM

Hi, whenever I try to load the playwith package I am getting following warning :
 
 library(playwith)
Loading required package: lattice
Loading required package: grid
Warning message:
In namespaceImportFrom(self, asNamespace(ns)) :
  replacing previous import: addhandler

Can anyone please tell me why I am getting that warning?

--- On Sun, 29/6/08, Gabor Grothendieck [EMAIL PROTECTED] wrote:

From: Gabor Grothendieck [EMAIL PROTECTED]
Subject: Re: [R] Interactive plot
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Date: Sunday, 29 June, 2008, 8:18 PM

Install the GTK runtime:

http://www.ggobi.org/rgtk2/

On Sun, Jun 29, 2008 at 9:06 AM, Ron Michael [EMAIL PROTECTED]
wrote:
 whenever I try to load playwith package I get following error
:

 library(playwith)
 Loading required package: lattice
 Loading required package: grid
 Error in inDL(x, as.logical(local), as.logical(now), ...) :
   unable to load shared library
'C:/PROGRA~1/R/R-27~1.1/library/RGtk2/libs/RGtk2.dll':
   LoadLibrary failure:  The specified module could not be found.

 Error: package/namespace load failed for 'playwith'

 What to do?

 --- On Sun, 29/6/08, Liviu Andronic [EMAIL PROTECTED] wrote:

 From: Liviu Andronic [EMAIL PROTECTED]
 Subject: Re: [R] Interactive plot
 To: Ron Michael [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Date: Sunday, 29 June, 2008, 7:46 PM

 On 6/29/08, Ron Michael [EMAIL PROTECTED] wrote:
  Now I want to present the plot in some interactive manner. I want to
put
 a slider in the plot where user move the slider for the 1st element of the
 vector vary and automatically this result will be reflected at
the
 plot window.

 playwith: A GUI for interactive plots using GTK+ ? [1]

 [1] http://cran.at.r-project.org/web/packages/playwith/index.html

 Send instant messages to your online friends http://uk.messenger.yahoo.com
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Re: [R] Interactive plot

2008-06-29 Thread Ron Michael
, RGtkObject
Error in `[[-.GObject`(`*tmp*`, tooltip-text, value = Zoom out to show 4x 
plot area) : 
  Cannot find 'tooltip-text' to set in GtkToolButton, GtkToolItem, GtkBin, 
GtkContainer, GtkWidget, GtkObject, GInitiallyUnowned, GObject, RGtkObject
Error in `[[-.GObject`(`*tmp*`, tooltip-text, value = Show the full scale 
starting from zero) : 
  Cannot find 'tooltip-text' to set in GtkToolButton, GtkToolItem, GtkBin, 
GtkContainer, GtkWidget, GtkObject, GInitiallyUnowned, GObject, RGtkObject

 
 
Any idea how to fix that?
 


--- On Mon, 30/6/08, Gabor Grothendieck [EMAIL PROTECTED] wrote:

From: Gabor Grothendieck [EMAIL PROTECTED]
Subject: Re: [R] Interactive plot
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Date: Monday, 30 June, 2008, 12:30 AM

In ?playwith the third example seems pretty close to what you
want.  Here it is changed to correspond to your setup.

Remove the barplot line from calc since we don't want calc to do
any plotting and then try this:

library(lattice)
playwith(barchart(seq_along(result) ~ result,
data = data.frame(result = calc(mat, c(alpha, vary[2],
parameters = list(alpha = seq(2000, 3000, by = 10)))



On Sun, Jun 29, 2008 at 1:07 PM, Ron Michael [EMAIL PROTECTED]
wrote:
 Hi all R users. I already done through some of the examples given with
playwith packages and feel nowhere they are matching with my requirement. Can
amyone please suggest me how to create my desired interactive plot with
tkrplot ?

 I want following. Let look at following codes :

 mat = cbind(c(0.59710430,0.23057380), c(0.23057380,
0.5971089)) set.seed = 1000 vary = runif(dim(mat)[1], 2000, 3000) calc =
function(mat, vary)
 {
 result = vector(length = (length(vary)+1))
 result[1] = sqrt(t(vary) %*% vary)
 for (i in 1 : length(vary))
 {
 result[(i+1)] = sum(vary)*sum(vary*mat[,i])
 }
 barplot(result)
 return(result)
 }

 Now I want to put a slider in the plot where user move the slider for the
1st element of the vector vary and automatically this result will
be reflected at the plot window. Can anyone please tell me how to do that with
tkrplot or TeachingDemos ?




 --- On Sun, 29/6/08, Ron Michael [EMAIL PROTECTED] wrote:

 From: Ron Michael [EMAIL PROTECTED]
 Subject: Re: [R] Interactive plot
 To: Gabor Grothendieck [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Date: Sunday, 29 June, 2008, 11:48 PM

 Hi, whenever I try to load the playwith package I am getting following
warning :

 library(playwith)
 Loading required package: lattice
 Loading required package: grid
 Warning message:
 In namespaceImportFrom(self, asNamespace(ns)) :
   replacing previous import: addhandler

 Can anyone please tell me why I am getting that warning?

 --- On Sun, 29/6/08, Gabor Grothendieck [EMAIL PROTECTED]
wrote:

 From: Gabor Grothendieck [EMAIL PROTECTED]
 Subject: Re: [R] Interactive plot
 To: [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Date: Sunday, 29 June, 2008, 8:18 PM

 Install the GTK runtime:

 http://www.ggobi.org/rgtk2/

 On Sun, Jun 29, 2008 at 9:06 AM, Ron Michael
[EMAIL PROTECTED]
 wrote:
 whenever I try to load playwith package I get following
error
 :

 library(playwith)
 Loading required package: lattice
 Loading required package: grid
 Error in inDL(x, as.logical(local), as.logical(now), ...) :
   unable to load shared library
 'C:/PROGRA~1/R/R-27~1.1/library/RGtk2/libs/RGtk2.dll':
   LoadLibrary failure:  The specified module could not be found.

 Error: package/namespace load failed for 'playwith'

 What to do?

 --- On Sun, 29/6/08, Liviu Andronic [EMAIL PROTECTED]
wrote:

 From: Liviu Andronic [EMAIL PROTECTED]
 Subject: Re: [R] Interactive plot
 To: Ron Michael [EMAIL PROTECTED]
 Cc: [EMAIL PROTECTED]
 Date: Sunday, 29 June, 2008, 7:46 PM

 On 6/29/08, Ron Michael [EMAIL PROTECTED] wrote:
  Now I want to present the plot in some interactive manner. I want
to
 put
 a slider in the plot where user move the slider for the 1st element of
the
 vector vary and automatically this result will be
reflected at
 the
 plot window.

 playwith: A GUI for interactive plots using GTK+ ? [1]

 [1] http://cran.at.r-project.org/web/packages/playwith/index.html

 Send instant messages to your online friends

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 and provide commented, minimal, self-contained, reproducible code.

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[R] Interactive plot

2008-06-28 Thread Ron Michael
Hi all,

I have created following codes :


mat = cbind(c(0.59710430,0.23057380), c(0.23057380, 0.5971089))
set.seed = 1000
vary = runif(dim(mat)[1], 2000, 3000)
calc = function(mat, vary)
{
 result = vector(length = (length(vary)+1))
 result[1] = sqrt(t(vary) %*% vary)
 for (i in 1 : length(vary))
{
 result[(i+1)] = sum(vary)*sum(vary*mat[,i])
}
 barplot(result)
 return(result)
}


Now I want to present the plot in some interactive manner. I want to put a 
slider in the plot where user move the slider for the 1st element of the vector 
vary and automatically this result will be reflected at the plot window. I 
already gone through some examples of tkrplot library, however unfortunately 
could not figure out how i can apply them in my problem. 

If anyone here explain me how to do that I would be grateful.

Regards,


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[R] Need help to draw a plot

2008-06-23 Thread Ron Michael
can i have some instruction on how to draw this type of plot in R : 
http://sitmo.com/doc/Image:Ll_ou_conpron.png#filelinks ?
Regards,

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and provide commented, minimal, self-contained, reproducible code.


[R] Interpretation of Variance decomposition in VAR model

2008-03-20 Thread Ron Michael
Hi all,

This question is not really R related, rather on Statistics subject itself. 
Even I did not do those using R. however still I want to post it here, because 
my hope is I could get help from great statisticians who are the very active 
member of this group.


My problem is to interpret Variance decomposition of VAR model in layman's 
language.

Using EViews I got following :


 Variance Decomposition of LN_FU:   
 Period S.E.LN_SPOT LN_FU

 1   0.02442293.669596.330413
 2   0.03483894.365065.634938
 3   0.04228094.607125.392882
 4   0.04854094.307255.692747
 5   0.05406093.990396.009611
 6   0.05904293.675456.324554
 7   0.06362193.334056.665951
 8   0.06788592.993477.006529
 9   0.07189392.659667.340337
 10  0.07568792.332667.667341

 Variance Decomposition of LN_SPOT: 
 Period S.E.LN_SPOT LN_FU

 1   0.023745100.0.00
 2   0.03374199.511220.488785
 3   0.04101899.253390.746605
 4   0.04720498.983541.016462
 5   0.05266098.624011.375990
 6   0.05760098.249851.750151
 7   0.06215597.863032.136970
 8   0.06640097.461972.538034
 9   0.07039497.056552.943451
 10  0.07417696.651023.348978

 Cholesky Ordering: LN_SPOT LN_FU   

Myquestion is How to interpret those result in layman language? If I 
sayfollowing : 93.66959% of tomorrow's volatility in LN_FU is explainedby 
LN_SPOT's today volatility and remaining 6.330413% is explained byit's today's 
Volatility, is this statement correct? Then what will bethe interpretation of 
remaining numbers like : 94.36506,5.634938,..etc?

And also What could be the interpretation of the SE in layman's term?

I already gone through Eviews help file however, did not get anything. If u 
people here help me on this regard, I will be very very grateful.

Regards,



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and provide commented, minimal, self-contained, reproducible code.


[R] Interpretation of Variance decomposition in VAR model

2008-03-20 Thread Ron Michael
Hi all,

This question is not really R related, rather on Statistics subject itself. 
Even I did not do those using R. however still I want to post it here, because 
my hope is I could get help from great statisticians who are the very active 
member of this group.


My problem is to interpret Variance decomposition of VAR model in layman's 
language.

Using EViews I got following :


 Variance Decomposition of LN_FU:   
 Period S.E.LN_SPOT LN_FU

 1   0.02442293.669596.330413
 2   0.03483894.365065.634938
 3   0.04228094.607125.392882
 4   0.04854094.307255.692747
 5   0.05406093.990396.009611
 6   0.05904293.675456.324554
 7   0.06362193.334056.665951
 8   0.06788592.993477.006529
 9   0.07189392.659667.340337
 10  0.07568792.332667.667341

 Variance Decomposition of LN_SPOT: 
 Period S.E.LN_SPOT LN_FU

 1   0.023745100.0.00
 2   0.03374199.511220.488785
 3   0.04101899.253390.746605
 4   0.04720498.983541.016462
 5   0.05266098.624011.375990
 6   0.05760098.249851.750151
 7   0.06215597.863032.136970
 8   0.06640097.461972.538034
 9   0.07039497.056552.943451
 10  0.07417696.651023.348978

 Cholesky Ordering: LN_SPOT LN_FU   

Myquestion is How to interpret those result in layman language? If I 
sayfollowing : 93.66959% of tomorrow's volatility in LN_FU is explainedby 
LN_SPOT's today volatility and remaining 6.330413% is explained byit's today's 
Volatility, is this statement correct? Then what will bethe interpretation of 
remaining numbers like : 94.36506,5.634938,..etc?

And also What could be the interpretation of the SE in layman's term?

I already gone through Eviews help file however, did not get anything. If u 
people here help me on this regard, I will be very very grateful.

Regards,


 




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and provide commented, minimal, self-contained, reproducible code.


[R] Different results in calculating SD of 2 numbers

2008-01-16 Thread Ron Michael
Hi all,

Can anyone tell me why I am getting different results in calculating SD of 2 
numbers ?

 (1.25-0.95)/2
[1] 0.15
 sd(c(1.25, 0.95))
[1] 0.2121320  # why it is different from 0.15?

Regards,

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.