Re: [R] Grid lines

2009-07-30 Thread Thomas Roth (geb. Kaliwe)

Maybe this helps


par(mar = c(5,4,6,1))
plot(1:10, type = n, axes = F)
xticks = axis(1, at = c(1,5,9), labels = 
c(1-1-2009,1-5-2009,1-9-2009))   #set axis manually

yticks = axis(2, at = 1:10)   #set axis manually
abline(v = xticks, col = gray)   #verticall lines
abline(h = yticks, col = gray, lty = 3)   #horizontal lines

legend(8,12, legend = c(test, test), col = 1:2, pch = 1:2, xpd = TRUE)

points(1:10)


Thomas Roth

Chris Li schrieb:

Hi everyone. I am new to R.

It will be greatly appreciated if someone can help me with the following
questions.

Here's the graph I have just produced. 
http://www.nabble.com/file/p24732839/calibration.jpeg 


(1) How can I put the legend on top of the grid lines?

(2) How can I match the grid lines with the x-axis ticks?

(3) How can I change the x-axis format from e.g. Mar, Apr...etc to
1-3-2009,1-4-2009...etc?

Many thanks! :-)

Chris



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Re: [R] Grid lines

2009-07-30 Thread Thomas Roth (geb. Kaliwe)

Maybe this helps


par(mar = c(5,4,6,1))
plot(1:10, type = n, axes = F)
xticks = axis(1, at = c(1,5,9), labels =
c(1-1-2009,1-5-2009,1-9-2009))   #set axis manually
yticks = axis(2, at = 1:10)   #set axis manually
abline(v = xticks, col = gray)   #verticall lines
abline(h = yticks, col = gray, lty = 3)   #horizontal lines

legend(8,12, legend = c(test, test), col = 1:2, pch = 1:2, xpd = TRUE)

points(1:10)


Thomas Roth

Chris Li schrieb:

Hi everyone. I am new to R.

It will be greatly appreciated if someone can help me with the following
questions.

Here's the graph I have just produced. 
http://www.nabble.com/file/p24732839/calibration.jpeg 


(1) How can I put the legend on top of the grid lines?

(2) How can I match the grid lines with the x-axis ticks?

(3) How can I change the x-axis format from e.g. Mar, Apr...etc to
1-3-2009,1-4-2009...etc?

Many thanks! :-)

Chris



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[R] how to evaluate character vector within pnorm()

2009-07-17 Thread Thomas Roth (geb. Kaliwe)

Hi,

I'm trying to evaluate a character vector within pnorm. I have a vector 
with values and names


x = c(2,3)
names(x) = c(mean, sd)

so that i tried the following

temp = paste(names(x), x, sep = =)

#gives
# temp
#[1] mean=2 sd=3

#Problem is that both values 2 and 3 are taken as values for the mean 
argument in pnorm

pnorm(0, eval(parse(text = temp)) )

#but not as
pnorm(0, mean = 2, sd = 3 )


#How can i get

pnorm(0, eval(parse(text = temp)) )

#to do

pnorm(0, mean = 2, sd = 3 )



Thank you for your time

Thomas Roth

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Re: [R] SOLVED: how to evaluate character vector within pnorm()

2009-07-17 Thread Thomas Roth (geb. Kaliwe)

That what i was looking for :-)

bill.venab...@csiro.au schrieb:

Here is one way:


x - c(2,3)
names(x) - c(mean, sd)

do.call(pnorm, c(list(0), as.list(x)))

 



Bill Venables
http://www.cmis.csiro.au/bill.venables/ 



-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
Behalf Of Thomas Roth (geb. Kaliwe)
Sent: Friday, 17 July 2009 6:03 PM
To: 'r-help@r-project.org'
Subject: [R] how to evaluate character vector within pnorm()

Hi,

I'm trying to evaluate a character vector within pnorm. I have a vector 
with values and names


x = c(2,3)
names(x) = c(mean, sd)

so that i tried the following

temp = paste(names(x), x, sep = =)

#gives
# temp
#[1] mean=2 sd=3

#Problem is that both values 2 and 3 are taken as values for the mean 
argument in pnorm

pnorm(0, eval(parse(text = temp)) )

#but not as
pnorm(0, mean = 2, sd = 3 )


#How can i get

pnorm(0, eval(parse(text = temp)) )

#to do

pnorm(0, mean = 2, sd = 3 )



Thank you for your time

Thomas Roth

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[R] how to check if ... is empty

2009-07-16 Thread Thomas Roth (geb. Kaliwe)

Hi,

I was wondering what would be the best way to check if the three dots 
argument contains any arguments (i.e. does ... contain any arguments or 
not? )


#Example

test = function(x,y, ...)
{
   #Wanted R-Code
   # if(empty(...))
   #do some calculation


   plot(x,y,...)

}

Thanks

Thomas Roth

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Re: [R] SOLVED: how to check if ... is empty

2009-07-16 Thread Thomas Roth (geb. Kaliwe)

Thank you both.

Thomas

Dimitris Rizopoulos schrieb:

one way is:

test - function(x, y, ...) {
dots - list(...)
if (length(dots)) cat(\nnon-empty\n) else cat(\nempty\n)
}

test(1, 1)
test(1, 1, 1)


I hope it helps.

Best,
Dimitris


Thomas Roth (geb. Kaliwe) wrote:

Hi,

I was wondering what would be the best way to check if the three dots 
argument contains any arguments (i.e. does ... contain any arguments 
or not? )


#Example

test = function(x,y, ...)
{
   #Wanted R-Code
   # if(empty(...))
   #do some calculation


   plot(x,y,...)

}

Thanks

Thomas Roth

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http://www.R-project.org/posting-guide.html

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Re: [R] paste ( x )

2009-07-14 Thread Thomas Roth (geb. Kaliwe)


maybe this helps

x = \test\
plot(1:10, main = x)   #heading contains  

#or

cat(\test\)

Thomas Roth

Paulo E. Cardoso schrieb:

maybe a very basic question but I need to parse an SQL code into a GIS from
a ODBC conn.

The code includes a specific sentence

 


OPTIONS COORDSYS(Latitude / Longitude);

 


and I need the   pasted into the string. They cannot disappear.

 


how to do this?

 




Paulo E. Cardoso

 



[[alternative HTML version deleted]]

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Re: [R] more than one mathematical annotation into a legend

2009-07-10 Thread Thomas Roth (geb. Kaliwe)
in the legend there's x but not the value of x which actually should be 
shown...


#does not work

x = 2
plot(1:10)
legend(4,4, expression(t[m] == x, t[n] == x))

#legend contains x but not the value of x

So this won't work



Zhiliang Ma schrieb:

On Thu, Jul 9, 2009 at 9:39 AM, Thomas Roth (geb.
Kaliwe)hamstersqu...@web.de wrote:
try this:

legend(4,4, expression(t[m] == x, t[n] == x))

cheers,
Zhiliang

  

Dear members,

Is there a way to put more than one mathematical annotation into a legend
together with a calculated value?

x = 2
plot(1:10)

#Works
legend(8, 8,  substitute(t[m] == x))

#does not work
legend(4,4, c(substitute(t[m] == x), substitute(t[n] == x)))

Thanks


Thomas Roth

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[R] more than one mathematical annotation into a legend

2009-07-09 Thread Thomas Roth (geb. Kaliwe)

Dear members,

Is there a way to put more than one mathematical annotation into a 
legend together with a calculated value?


x = 2
plot(1:10)

#Works
legend(8, 8,  substitute(t[m] == x))

#does not work
legend(4,4, c(substitute(t[m] == x), substitute(t[n] == x)))

Thanks


Thomas Roth

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[R] lattice wireframe within a loop ???

2009-06-24 Thread Thomas Roth (geb. Kaliwe)

Hi,

I have the following problem. Calling wireframe within a loop results 
into an empty window(s)


#generate some data
temp = expand.grid(A = 1:3,B = 1:3)
temp = cbind(temp, y1 = rnorm(9))
temp = cbind(temp, y2 = runif(9))


#plot y1 and y2 in two different windows
for(i in 1:2)
{
wireframe(y1 ~ A*B, temp, shade =T)
windows()
wireframe(y2 ~ A*B, temp, shade =T)
}


#However, calling it twice outside a loop works?

wireframe(y1 ~ A*B, temp, shade =T)
windows()
wireframe(y2 ~ A*B, temp, shade =T)


Obviously i'm missing something. How can i call wireframe more than one 
time in a loop and get a wireframe?



Greetings

Thomas Roth

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Re: [R] lattice wireframe within a loop ??? - solved

2009-06-24 Thread Thomas Roth (geb. Kaliwe)

Thank you.

ONKELINX, Thierry schrieb:
You need to print() lattice plots inside a loop or a function. 





ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
methodology and quality assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
thierry.onkel...@inbo.be
www.inbo.be

To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey
 
-Oorspronkelijk bericht-

Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens Thomas Roth (geb. Kaliwe)
Verzonden: woensdag 24 juni 2009 13:08
Aan: 'r-help@r-project.org'
Onderwerp: [R] lattice wireframe within a loop ???

Hi,

I have the following problem. Calling wireframe within a loop results
into an empty window(s)

#generate some data
temp = expand.grid(A = 1:3,B = 1:3)
temp = cbind(temp, y1 = rnorm(9))
temp = cbind(temp, y2 = runif(9))


#plot y1 and y2 in two different windows for(i in 1:2) {
wireframe(y1 ~ A*B, temp, shade =T)
windows()
wireframe(y2 ~ A*B, temp, shade =T)
}


#However, calling it twice outside a loop works?

wireframe(y1 ~ A*B, temp, shade =T)
windows()
wireframe(y2 ~ A*B, temp, shade =T)


Obviously i'm missing something. How can i call wireframe more than one
time in a loop and get a wireframe?


Greetings

Thomas Roth

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Dit bericht en eventuele bijlagen geven enkel de visie van de schrijver weer 
en binden het INBO onder geen enkel beding, zolang dit bericht niet bevestigd is
door een geldig ondertekend document. The views expressed in  this message 
and any annex are purely those of the writer and may not be regarded as stating 
an official position of INBO, as long as the message is not confirmed by a duly 
signed document.





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[R] S4 Package with definition of method 'names'

2009-06-11 Thread Thomas Roth (geb. Kaliwe)

Dear List,

Is it possible to build a package with 'names' method for a S4-Class?

The following  works if directly pasted into R:
(a simple test class with 1 attribute that is returned by invoking 'names')


#class definition
setClass(test, representation = representation(name = character),
 prototype = prototype(name = thisIsMyName))

#definition of names for class test

setMethod(names, test, function(x)
{
 x...@name
}
)

#definition of names- for class test
setReplaceMethod(names, test, function(x, value)
{
x...@name - value
x
}
)


test = new(test)
names(test)  #returns thisIsMyName



However 'R CMD check ' for building a package fails with

Error in setMethod(f, signature, NULL, where = where) :
 the method for function names and signature = is sealed and cannot 
be re-defined
Calls: Anonymous ... sys.source - eval - eval - removeMethod - 
setMethod

Execution halted
make[2]: *** [lazyload] Error 1
make[1]: *** [all] Error 2
make: *** [pkg-DAP] Error 2



This is somewhat confusing since it works nicely if pasted into R.

Any Ideas

Thank you for your time

Thomas Roth

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Re: [R] Create Pie chart from .csv file

2009-05-05 Thread Thomas Roth (geb. Kaliwe)

Sorry for mailing to you personally...

for types

read.csv(file.choose())
freqTable = table(types)
pie(freqTable)


##example for some data
temp = data.frame(types = 1:10)
pie(table(temp))

Thomas Roth

PS: use barplot instead of pie

DonkeyRhubarb schrieb:

Hi all,

I am looking to create a pie chart from a given column in a .csv file. 


My class variables are as follows:

entry_type, uniquekey,  types, title,url, abstract, journal, 
author, month,
year, howpublished

So say I want to export a pie chart that groups together all  entries under
'types' e.g. 3 x statistics 2x education etc. Im looking to have a piechart
represent this graphically that shows which type of entry is in most
frequently. Preferably I'd like to export to a PDF chart and while I can do
this by typing variables directly into the R console, I cannot manage it
from a .csv file.

If you cannot help me with this specific problem, just knowing how to create
a generic pie chart would be a great help.

This is part of my final software project which is due in one week. I would
very much appreciate any help.

Many thanks in advance




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Re: [R] Import R-output into Java

2009-03-19 Thread Thomas Roth (geb. Kaliwe)

#I used sink
?sink


#Thomas



Maxl18 schrieb:

Hello,
I want to import R-output via Rserve to Java, especially for the function
ctree from the package party.
Rserve is working properly.

Yet, I only get the predictions with the Java code

   try{
   RConnection c = new RConnection();
   ...
   c.voidEval(modell - ctree(...));
   REXP y = c.eval(nodes(modell,1)[[1]]$prediction);
   ...
   }catch(Exception e){}

When I try to get the whole text with

   REXP z = c.eval(nodes(modell,1)[[1]]);
   System.out.println(z);

I get something like   
org.rosuda.rengine.rexpgenericvec...@119c082+[10]named


But I want the text which is printed in R.

What can I do?
Thanks, Max


Once again:
It`s clear to get the result in R but I don`t know hoe to get the R-output
into Java (or into a file, i.e. .txt)



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[R] S4 coerce as.data.frame for lm

2009-03-10 Thread Thomas Roth (geb. Kaliwe)

#Hi,
#
#For a given class test, an object of class test cannot be used as data 
in the lm method although as.data.frame was implemented... where's my 
mistake?

#
#Suppose i have defined a S4 class test

#S4 Class test containting a slot data
#which is of type data.frame

setClass(Class = test, representation = representation(name = 
character, data = data.frame)  


temp = new(test)   #temp is of class test

t...@data = faithful   #assign some data to it

#now define as.data.frame for class test
setMethod(as.data.frame, test, function(x, row.names = NULL, 
optional = FALSE)

{

 return(x...@data)

}
)

as.data.frame(temp)   #works

lm(eruptions ~ waiting, data = temp)   #doesn't work


#Thank you for any hints
#Thomas Roth



#from the lm help page
|#data| - an optional data frame, list or environment (or object 
coercible by |as.data.frame| to a data frame) containing the variables 
in the model. If not found in |data|, the variables are taken from 
|environment(formula)|, typically the #environment from which |lm| is 
called.


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[R] lattice: remove box around a wireframe

2009-03-04 Thread Thomas Roth (geb. Kaliwe)

#Hi,
#
#somebody knows how to  remove the outer box around a wireframe and 
reduce the height

#
#

test = data.frame(expand.grid(c(1:10), c(1:10)))
z = test[,1] + test[,2]
test = cbind(test, z)
names(test) = c(x, y, z)
require(lattice)
wireframe(z ~ x*y, data = test, par.box = c(col = transparent) )  #not 
this one but the remaining outer box.


Thanks in advance

Thomas Roth

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Re: [R] lattice: remove box around a wireframe

2009-03-04 Thread Thomas Roth (geb. Kaliwe)

:-) works!


Sundar Dorai-Raj schrieb:

(Sorry for the repeat. Forgot to copy R-help)

Try,

test = data.frame(expand.grid(c(1:10), c(1:10)))
z = test[,1] + test[,2]
test = cbind(test, z)
names(test) = c(x, y, z)
require(lattice)
wireframe(z ~ x*y, data = test,
 par.settings = list(axis.line = list(col = transparent)),
 par.box = c(col = transparent) )

--sundar

On Wed, Mar 4, 2009 at 8:17 AM, Thomas Roth (geb. Kaliwe)
hamstersqu...@web.de wrote:
  

#Hi,
#
#somebody knows how to  remove the outer box around a wireframe and reduce
the height
#
#

test = data.frame(expand.grid(c(1:10), c(1:10)))
z = test[,1] + test[,2]
test = cbind(test, z)
names(test) = c(x, y, z)
require(lattice)
wireframe(z ~ x*y, data = test, par.box = c(col = transparent) )  #not
this one but the remaining outer box.

Thanks in advance

Thomas Roth

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Re: [R] Help on BarPlot

2009-02-10 Thread Thomas Roth (geb. Kaliwe)

Hi,

#There are a lot of examples for barplot if you just type

example(barplot)

# i altered one slightly to put the values on top of each bar

mp - barplot(VADeaths) # default
#tot - colMeans(VADeaths)   #changed this line
tot = colSums(VADeaths)#wether you need max, min, mean , colSums 
will depend on your data

text(mp, tot + 4, format(tot), xpd = TRUE, col = blue)


#you should be able to get it from here


Thomas




Steve Sidney schrieb:

Dear all

As a new user of R, can someone please help me with the following

I have created a programme to analyse laboratory data and one of the graphs is 
a bar plot of 'Z' scores.

On the bar plot I am using the following line to plot some results

 barplot (zb[,c(ZBW)], ylim = c(-6,6), names.arg=zb[,c(LabNo)],xlab=Lab Code 
Number, cex.names = .5 , axis.lty=1 , main =  Total Coliform )

What I would like to do is move the xlab parameter to sit on top or on each bar 
and not on the x-axis at y=0.

Any help would be appreciated.

Thanks

Steve
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Re: [R] plot Ticks

2009-01-27 Thread Thomas Roth (geb. Kaliwe)

you could set them manually, if thats what you're looking for

plot(1:10, axes = F)
axis(1, at = seq(1,10 , length = 3))

mau...@alice.it schrieb:

Is there a way to force the number of ticks along an axis ?
I read the on-line documentation and tried many combinations of all available 
parameters from functions
par(), axTicks(), axis(), plot() ... but no luck !

Thank you very much,
Maura


tutti i telefonini TIM!


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Re: [R] Tinn-R

2009-01-26 Thread Thomas Roth (geb. Kaliwe)
First thing you need to do is, save the file with an .r ending. Tinn-R 
will then come up with syntax highlighting (as far as i remember).


Options-Main-Application   leads you to the r-configuration...

HTH
Thomas

Tibert, Brock schrieb:

Tibert, Brock schrieb:

Hi Everyone,

I was hoping someone could help me with the settings for Tinn-R.  I see in the 
screen shots that it has syntax help, or something similar (tips on what 
functions, etc).  I can not seem to get this to turn on in the program, and I 
am wondering if I have to set up a few options.   I quickly read through the 
help and could not figure it out.

Many thanks!

- Brock

P.S.  It appears as if Tinn-R is widely used, but would you recommend something 
different?  I am new to R and programming, but have learned (somewhat) using 
VBA editors I have grown to love to the intelligent typing that goes along with 
it.

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