Re: [R] Comparison of vectors in a matrix
Yes, thanks for this, this is exactly what I want to do. However, I have a remaining problem which is how to get R to understand that each entry in my matrix is a vector of names. I have been trying to import my text file with the names in each vector of names enclosed in quotes and separated by commas, or separated by spaces, or without quotes, etc, with no luck. Everytime, R seems to consider the vector of names as just one long name. In my first colum, for example, I have henry, in the second, mary, ruth, and in the third mary, joseph, and I have no idea how to get R to see that mary, ruth, for example, is composed of two strings of text, rather than just one. Thanks for any further help! http://old.nabble.com/file/p26305756/ffoexample.txt ffoexample.txt Tony Plate wrote: Nice problem! If I understand you correctly, here's how to do it (with list-based matrices): set.seed(1) (x - matrix(lapply(rpois(10,2)+1, function(k) sample(letters[1:10], size=k)), ncol=2, dimnames=list(1:5,c(A,B A B 1 Character,2 Character,5 2 Character,2 Character,5 3 Character,3 Character,3 4 Character,5 Character,3 5 Character,2 i x[1,1] [[1]] [1] c b x[1,2] [[1]] [1] c d a j f (y - cbind(x, A-B=apply(x, 1, function(ab) setdiff(ab[[1]], ab[[2]] A B A-B 1 Character,2 Character,5 b 2 Character,2 Character,5 g 3 Character,3 Character,3 Character,3 4 Character,5 Character,3 Character,2 5 Character,2 i Character,2 y[1,3] [[1]] [1] b -- Tony Plate esterhazy wrote: Hi, I have a matrix with two columns, and the elements of the matrix are vectors. So for example, in line 3 of column 1 I have a vector v31=(marc, robert, marie). What I need to do is to compare all vectors in column 1 and 2, so as to get, for example setdiff(v31,v32) into a new column. Is there a way to do this in R? Thanks! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://old.nabble.com/Comparison-of-vectors-in-a-matrix-tp26284855p26305756.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Comparison of vectors in a matrix
On Nov 11, 2009, at 1:02 PM, esterhazy wrote: Yes, thanks for this, this is exactly what I want to do. However, I have a remaining problem which is how to get R to understand that each entry in my matrix is a vector of names. I have been trying to import my text file with the names in each vector of names enclosed in quotes and separated by commas, or separated by spaces, or without quotes, etc, with no luck. Those are all subsumed under the R whitespace separators that scan and the read.* functions use by default. Everytime, R seems to consider the vector of names as just one long name. In my first colum, for example, I have henry, in the second, mary, ruth, and in the third mary, joseph, and I have no idea how to get R to see that mary, ruth, for example, is composed of two strings of text, rather than just one. Thanks for any further help! http://old.nabble.com/file/p26305756/ffoexample.txt ffoexample.txt I copied and pasted into a textConnection: lines - readLines(textConnection(usernamefriends friendof + 26376 paradisacorbasi zannechaos filmstarusa jelliclecat status jennilee_rose obiwaynekenobi shaycaron jillthepill 26376 witchy1 jumbach oscarwinner slai jenniebennie tirwen estall bront zarchasmpgmr pink_kimono reidzilla miz_anneliese ambelies jrianne henry3730 thufer_hawat mom2bunky venaeli grbenda ikkin56 paradisacorbasi filmstarusa jelliclecat jennilee_rose shaycaron jillthepill 26376 witchy1 jumbach oscarwinner tirwen estall bront zarchasmpgmr pink_kimono reidzilla miz_anneliese ambelies jrianne henry3730 ahahaha_ha thufer_hawat mom2bunky venaeli grbenda donna_stewart gjanyn + aaandy ma monotony porcelian abrokenstarr seraphimsigrist ballena cbaqir _cassyandra darkspree erishkigal pinkdevildances lightning_geek a_life_verbatim frozen_wishes lijago tindernight crashing_angel sabrina_g giggly_teapot smarties_2087 theinimitable_l african_sunset sirenlunaris eagan_bryhtm robomonkeyninja maid_ov_metal aubloomiel countdownish queennola pearl007 princess_macaw wolfie_sara gypsy_jack may_cash morningchorus vanityflair lyingpeacefully squashedfrogs d_e_r_v_i_s_h the_koira lakshmichithra muffinbits amaya_aneko jenikaandzhaodi blood_gypsy aura_oneill icemodeled wannabesnorlax2 ma frida monotony porcelian abrokenstarr seraphimsigrist ballena cbaqir _cassyandra shepardshadows darkspree erishkigal pinkdevildances lightning_geek a_life_verbatim frozen_wishes lijago tindernight crashing_angel sabrina_g giggly_teapot laudanum_tea smarties_2087 theinimitable_l african_sunset sirenlunaris eagan_bryhtm robomonkeyninja aaskie maid_ov_metal aubloomiel countdownish queennola pearl007 princess_macaw wolfie_sara gypsy_jack may_cash morningchorus vanityflair lyingpeacefully squashedfrogs d_e_r_v_i_s_h the_koira lakshmichithra muffinbits amaya_aneko jenikaandzhaodi blood_gypsy aura_oneill icemodeled sixtycents wannabesnorlax2)) #realLines will bring in everything up to an EOL. # and then used scan() on the individual lines: col1 - scan(textConnection(lines[1]), what=character) Read 3 items col1 [1] username friends friendof col2 - scan(textConnection(lines[2]), what=character) Read 58 items col3 - scan(textConnection(lines[3]), what=character) Read 102 items I have not figured out what you and Tony are doing with these collections of character vectors, but this should help with you doing the basic data entry. Tony Plate wrote: Nice problem! If I understand you correctly, here's how to do it (with list-based matrices): set.seed(1) (x - matrix(lapply(rpois(10,2)+1, function(k) sample(letters[1:10], size=k)), ncol=2, dimnames=list(1:5,c(A,B A B 1 Character,2 Character,5 2 Character,2 Character,5 3 Character,3 Character,3 4 Character,5 Character,3 5 Character,2 i x[1,1] [[1]] [1] c b x[1,2] [[1]] [1] c d a j f (y - cbind(x, A-B=apply(x, 1, function(ab) setdiff(ab[[1]], ab[[2]] A B A-B 1 Character,2 Character,5 b 2 Character,2 Character,5 g 3 Character,3 Character,3 Character,3 4 Character,5 Character,3 Character,2 5 Character,2 i Character,2 y[1,3] [[1]] [1] b -- Tony Plate esterhazy wrote: Hi, I have a matrix with two columns, and the elements of the matrix are vectors. So for example, in line 3 of column 1 I have a vector v31=(marc, robert, marie). What I need to do is to compare all vectors in column 1 and 2, so as to get, for example setdiff(v31,v32) into a new column. Is there a way to do this in R? Thanks! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context:
Re: [R] Comparison of vectors in a matrix
This is a tricky data entry problem. The right technique will depend on the fine details of the
data, and it's not clear what those are. E.g., when you say In my first column, for example,
I have henry , it's unclear to me whether or not the double quotes are part of
the data or not - which is why it's nice to provide reproducible examples.
But, if you do have quoted strings in your data fields as they exist in an R
matrix, you can do something like the following:
# each element of the matrix x contains one or more quoted strings, separated
by commas
x - matrix(c('a, b', 'c', 'b', 'd'), ncol=2, dimnames=list(c(row1, row2),
c(X,Y)))
x
X Y
row1 \a\, \b\ \b\
row2 \c\\d\
# use R's parsing and evaluation to turn 'a, b' into c(a, b), and turn
that
# into a matrix containing character vectors of various lengths.
matrix(lapply(parse(text=paste(c(, x, ))), eval), ncol=ncol(x),
dimnames=dimnames(x))
X Y
row1 Character,2 b
row2 c d
- Tony Plate
esterhazy wrote:
Yes, thanks for this, this is exactly what I want to do.
However, I have a remaining problem which is how to get R to understand that
each entry in my matrix is a vector of names.
I have been trying to import my text file with the names in each vector of
names enclosed in quotes and separated by commas, or separated by spaces, or
without quotes, etc, with no luck.
Everytime, R seems to consider the vector of names as just one long name.
In my first colum, for example, I have henry, in the second, mary,
ruth, and in the third mary, joseph, and I have no idea how to get R
to see that mary, ruth, for example, is composed of two strings of text,
rather than just one.
Thanks for any further help!
http://old.nabble.com/file/p26305756/ffoexample.txt ffoexample.txt
Tony Plate wrote:
Nice problem!
If I understand you correctly, here's how to do it (with list-based
matrices):
set.seed(1)
(x - matrix(lapply(rpois(10,2)+1, function(k) sample(letters[1:10],
size=k)), ncol=2, dimnames=list(1:5,c(A,B
A B
1 Character,2 Character,5
2 Character,2 Character,5
3 Character,3 Character,3
4 Character,5 Character,3
5 Character,2 i
x[1,1]
[[1]]
[1] c b
x[1,2]
[[1]]
[1] c d a j f
(y - cbind(x, A-B=apply(x, 1, function(ab) setdiff(ab[[1]],
ab[[2]]
A B A-B
1 Character,2 Character,5 b
2 Character,2 Character,5 g
3 Character,3 Character,3 Character,3
4 Character,5 Character,3 Character,2
5 Character,2 i Character,2
y[1,3]
[[1]]
[1] b
-- Tony Plate
esterhazy wrote:
Hi,
I have a matrix with two columns, and the elements of the matrix are
vectors.
So for example, in line 3 of column 1 I have a vector v31=(marc,
robert,
marie).
What I need to do is to compare all vectors in column 1 and 2, so as to
get,
for example setdiff(v31,v32) into a new column.
Is there a way to do this in R?
Thanks!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Comparison of vectors in a matrix
That is wonderful, now I think I am all set! Thanks again!
Tony Plate wrote:
This is a tricky data entry problem. The right technique will depend on
the fine details of the data, and it's not clear what those are. E.g.,
when you say In my first column, for example, I have henry , it's
unclear to me whether or not the double quotes are part of the data or not
- which is why it's nice to provide reproducible examples.
But, if you do have quoted strings in your data fields as they exist in an
R matrix, you can do something like the following:
# each element of the matrix x contains one or more quoted strings,
separated by commas
x - matrix(c('a, b', 'c', 'b', 'd'), ncol=2,
dimnames=list(c(row1, row2), c(X,Y)))
x
X Y
row1 \a\, \b\ \b\
row2 \c\\d\
# use R's parsing and evaluation to turn 'a, b' into c(a, b), and
turn that
# into a matrix containing character vectors of various lengths.
matrix(lapply(parse(text=paste(c(, x, ))), eval), ncol=ncol(x),
dimnames=dimnames(x))
X Y
row1 Character,2 b
row2 c d
- Tony Plate
esterhazy wrote:
Yes, thanks for this, this is exactly what I want to do.
However, I have a remaining problem which is how to get R to understand
that
each entry in my matrix is a vector of names.
I have been trying to import my text file with the names in each vector
of
names enclosed in quotes and separated by commas, or separated by spaces,
or
without quotes, etc, with no luck.
Everytime, R seems to consider the vector of names as just one long name.
In my first colum, for example, I have henry, in the second, mary,
ruth, and in the third mary, joseph, and I have no idea how to get
R
to see that mary, ruth, for example, is composed of two strings of
text,
rather than just one.
Thanks for any further help!
http://old.nabble.com/file/p26305756/ffoexample.txt ffoexample.txt
Tony Plate wrote:
Nice problem!
If I understand you correctly, here's how to do it (with list-based
matrices):
set.seed(1)
(x - matrix(lapply(rpois(10,2)+1, function(k) sample(letters[1:10],
size=k)), ncol=2, dimnames=list(1:5,c(A,B
A B
1 Character,2 Character,5
2 Character,2 Character,5
3 Character,3 Character,3
4 Character,5 Character,3
5 Character,2 i
x[1,1]
[[1]]
[1] c b
x[1,2]
[[1]]
[1] c d a j f
(y - cbind(x, A-B=apply(x, 1, function(ab) setdiff(ab[[1]],
ab[[2]]
A B A-B
1 Character,2 Character,5 b
2 Character,2 Character,5 g
3 Character,3 Character,3 Character,3
4 Character,5 Character,3 Character,2
5 Character,2 i Character,2
y[1,3]
[[1]]
[1] b
-- Tony Plate
esterhazy wrote:
Hi,
I have a matrix with two columns, and the elements of the matrix are
vectors.
So for example, in line 3 of column 1 I have a vector v31=(marc,
robert,
marie).
What I need to do is to compare all vectors in column 1 and 2, so as to
get,
for example setdiff(v31,v32) into a new column.
Is there a way to do this in R?
Thanks!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
View this message in context:
http://old.nabble.com/Comparison-of-vectors-in-a-matrix-tp26284855p26306896.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Comparison of vectors in a matrix
Hi, I have a matrix with two columns, and the elements of the matrix are vectors. So for example, in line 3 of column 1 I have a vector v31=(marc, robert, marie). What I need to do is to compare all vectors in column 1 and 2, so as to get, for example setdiff(v31,v32) into a new column. Is there a way to do this in R? Thanks! -- View this message in context: http://old.nabble.com/Comparison-of-vectors-in-a-matrix-tp26284855p26284855.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Comparison of vectors in a matrix
Nice problem! If I understand you correctly, here's how to do it (with list-based matrices): set.seed(1) (x - matrix(lapply(rpois(10,2)+1, function(k) sample(letters[1:10], size=k)), ncol=2, dimnames=list(1:5,c(A,B A B 1 Character,2 Character,5 2 Character,2 Character,5 3 Character,3 Character,3 4 Character,5 Character,3 5 Character,2 i x[1,1] [[1]] [1] c b x[1,2] [[1]] [1] c d a j f (y - cbind(x, A-B=apply(x, 1, function(ab) setdiff(ab[[1]], ab[[2]] A B A-B 1 Character,2 Character,5 b 2 Character,2 Character,5 g 3 Character,3 Character,3 Character,3 4 Character,5 Character,3 Character,2 5 Character,2 i Character,2 y[1,3] [[1]] [1] b -- Tony Plate esterhazy wrote: Hi, I have a matrix with two columns, and the elements of the matrix are vectors. So for example, in line 3 of column 1 I have a vector v31=(marc, robert, marie). What I need to do is to compare all vectors in column 1 and 2, so as to get, for example setdiff(v31,v32) into a new column. Is there a way to do this in R? Thanks! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
