Re: [R] How can I estimate a Box-Cox function with R?

2009-05-22 Thread Ikerne del Valle



	Thanks Gregory. I see that that with 
boxcox.lm() the optimal lambda is obtained and 
plotted against log-likelihood.


library(MASS)
boxcox(Volume ~ log(Height) + log(Girth), data = trees,
   lambda = seq(-0.25, 0.25, length = 10))

But has how can I see the fit of the same linear 
model with the optimal BoxCox transformation, the 
standard error for lambda etc.?


Best. Ikerne.



Have you looked at the boxcox function in the 
MASS package?  That may do what you want.


--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111



 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Ikerne del Valle
 Sent: Thursday, May 21, 2009 4:29 AM
 To: fernando.tus...@ehu.es

  Cc: r-help@r-project.org

 Subject: [R] How can I estimate a Box-Cox function with R?


Dear Fernando and all:

Thanks for your help. Now works. This is
 a training example to learn how to estimate a
 Box-Cox (right and/or left side transformations)
 with R (as LIMDEP does) in order to compare these
 estimations with the ones derived by applying
 NLS, ones the dependent variable has been divided
 by its geometric mean (see below) as suggested by
 (Zarembka (1974) and Spitzer (1984). However the
 example of the demand of money seems not to work.
 Any idea to face the error messages or how to
 estimate a Box-Cox function with R?

Best regards,
Ikerne

 library(nlrwr)
 r-
 c(4.50,4.19,5.16,5.87,5.95,4.88,4.50,6.44,7.83,6.25,5.50,5.46,7.46,10.2
 8,11.77,13.42,11.02,8.50,8.80,7.69)
 Lr-log(r)
 M-
 c(480.00,524.30,566.30,589.50,628.20,712.80,805.20,861.00,908.40,1023.1
 0,1163.60,1286.60,1388.90,1497.90,1631.40,1794.40,1954.90,2188.80,2371.
 70,2563.60)
 LM-log(M)
 Y-
 c(2208.30,2271.40,2365.60,2423.30,2416.20,2484.80,2608.50,2744.10,2729.
 30,2695.00,2826.70,2958.60,3115.20,3192.40,3187.10,3248.80,3166.00,3277
 .70,3492.00,3573.50)
 LY-log(Y)
 gmM-exp((1/20)*sum(LM))
 GM-M/gmM
 Gr-r/gmM
 GY-Y/gmM
 money-data.frame(r,M,Y,Lr,LM,LY,GM,Gr,GY)
 attach(money)
 ols1-lm(GM~r+Y)
 output1-summary(ols1)
 coef1-ols1$coefficients
 a1-coef1[[1]]
 b11-coef1[[2]]
 b21-coef1[[3]]
 ols2-lm(GM~Gr+GY)
 output2-summary(ols2)
 coef2-ols2$coefficients
 a2-coef2[[1]]
 b12-coef2[[2]]
 b22-coef2[[3]]
 money.m1-
 nls(GM~a+b*r^g+c*Y^g,data=money,start=list(a=a1,b=b11,g=1,c=b21))
 money.m2-
 nls(GM~a+b*Gr^g+c*GY^g,data=money,start=list(a=a2,b=b12,g=1,c=b22))


Ikerne del Valle Erkiaga
Department of Applied Economics V
Faculty of Economic and Business Sciences
University of the Basque Country
Avda. Lehendakari Agirre, Nº 83
48015 Bilbao (Bizkaia) Spain

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.


__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] How can I estimate a Box-Cox function with R?

2009-05-21 Thread Ikerne del Valle


Dear Fernando and all:

	Thanks for your help. Now works. This is 
a training example to learn how to estimate a 
Box-Cox (right and/or left side transformations) 
with R (as LIMDEP does) in order to compare these 
estimations with the ones derived by applying 
NLS, ones the dependent variable has been divided 
by its geometric mean (see below) as suggested by 
(Zarembka (1974) and Spitzer (1984). However the 
example of the demand of money seems not to work. 
Any idea to face the error messages or how to 
estimate a Box-Cox function with R?


Best regards,
Ikerne

library(nlrwr)
r-c(4.50,4.19,5.16,5.87,5.95,4.88,4.50,6.44,7.83,6.25,5.50,5.46,7.46,10.28,11.77,13.42,11.02,8.50,8.80,7.69)
Lr-log(r)
M-c(480.00,524.30,566.30,589.50,628.20,712.80,805.20,861.00,908.40,1023.10,1163.60,1286.60,1388.90,1497.90,1631.40,1794.40,1954.90,2188.80,2371.70,2563.60)
LM-log(M)
Y-c(2208.30,2271.40,2365.60,2423.30,2416.20,2484.80,2608.50,2744.10,2729.30,2695.00,2826.70,2958.60,3115.20,3192.40,3187.10,3248.80,3166.00,3277.70,3492.00,3573.50)
LY-log(Y)
gmM-exp((1/20)*sum(LM))
GM-M/gmM
Gr-r/gmM
GY-Y/gmM
money-data.frame(r,M,Y,Lr,LM,LY,GM,Gr,GY)
attach(money)
ols1-lm(GM~r+Y)
output1-summary(ols1)
coef1-ols1$coefficients
a1-coef1[[1]]
b11-coef1[[2]]
b21-coef1[[3]]
ols2-lm(GM~Gr+GY)
output2-summary(ols2)
coef2-ols2$coefficients
a2-coef2[[1]]
b12-coef2[[2]]
b22-coef2[[3]]
money.m1-nls(GM~a+b*r^g+c*Y^g,data=money,start=list(a=a1,b=b11,g=1,c=b21))
money.m2-nls(GM~a+b*Gr^g+c*GY^g,data=money,start=list(a=a2,b=b12,g=1,c=b22))


Ikerne del Valle Erkiaga
Department of Applied Economics V
Faculty of Economic and Business Sciences
University of the Basque Country
Avda. Lehendakari Agirre, Nº 83
48015 Bilbao (Bizkaia) Spain

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] How can I estimate a Box-Cox function with R?

2009-05-21 Thread Greg Snow
Have you looked at the boxcox function in the MASS package?  That may do what 
you want.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Ikerne del Valle
 Sent: Thursday, May 21, 2009 4:29 AM
 To: fernando.tus...@ehu.es
 Cc: r-help@r-project.org
 Subject: [R] How can I estimate a Box-Cox function with R?
 
 
   Dear Fernando and all:
 
   Thanks for your help. Now works. This is
 a training example to learn how to estimate a
 Box-Cox (right and/or left side transformations)
 with R (as LIMDEP does) in order to compare these
 estimations with the ones derived by applying
 NLS, ones the dependent variable has been divided
 by its geometric mean (see below) as suggested by
 (Zarembka (1974) and Spitzer (1984). However the
 example of the demand of money seems not to work.
 Any idea to face the error messages or how to
 estimate a Box-Cox function with R?
 
   Best regards,
   Ikerne
 
 library(nlrwr)
 r-
 c(4.50,4.19,5.16,5.87,5.95,4.88,4.50,6.44,7.83,6.25,5.50,5.46,7.46,10.2
 8,11.77,13.42,11.02,8.50,8.80,7.69)
 Lr-log(r)
 M-
 c(480.00,524.30,566.30,589.50,628.20,712.80,805.20,861.00,908.40,1023.1
 0,1163.60,1286.60,1388.90,1497.90,1631.40,1794.40,1954.90,2188.80,2371.
 70,2563.60)
 LM-log(M)
 Y-
 c(2208.30,2271.40,2365.60,2423.30,2416.20,2484.80,2608.50,2744.10,2729.
 30,2695.00,2826.70,2958.60,3115.20,3192.40,3187.10,3248.80,3166.00,3277
 .70,3492.00,3573.50)
 LY-log(Y)
 gmM-exp((1/20)*sum(LM))
 GM-M/gmM
 Gr-r/gmM
 GY-Y/gmM
 money-data.frame(r,M,Y,Lr,LM,LY,GM,Gr,GY)
 attach(money)
 ols1-lm(GM~r+Y)
 output1-summary(ols1)
 coef1-ols1$coefficients
 a1-coef1[[1]]
 b11-coef1[[2]]
 b21-coef1[[3]]
 ols2-lm(GM~Gr+GY)
 output2-summary(ols2)
 coef2-ols2$coefficients
 a2-coef2[[1]]
 b12-coef2[[2]]
 b22-coef2[[3]]
 money.m1-
 nls(GM~a+b*r^g+c*Y^g,data=money,start=list(a=a1,b=b11,g=1,c=b21))
 money.m2-
 nls(GM~a+b*Gr^g+c*GY^g,data=money,start=list(a=a2,b=b12,g=1,c=b22))
 
 
   Ikerne del Valle Erkiaga
   Department of Applied Economics V
   Faculty of Economic and Business Sciences
   University of the Basque Country
   Avda. Lehendakari Agirre, Nº 83
   48015 Bilbao (Bizkaia) Spain
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.