[R] R PLS package data format
Dear sir, If I have a vector as: y - c(1:4) and a matrix as: x - matrix (5:12, nrow=4, ncol=2) Then I create a data frame as: t - data.frame(y, x) R will generate a data frame of 3 columns names(t) y X1 X2 is.vector(t$X1) returns TRUE is.vector(t$X2) returns TRUE R splits the columns of a matrix into column vectors automatically. How should I create a data frame of t$y t$x such that is.vector(t$y) returns TRUE is.matrix(t$x) returns TRUE That is, how to make x column of the data frame a matrix? Just like the test data ¡§gasoline¡¨ in your PLS package: library(pls) data(yarn) is.vector(density) returns TRUE is.matrix(NIR) returns TURE (NIR is a matrix) Best regards, Shaowen Cheng The information in this e-mail may be confidential; it is intended for use solely by the individual or entity named as the recipient hereof. Disclosure, copying, distribution, or use of the contents of this e-mail by persons other than the intended recipient may violate applicable laws and if you have received this e-mail in error, please delete the original message and notify us by collect call immediately. Thank you. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R PLS package data format
hi, because of my ignorance I can't figure out why would you need such a structure. However the following trick works: a - matrix(1:6,3) b - data.frame(1:3) b$a - a b X1.3 a.1 a.2 11 1 4 22 2 5 33 3 6 names(b) [1] X1.3 a class(b$a) [1] matrix is.matrix(b$a) [1] TRUE hope that's help PF 2011/6/27 新鼎-智慧製造事業處-鄭紹文 shaowench...@acs.com.tw: Dear sir, If I have a vector as: y - c(1:4) and a matrix as: x - matrix (5:12, nrow=4, ncol=2) Then I create a data frame as: t - data.frame(y, x) R will generate a data frame of 3 columns names(t) y X1 X2 is.vector(t$X1) returns TRUE is.vector(t$X2) returns TRUE R splits the columns of a matrix into column vectors automatically. How should I create a data frame of t$y t$x such that is.vector(t$y) returns TRUE is.matrix(t$x) returns TRUE That is, how to make x column of the data frame a matrix? Just like the test data ¨gasoline〃 in your PLS package: library(pls) data(yarn) is.vector(density) returns TRUE is.matrix(NIR) returns TURE (NIR is a matrix) Best regards, Shaowen Cheng The information in this e-mail may be confidential; it is intended for use solely by the individual or entity named as the recipient hereof. Disclosure, copying, distribution, or use of the contents of this e-mail by persons other than the intended recipient may violate applicable laws and if you have received this e-mail in error, please delete the original message and notify us by collect call immediately. Thank you. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- +--- | Patrizio Frederic, | http://www.economia.unimore.it/frederic_patrizio/ +--- __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R PLS package data format
On 2011-06-27 03:02, 新鼎-智慧製造事業處-鄭紹文 wrote:
Dear sir,
If I have a vector as:
y- c(1:4)
and a matrix as:
x- matrix (5:12, nrow=4, ncol=2)
Then I create a data frame as:
t- data.frame(y, x)
R will generate a data frame of 3 columns
names(t)
y X1 X2
is.vector(t$X1) returns TRUE
is.vector(t$X2) returns TRUE
R splits the columns of a matrix into column vectors automatically.
How should I create a data frame of t$y t$x such that
is.vector(t$y) returns TRUE
is.matrix(t$x) returns TRUE
That is, how to make x column of the data frame a matrix? Just like the test
data ¡§gasoline¡¨ in your PLS package:
library(pls)
data(yarn)
is.vector(density) returns TRUE
is.matrix(NIR) returns TURE (NIR is a matrix)
This is all perfectly well described in ?data.frame where
you will also find reference to the use of I() to
accomplish your goal.
Peter Ehlers
Best regards,
Shaowen Cheng
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