Re: [R] Reverse seq

2008-03-31 Thread Chuck Cleland
On 3/31/2008 6:31 AM, Mario Maiworm wrote:
 Hi all,
 I thought I was not SUCH a nooby:) 
 How can I reverse a sequence/ vector?
 i.e., turn 
 X - 3 5 4 2 6 5 4 3 6
 Into 
 X - 6 3 4 5 6 2 4 5 3
 I mean without looping and indexing.
 There should be a very easy solution, shouldn't it?

  rev(X)
[1] 6 3 4 5 6 2 4 5 3

?rev

 Mario
 
 
 __
 
 Mario Maiworm
 Biological Psychology and Neuropsychology
 University of Hamburg
 Von-Melle-Park 11
 D-20146 Hamburg
 
 Phone: +49 40 42838 3515
 Fax: +49 40 42838 6591
 
 http://bpn.uni-hamburg.de/Maiworm_e.html
 http://cinacs.org
 
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-- 
Chuck Cleland, Ph.D.
NDRI, Inc. (www.ndri.org)
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New York, NY 10010
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R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] Reverse seq

2008-03-31 Thread Mario Maiworm
Hi all,
I thought I was not SUCH a nooby:) 
How can I reverse a sequence/ vector?
i.e., turn 
X - 3 5 4 2 6 5 4 3 6
Into 
X - 6 3 4 5 6 2 4 5 3
I mean without looping and indexing.
There should be a very easy solution, shouldn't it?

Mario


__

Mario Maiworm
Biological Psychology and Neuropsychology
University of Hamburg
Von-Melle-Park 11
D-20146 Hamburg

Phone: +49 40 42838 3515
Fax: +49 40 42838 6591

http://bpn.uni-hamburg.de/Maiworm_e.html
http://cinacs.org

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.