Re: [R] Repeat the first day data through all the day. Zoo
On Wed, Aug 25, 2010 at 7:43 AM, skan juanp...@gmail.com wrote: I have a zoo series. It lasts 10 years and its frequency is 15min. I'd like to get a new zoo series (or vector) with the same number of elements, whith each element equal to the first element of the day. That's, The first element everyday is repeated throughout the wole day. This is not same as aggregate(originalseries,as.Date,head,1) because this gives a vector with just one element for each day. Try ave: library(zoo) library(chron) zz - z - zoo(1:100, chron(0:9/5)) zz[] - ave(coredata(z), as.Date(time(z)), FUN = function(x) head(x, 1)) cbind(z, zz) z zz (01/01/70 00:00:00) 1 1 (01/01/70 04:48:00) 2 1 (01/01/70 09:36:00) 3 1 (01/01/70 14:24:00) 4 1 (01/01/70 19:12:00) 5 1 (01/02/70 00:00:00) 6 6 (01/02/70 04:48:00) 7 6 (01/02/70 09:36:00) 8 6 (01/02/70 14:24:00) 9 6 (01/02/70 19:12:00) 10 6 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Repeat the first day data through all the day. Zoo
On Wed, Aug 25, 2010 at 7:56 AM, Gabor Grothendieck ggrothendi...@gmail.com wrote: On Wed, Aug 25, 2010 at 7:43 AM, skan juanp...@gmail.com wrote: I have a zoo series. It lasts 10 years and its frequency is 15min. I'd like to get a new zoo series (or vector) with the same number of elements, whith each element equal to the first element of the day. That's, The first element everyday is repeated throughout the wole day. This is not same as aggregate(originalseries,as.Date,head,1) because this gives a vector with just one element for each day. Try ave: library(zoo) library(chron) zz - z - zoo(1:100, chron(0:9/5)) That should have been 10, not 100; however, it ignored 11:100 so the answer is the same. zz[] - ave(coredata(z), as.Date(time(z)), FUN = function(x) head(x, 1)) cbind(z, zz) z zz (01/01/70 00:00:00) 1 1 (01/01/70 04:48:00) 2 1 (01/01/70 09:36:00) 3 1 (01/01/70 14:24:00) 4 1 (01/01/70 19:12:00) 5 1 (01/02/70 00:00:00) 6 6 (01/02/70 04:48:00) 7 6 (01/02/70 09:36:00) 8 6 (01/02/70 14:24:00) 9 6 (01/02/70 19:12:00) 10 6 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Repeat the first day data through all the day. Zoo
On Wed, Aug 25, 2010 at 7:43 AM, skan juanp...@gmail.com wrote: down vote favorite Hello I have a zoo series. It lasts 10 years and its frequency is 15min. I'd like to get a new zoo series (or vector) with the same number of elements, whith each element equal to the first element of the day. That's, The first element everyday is repeated throughout the wole day. This is not same as aggregate(originalseries,as.Date,head,1) because this gives a vector with just one element for each day. cheers Here are a few more solutions too: library(zoo) library(chron) z - zoo(1:10, chron(0:9/5)) # aggregate / na.locf z.ag - aggregate(z, as.Date, head, 1) na.locf(z.ag, xout = time(z)) # duplicated / na.locf z.na - ifelse.zoo(!duplicated(as.Date(time(z))), z, NA) na.locf(z.na) # ave - as before zz - z zz[] - ave(coredata(z), as.Date(time(z)), FUN = function(x) head(x, 1)) zz __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Repeat the first day data through all the day. Zoo
thanks I'll try them, Why do you use the brackets in zz[] ? -- View this message in context: http://r.789695.n4.nabble.com/Repeat-the-first-day-data-through-all-the-day-Zoo-tp2338069p2338266.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Repeat the first day data through all the day. Zoo
On Wed, Aug 25, 2010 at 9:48 AM, skan juanp...@gmail.com wrote: thanks I'll try them, Why do you use the brackets in zz[] ? So it stays a zoo object with the same index. We are only replacing the data part. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Repeat the first day data through all the day. Zoo
# duplicated / na.locf doesn't work it says Error in fix.by(by.x, x) : 'by' must specify valid column(s) if I use ifelse instead of ifelse.zoo it works but it gives me a non zoo vector. Myabe is because my zoo version is older. cheers -- View this message in context: http://r.789695.n4.nabble.com/Repeat-the-first-day-data-through-all-the-day-Zoo-tp2338069p2338409.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Repeat the first day data through all the day. Zoo
On Wed, Aug 25, 2010 at 11:18 AM, skan juanp...@gmail.com wrote: # duplicated / na.locf doesn't work it says Error in fix.by(by.x, x) : 'by' must specify valid column(s) if I use ifelse instead of ifelse.zoo it works but it gives me a non zoo vector. Myabe is because my zoo version is older. They all work: library(zoo) library(chron) z - zoo(1:10, chron(0:9/5)) # aggregate / na.locf z.ag - aggregate(z, as.Date, head, 1) na.locf(z.ag, xout = time(z)) (01/01/70 00:00:00) (01/01/70 04:48:00) (01/01/70 09:36:00) (01/01/70 14:24:00) 1 1 1 1 (01/01/70 19:12:00) (01/02/70 00:00:00) (01/02/70 04:48:00) (01/02/70 09:36:00) 1 6 6 6 (01/02/70 14:24:00) (01/02/70 19:12:00) 6 6 # duplicated / na.locf z.na - ifelse.zoo(!duplicated(as.Date(time(z))), z, NA) na.locf(z.na) (01/01/70 00:00:00) (01/01/70 04:48:00) (01/01/70 09:36:00) (01/01/70 14:24:00) 1 1 1 1 (01/01/70 19:12:00) (01/02/70 00:00:00) (01/02/70 04:48:00) (01/02/70 09:36:00) 1 6 6 6 (01/02/70 14:24:00) (01/02/70 19:12:00) 6 6 # ave - as before zz - z zz[] - ave(coredata(z), as.Date(time(z)), FUN = function(x) head(x, 1)) zz (01/01/70 00:00:00) (01/01/70 04:48:00) (01/01/70 09:36:00) (01/01/70 14:24:00) 1 1 1 1 (01/01/70 19:12:00) (01/02/70 00:00:00) (01/02/70 04:48:00) (01/02/70 09:36:00) 1 6 6 6 (01/02/70 14:24:00) (01/02/70 19:12:00) 6 6 packageDescription(zoo)$Version [1] 1.6-4 R.version.string [1] R version 2.11.1 Patched (2010-05-31 r52167) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
