Hi,
Try this,
files - paste(RA94010,1:3,sep=)
# or files - list.files(pattern = RA94010)
list.of.data - lapply(files, read.table, header=F)
# if required, collapse into a single data.frame
do.call(rbind, list.of.data)
HTH,
baptiste
2009/10/28 Sybille Wendel wendel.sybi...@googlemail.com:
Dear all,
I have a lot of data files (.txt) that I want to read in all at once, if
possible.
the files have names in time system. for example: RA940101, RA940102,
RA940103, RA940104 an so on.
(meaning: RA, year:91, month: here january, day of the month.)
I tried something like
vektor - c(RA940101,RA940102,RA940103)
for (x in 1:3)
{ data - read.table(paste(vektor[x],sep=),header=F) }
But how can I put the vektor on the left side, so that data would be instead
of data the three first days of the year 1994?
best wishes and thanks a lot for your answers,
Sybille
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.