[Vo]:translation of Parkhomov 3rd

2015-03-27 Thread Peter Gluck
with apologies for the delay had PC troubles, made blunders

http://egooutpeters.blogspot.ro/2015/03/parkhomovs-3rd-paper-text.html


Peter
-- 
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com


[Vo]:Parkhomov 3 translation text

2015-03-27 Thread Peter Gluck
see it attached, the paper is at
https://yadi.sk/i/zTRxBwVofYmaE

My text is not going with Blogger huge letters appear

I am asking the colleagues skilled to combine text and images.
 Peter

-- 
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com


AGP-3t.rtf
Description: RTF file


Re: [Vo]:translation of Parkhomov 3rd

2015-03-27 Thread Marcus Winckers
Could you have a look at conclusion 1.?
50 kWh is 180 mj.
Or 5 kWh is 18mj is 5 x 22 eurocent (electicity price) =1 euro= 0.5 liter
petrol.
Or am i missing ...

Marcus
Op 27 mrt. 2015 12:17 schreef Peter Gluck peter.gl...@gmail.com:

 with apologies for the delay had PC troubles, made blunders

 http://egooutpeters.blogspot.ro/2015/03/parkhomovs-3rd-paper-text.html


 Peter
 --
 Dr. Peter Gluck
 Cluj, Romania
 http://egooutpeters.blogspot.com



Re: [Vo]:translation of Parkhomov 3rd

2015-03-27 Thread Peter Gluck
you are right, the error is in the original

peter

On Fri, Mar 27, 2015 at 2:51 PM, Marcus Winckers marcki...@gmail.com
wrote:

 Could you have a look at conclusion 1.?
 50 kWh is 180 mj.
 Or 5 kWh is 18mj is 5 x 22 eurocent (electicity price) =1 euro= 0.5 liter
 petrol.
 Or am i missing ...

 Marcus
 Op 27 mrt. 2015 12:17 schreef Peter Gluck peter.gl...@gmail.com:

 with apologies for the delay had PC troubles, made blunders

 http://egooutpeters.blogspot.ro/2015/03/parkhomovs-3rd-paper-text.html


 Peter
 --
 Dr. Peter Gluck
 Cluj, Romania
 http://egooutpeters.blogspot.com




-- 
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com


[Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Jones Beene
The following is overly simplistic, but also surprisingly intuitive for a
particular hypothesis, so it is worth the effort to try to get down an
explanation for the Rossi/Parkhomov effect . one containing less than a
thousand words, by using a few images.

Here is an image of the Li-7 nucleus. Keep in mind the single tenet that
like-charges repel. In a small nucleus, and ignoring QM for a moment in
favor of macro geometrical restraints this means that nesting of nucleons
becomes complicated. since in the case of 3 protons, they must be kept apart
by neutrons.

http://www.lnhatom.com/Lithium%207.jpg

To oversimplify the point which will be made below: the red balls are the 3
protons, and they do not touch each other because the 4 neutrons form a
tetrahedron which effectively separates them, and a tetrahedron is an
especially stable geometry. Therefore, this isotope should be more stable
than one where like charges have the possibility of fleeting contact. In
fact, almost 93% of natural lithium is this particular isotope: Li7 despite
this isotope being a drip line anomaly in itself. 

That stable tetrahedral nesting arrangement at the core of Li7 is not the
case with lithium-6 however; and this nucleus becomes unstable, particularly
when stressed by incursion of positive charge (such as by the approach of a
proton). That is because the only stable geometry which we can visualize for
Li6 is to have a near-planar hexagonal arrangement of alternating neutrons
and protons, arranged somewhat like a benzene ring, which is not spherical
and not stable wrt the strong force:

https://dlnmh9ip6v2uc.cloudfront.net/assets/0/4/e/8/2/519fa09dce395f8b08
00.png
Therefore, a planar structure like the one above, when it is located inside
orbiting electrons is itself unstable, and the natural charge-equalizing
tendency is for the hexagonal plane to revert to something more compact,
like a sphere. Therefore on occasion, and as several papers are now
suggesting, the lithium-6 nucleus temporarily takes the form of 3 deuterons,
arranged in the X,Y  Z axes where the neutrons of each deuteron are in
contact. This is where Efimov state comes into play.

Now the visual image of greatest impact is to imagine the 3 deuterons
expressing the Efimov Halo Effect, which is state of oscillating balance
and Russian nesting dolls geometry as predicted by Efimov. This state
should function like a pump, among other possibilities.  But a pump for
what?

For those who suspect that the Dirac sea, as expressed in Don Hotson's many
papers, is accessible as a point source, then one suggestion is that the Li6
nucleus can act like a pump for something which is intrinsic to the Dirac
sea. and since epos are ruled out by the lack of observed radiation, then
that something is most likely spin, or a subset like angular momentum, or
a quantum of spin: a Dirac spinor, or something along those lines. 

Thus the Li6 nucleus would be the a gateway for spin energy coupling -
especially at a temperature where the 3-deuteron geometry is favored. This
temperature seems to be in the range of 1400K in the dogbone.

This hypothesis suggests that the key to the excess heat in dogbone-type
devices is lithium-6. The thermal anomaly will be maximized by enrichment in
the isotope, and should go away with all Li7. 

Thus, this hypothesis, despite being complicated in detail - is easily
falsifiable, unlike most of the other explanations floating around, which
generally fail due to the lack of observable high energy radiation. 






RE: [Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Jones Beene
Bob,

In general - the evidence says that there is an almost complete lack of high
energy radiation, or neutron activation, in the reported experiments even at
the kilowatt thermal level- this means that there are no neutrons, no fusion
and little transmutation (other than incidental). 

If any of these indicia were present, there would be substantial activation:
which would be proof. But there is none of this. It seem prudent to drop the
idea of nuclear fusion until there is minimal evidence that supports it. Now
it is simply a default position.

The path forward in RD is clear to me - construct two cells, one depleted
in Li7 and the other depleted in Li6. If there is no clear advantage to the
Li6, then this  hypothesis fails and another one must be found. Experiment
rules, and experiment says that there is no nuclear fusion.

Unfortunately, ORNL is quoting $35,000 gram for Li6. This is many times
higher - probably 100x higher than last year. It looks like politics has
become involved, and that there could be a high level effort to discourage
the use of Li6. Why?


From: Bob Cook 

Jones--
 
The Li-6 loves neutrons and will readily change to Li-7, if one is nearby.
It may be that the Li-6 acts as a catalyst to combine the charge of a proton
and an electron to form a neutron and He-5, which in turn gives up another
neutron and gets to He-4. The neutrons can then combine with most anything
to form an isotope up to Ni-62 with loss of mass along the way.  It will be
interesting to see what the isotopic analysis of Parkhomov's ash is.  It is
being evaluated currently.  We may see some Si-28 coming from Al-27
transmutation via the short-lived Al-28 isotope.  
 
Also, in thinking about the geometrical stability of the Li-7 and the lack
of the stability of Li-6.  I assume you envision a concentrated point charge
associated with the protons with respect to the geometry.
 
I for one do not think there is a segregation of charge within the nucleus,
but that the charge is spread  throughout the nucleus so as to eliminate
discontinuities at a 0 distance. Thus, variation in charge density within a
nucleus is nil. However the charge density shape can be modified by the
approach of other charges or electric or magnetic fields.  That is what
happens when Li-6 is hit with a gamma which causes it to breakup or activate
to a higher energy state--an isomer with an unstable charge density
configuration. 
 
Bob
 
 
 
 
- Original Message - 
From: Jones Beene mailto:jone...@pacbell.net  
To: vortex-l@eskimo.com 
Sent: Friday, March 27, 2015 8:07 AM
Subject: [Vo]:A picture is worth a thousand words, or maybe 10k

The following is overly simplistic, but also surprisingly intuitive for a
particular hypothesis, so it is worth the effort to try to get down an
explanation for the Rossi/Parkhomov effect ... one containing less than a
thousand words, by using a few images...
Here is an image of the Li-7 nucleus. Keep in mind the single tenet that
like-charges repel. In a small nucleus, and ignoring QM for a moment in
favor of macro geometrical restraints this means that nesting of nucleons
becomes complicated... since in the case of 3 protons, they must be kept
apart by neutrons.
http://www.lnhatom.com/Lithium%207.jpg
To oversimplify the point which will be made below: the red balls are the 3
protons, and they do not touch each other because the 4 neutrons form a
tetrahedron which effectively separates them, and a tetrahedron is an
especially stable geometry. Therefore, this isotope should be more stable
than one where like charges have the possibility of fleeting contact. In
fact, almost 93% of natural lithium is this particular isotope: Li7 despite
this isotope being a drip line anomaly in itself. 
That stable tetrahedral nesting arrangement at the core of Li7 is not the
case with lithium-6 however; and this nucleus becomes unstable, particularly
when stressed by incursion of positive charge (such as by the approach of a
proton). That is because the only stable geometry which we can visualize for
Li6 is to have a near-planar hexagonal arrangement of alternating neutrons
and protons, arranged somewhat like a benzene ring, which is not spherical
and not stable wrt the strong force:
https://dlnmh9ip6v2uc.cloudfront.net/assets/0/4/e/8/2/519fa09dce395f8b08
00.png
Therefore, a planar structure like the one above, when it is located inside
orbiting electrons is itself unstable, and the natural charge-equalizing
tendency is for the hexagonal plane to revert to something more compact,
like a sphere. Therefore on occasion, and as several papers are now
suggesting, the lithium-6 nucleus temporarily takes the form of 3 deuterons,
arranged in the X,Y  Z axes where the neutrons of each deuteron are in
contact. This is where Efimov state comes into play.
Now the visual image of greatest impact is to imagine the 3 deuterons
expressing the Efimov Halo Effect, which is state of oscillating balance
and Russian nesting dolls geometry as 

[Vo]:Ego Out post 600- daily info for 27 March 2007

2015-03-27 Thread Peter Gluck
Dear Friends
It is:
http://egooutpeters.blogspot.ro/2015/03/more-lenr-issues-at-march-27-2015.html

Peter
-- 
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com


[Vo]:translation of Parkhomov 3rd

2015-03-27 Thread Bob Higgins
I went into the Powerpoint file and translated the text and figures of
Alexander Parkhomov's latest presentation into English (Thank you Google
Translate).  Here is a link to the translated document.  Please point out
any errors and I will correct them.  I took the liberty of correcting the
numerical mistake at the end.

https://drive.google.com/open?id=0B5Pc25a4cOM2WWVmdHRjVmVHMDAauthuser=0

Bob Higgins


Re: [Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Frank Znidarsic
The spacing of the nucleons is 1.36 fermi meters.  That's twice the radii.  The 
reciprocal of this spacing is the nuclear wave number.
The wave number and the elastic constant give a sonic velocity of 1,094,000 
meters per second in the structure.


Frank Znidarsic



-Original Message-
From: Bob Cook frobertc...@hotmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Fri, Mar 27, 2015 12:27 pm
Subject: Re: [Vo]:A picture is worth a thousand words, or maybe 10k


  
  Jones-- 
  

  
  The Li-6 loves neutrons and will readily change to Li-7, if one is nearby.  
It may be that the Li-6 acts as a catalyst to combine the charge of a proton 
and an electron to form a neutron and He-5, which in turn gives up another 
neutron and gets to He-4. The neutrons can then combine with most anything to 
form an isotope up to Ni-62 with loss of mass along the way.  It will be 
interesting to see what the isotopic analysis of Parkhomov's ash is.  It is 
being evaluated currently.  We may see some Si-28 coming from Al-27 
transmutation via the short-lived Al-28 isotope.   
  

  
  Also, in thinking about the geometrical stability of the Li-7 and the lack of 
the stability of Li-6.  I assume you envision a concentrated point charge 
associated with the protons with respect to the geometry. 
  

  
  I for one do not think there is a segregation of charge within the nucleus, 
but that the charge is spread  throughout the nucleus so as to eliminate 
discontinuities at a 0 distance. Thus, variation in charge density within a 
nucleus is nil. However the charge density shape can be modified by the 
approach of other charges or electric or magnetic fields.  That is what happens 
when Li-6 is hit with a gamma which causes it to breakup or activate to a 
higher energy state--an isomer with an unstable charge density configuration.  
  

  
  Bob 
  

  

  

  

  
   
- Original Message -   
   
   From:Jones Beene   
   
   To:vortex-l@eskimo.com   
   
   Sent: Friday, March 27, 2015 8:07 AM  
   
   Subject: [Vo]:A picture is worth a thousand words, or maybe 10k  
   
   
  
   
The following is overly simplistic, but also surprisingly intuitive for a 
particular hypothesis, so it is worth the effort to try to get down an 
explanation for the Rossi/Parkhomov effect … one containing less than a 
thousand words, by using a few images…
   
Here is an image of the Li-7 nucleus. Keep in mind the single tenet that 
like-charges repel. In a small nucleus, and ignoring QM for a moment in favor 
of macro geometrical restraints this means that nesting of nucleons becomes 
complicated… since in the case of 3 protons, they must be kept apart by 
neutrons.
   
   
http://www.lnhatom.com/Lithium%207.jpg
   
To oversimplify the point which will be made below: the red balls are the 3 
protons, and they do not touch each other because the 4 neutrons form a 
tetrahedron which effectively separates them, and a tetrahedron is an 
especially stable geometry. Therefore, this isotope should be more stable than 
one where like charges have the possibility of fleeting contact. In fact, 
almost 93% of natural lithium is this particular isotope: Li7 despite this 
isotope being a drip line anomaly in itself. 
   
That stable tetrahedral nesting arrangement at the core of Li7 is not the case 
with lithium-6 however; and this nucleus becomes unstable, particularly when 
stressed by incursion of positive charge (such as by the approach of a proton). 
That is because the only stable geometry which we can visualize for Li6 is to 
have a near-planar hexagonal arrangement of alternating neutrons and protons, 
arranged somewhat like a benzene ring, which is not spherical and not stable 
wrt the strong force:
   
   
https://dlnmh9ip6v2uc.cloudfront.net/assets/0/4/e/8/2/519fa09dce395f8b0800.png
   
Therefore, a planar structure like the one above, when it is located inside 
orbiting electrons is itself unstable, and the natural charge-equalizing 
tendency is for the hexagonal plane to revert to something more compact, like a 
sphere. Therefore on occasion, and as several papers are now suggesting, the 
lithium-6 nucleus temporarily takes the form of 3 deuterons, arranged in the 
X,Y  Z axes where the neutrons of each deuteron are in contact. This is where 
Efimov state comes into play.
   
Now the visual image of greatest impact is to imagine the 3 deuterons 
expressing the Efimov “Halo Effect,” which is state of oscillating balance and 
Russian nesting dolls geometry as predicted by Efimov. This state should 
function like a pump, among other possibilities.  But a pump for what?
   
For those who suspect that the Dirac sea, as expressed in Don Hotson’s many 
papers, is accessible as a point source, then one suggestion is that the Li6  
nucleus can act like a pump for “something” which is intrinsic to the Dirac sea…
 and since epos are ruled out by the lack of observed radiation, then that 
something 

Fwd: [Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Frank Znidarsic




 The spacing of the nucleons is 1.36 fermi meters.  That's twice their radii. 
This is a constant as the density of the nucleus is constant.   The reciprocal 
of this spacing is the nuclear wave number. The wave number and the elastic 
constant give a sonic velocity of 1,094,000 meters per second in the structure.


That's my constant and I am sticking to it.  It is also the cold fusion 
velocity.
   
   
   
   
Frank Znidarsic   



-Original Message-
 From: Bob Cook frobertc...@hotmail.com
 To: vortex-l vortex-l@eskimo.com
 Sent: Fri, Mar 27, 2015 12:27 pm
 Subject: Re: [Vo]:A picture is worth a thousand words, or maybe 10k
 
 
  
   
Jones--   
   

   
The Li-6 loves neutrons and will readily change to Li-7, if one is 
nearby.  It may be that the Li-6 acts as a catalyst to combine the charge of a 
proton and an electron to form a neutron and He-5, which in turn gives up 
another neutron and gets to He-4. The neutrons can then combine with most 
anything to form an isotope up to Ni-62 with loss of mass along the way.  It 
will be interesting to see what the isotopic analysis of Parkhomov's ash is.  
It is being evaluated currently.  We may see some Si-28 coming from Al-27 
transmutation via the short-lived Al-28 isotope. 
   

   
Also, in thinking about the geometrical stability of the Li-7 and the 
lack of the stability of Li-6.  I assume you envision a concentrated point 
charge associated with the protons with respect to the geometry.   
   

   
I for one do not think there is a segregation of charge within the 
nucleus, but that the charge is spread  throughout the nucleus so as to 
eliminate discontinuities at a 0 distance. Thus, variation in charge density 
within a nucleus is nil. However the charge density shape can be modified by 
the approach of other charges or electric or magnetic fields.  That is what 
happens when Li-6 is hit with a gamma which causes it to breakup or activate to 
a higher energy state--an isomer with an unstable charge density configuration. 
   
   

   
Bob   
   

   

   

   

   

 - Original Message -

 From: Jones Beene

 To: vortex-l@eskimo.com

 Sent: Friday, March 27, 2015 8:07 AM

 Subject: [Vo]:A picture is worth a thousand words, or maybe 10k

 


The following is overly simplistic, but also 
surprisingly intuitive for a particular hypothesis, so it is 
worth the effort to try to get down an 
explanation for the Rossi/Parkhomov effect … one
 containing less than a thousand words, by  
   using a few images…   

Here is an image of the Li-7 nucleus. Keep in mind the single   
  tenet that like-charges repel. In a small 
nucleus, and ignoring QM for a moment in favor of macro geometrical 
restraints this means that nesting of nucleons  
   becomes complicated… since in the case of
 3 protons, they must be kept 
apart by neutrons.   

   

http://www.lnhatom.com/Lithium%207.jpg  
 

To oversimplify the point which will be made below: 
the red balls are the 3 protons, and they do not touch each other   
  because the 4 neutrons form a tetrahedron which effectively separates 
them, and a tetrahedron is an especially stable 
geometry. Therefore, this isotope   
  should be more stable than one where like charges have
 the possibility of fleeting contact. In fact, almost 93% of natural 
lithium is this particular isotope: Li7 despite this 
isotope being a drip line anomaly in itself.

That stable tetrahedral nesting arrangement 
at the core of Li7 is not the case with lithium-6 however   
 ; and this nucleus becomes unstable, 
particularly when stressed by incursion of positive charge (such as by 
the approach of a proton). That is because the only 
stable geometry which we can visualize for Li6

Re: [Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Bob Cook
A picture is worth a thousand words, or maybe 10kJones--

The Li-6 loves neutrons and will readily change to Li-7, if one is nearby.  It 
may be that the Li-6 acts as a catalyst to combine the charge of a proton and 
an electron to form a neutron and He-5, which in turn gives up another neutron 
and gets to He-4. The neutrons can then combine with most anything to form an 
isotope up to Ni-62 with loss of mass along the way.  It will be interesting to 
see what the isotopic analysis of Parkhomov's ash is.  It is being evaluated 
currently.  We may see some Si-28 coming from Al-27 transmutation via the 
short-lived Al-28 isotope.  

Also, in thinking about the geometrical stability of the Li-7 and the lack of 
the stability of Li-6.  I assume you envision a concentrated point charge 
associated with the protons with respect to the geometry.

I for one do not think there is a segregation of charge within the nucleus, but 
that the charge is spread  throughout the nucleus so as to eliminate 
discontinuities at a 0 distance. Thus, variation in charge density within a 
nucleus is nil. However the charge density shape can be modified by the 
approach of other charges or electric or magnetic fields.  That is what happens 
when Li-6 is hit with a gamma which causes it to breakup or activate to a 
higher energy state--an isomer with an unstable charge density configuration. 

Bob

 


  - Original Message - 
  From: Jones Beene 
  To: vortex-l@eskimo.com 
  Sent: Friday, March 27, 2015 8:07 AM
  Subject: [Vo]:A picture is worth a thousand words, or maybe 10k


  The following is overly simplistic, but also surprisingly intuitive for a 
particular hypothesis, so it is worth the effort to try to get down an 
explanation for the Rossi/Parkhomov effect . one containing less than a 
thousand words, by using a few images.

  Here is an image of the Li-7 nucleus. Keep in mind the single tenet that 
like-charges repel. In a small nucleus, and ignoring QM for a moment in favor 
of macro geometrical restraints this means that nesting of nucleons becomes 
complicated. since in the case of 3 protons, they must be kept apart by 
neutrons.


  http://www.lnhatom.com/Lithium%207.jpg

  To oversimplify the point which will be made below: the red balls are the 3 
protons, and they do not touch each other because the 4 neutrons form a 
tetrahedron which effectively separates them, and a tetrahedron is an 
especially stable geometry. Therefore, this isotope should be more stable than 
one where like charges have the possibility of fleeting contact. In fact, 
almost 93% of natural lithium is this particular isotope: Li7 despite this 
isotope being a drip line anomaly in itself. 

  That stable tetrahedral nesting arrangement at the core of Li7 is not the 
case with lithium-6 however; and this nucleus becomes unstable, particularly 
when stressed by incursion of positive charge (such as by the approach of a 
proton). That is because the only stable geometry which we can visualize for 
Li6 is to have a near-planar hexagonal arrangement of alternating neutrons and 
protons, arranged somewhat like a benzene ring, which is not spherical and not 
stable wrt the strong force:


  
https://dlnmh9ip6v2uc.cloudfront.net/assets/0/4/e/8/2/519fa09dce395f8b0800.png

  Therefore, a planar structure like the one above, when it is located inside 
orbiting electrons is itself unstable, and the natural charge-equalizing 
tendency is for the hexagonal plane to revert to something more compact, like a 
sphere. Therefore on occasion, and as several papers are now suggesting, the 
lithium-6 nucleus temporarily takes the form of 3 deuterons, arranged in the 
X,Y  Z axes where the neutrons of each deuteron are in contact. This is where 
Efimov state comes into play.

  Now the visual image of greatest impact is to imagine the 3 deuterons 
expressing the Efimov Halo Effect, which is state of oscillating balance and 
Russian nesting dolls geometry as predicted by Efimov. This state should 
function like a pump, among other possibilities.  But a pump for what?

  For those who suspect that the Dirac sea, as expressed in Don Hotson's many 
papers, is accessible as a point source, then one suggestion is that the Li6  
nucleus can act like a pump for something which is intrinsic to the Dirac 
sea. and since epos are ruled out by the lack of observed radiation, then that 
something is most likely spin, or a subset like angular momentum, or a 
quantum of spin: a Dirac spinor, or something along those lines. 

  Thus the Li6 nucleus would be the a gateway for spin energy coupling - 
especially at a temperature where the 3-deuteron geometry is favored. This 
temperature seems to be in the range of 1400K in the dogbone.

  This hypothesis suggests that the key to the excess heat in dogbone-type 
devices is lithium-6. The thermal anomaly will be maximized by enrichment in 
the isotope, and should go away with all Li7. 

  Thus, this hypothesis, despite 

Re: [Vo]:translation of Parkhomov 3rd

2015-03-27 Thread Frank Acland
Great work, Bob -- very useful!

On Fri, Mar 27, 2015 at 12:35 PM, Bob Higgins rj.bob.higg...@gmail.com
wrote:

 I went into the Powerpoint file and translated the text and figures of
 Alexander Parkhomov's latest presentation into English (Thank you Google
 Translate).  Here is a link to the translated document.  Please point out
 any errors and I will correct them.  I took the liberty of correcting the
 numerical mistake at the end.

 https://drive.google.com/open?id=0B5Pc25a4cOM2WWVmdHRjVmVHMDAauthuser=0

 Bob Higgins




-- 
Frank Acland
Publisher, E-Cat World http://www.e-catworld.com


[Vo]:ICCF19 abstracts and daily program

2015-03-27 Thread Jed Rothwell
The ICCF19 secretariat sent me this notice.


At the following link is now available the list of the posters and oral
presentations accepted:

http://www.iccf19.com/program_abstract.html

A weekly calendar is available at this link:

http://www.iccf19.com/program_overview.html

A more detailed daily program is available at this webpage:

http://www.iccf19.com/program_detail.html


RE: [Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Jones Beene
Given that the deuteron is a magnetic dipole - a quantum nuclear magnet
which interacts with its own electrons to form a magnon... we have an
interesting situation when 3 deuterons, connected at the focal point as if
one pole, and having an x,y, and z axis... oscillate at elevated
temperatures. Since a single pole is expressed outwardly, this arrangement
looks to all the world to be a tiny monopole, but of course it is not.

Efimov effect in quantum magnets  Nishida, et al. Nature Physics 9,
93-97 (2013)
http://www.nature.com/nphys/journal/v9/n2/abs/nphys2523.html

This paper adds some formality to the above emerging view that a lithium-6
nucleus, when acting like 3 deuterons on a transient basis, is coupling spin
energy from the Dirac sea into the normal spatial dimensions of a simple
reactor.

Quote: Physics is said to be universal when it emerges regardless of the
underlying microscopic details. A prominent example is the Efimov effect,
which predicts the emergence of an infinite tower of three-body bound states
obeying discrete scale invariance when the particles interact resonantly.
Because of its universality and peculiarity, the Efimov effect has been the
subject of extensive research in chemical, atomic, nuclear and particle
physics for decades. Here we employ an anisotropic Heisenberg model to show
that collective excitations in quantum magnets (magnons) also exhibit the
Efimov effect. We locate anisotropy-induced two-magnon resonances, compute
binding energies of three magnons and find that they fit into the universal
scaling law. We propose several approaches to experimentally realize the
Efimov effect in quantum magnets, where the emergent Efimov states of
magnons can be observed with commonly used spectroscopic measurements. Our
study thus opens up new avenues for universal few-body physics in condensed
matter systems.

_
From: Jones Beene 

Bob,

In general - the evidence says that there is an almost complete lack of high
energy radiation, or neutron activation, in the reported experiments even at
the kilowatt thermal level- this means that there are no neutrons, no fusion
and little transmutation (other than incidental). 

If any of these indicia were present, there would be substantial activation:
which would be proof. But there is none of this. It seem prudent to drop the
idea of nuclear fusion until there is minimal evidence that supports it. Now
it is simply a default position.

The path forward in RD is clear to me - construct two cells, one depleted
in Li7 and the other depleted in Li6. If there is no clear advantage to the
Li6, then this  hypothesis fails and another one must be found. Experiment
rules, and experiment says that there is no nuclear fusion.

Unfortunately, ORNL is quoting $35,000 gram for Li6. This is many times
higher - probably 100x higher than last year. It looks like politics has
become involved, and that there could be a high level effort to discourage
the use of Li6. Why?


From: Bob Cook 

Jones--
 
The Li-6 loves neutrons and will readily change to Li-7, if one is nearby.
It may be that the Li-6 acts as a catalyst to combine the charge of a proton
and an electron to form a neutron and He-5, which in turn gives up another
neutron and gets to He-4. The neutrons can then combine with most anything
to form an isotope up to Ni-62 with loss of mass along the way.  It will be
interesting to see what the isotopic analysis of Parkhomov's ash is.  It is
being evaluated currently.  We may see some Si-28 coming from Al-27
transmutation via the short-lived Al-28 isotope.  
 
Also, in thinking about the geometrical stability of the Li-7 and the lack
of the stability of Li-6.  I assume you envision a concentrated point charge
associated with the protons with respect to the geometry.
 
I for one do not think there is a segregation of charge within the nucleus,
but that the charge is spread  throughout the nucleus so as to eliminate
discontinuities at a 0 distance. Thus, variation in charge density within a
nucleus is nil. However the charge density shape can be modified by the
approach of other charges or electric or magnetic fields.  That is what
happens when Li-6 is hit with a gamma which causes it to breakup or activate
to a higher energy state--an isomer with an unstable charge density
configuration. 
 
Bob
 
- Original Message - 
From: Jones Beene mailto:jone...@pacbell.net  
The following is overly simplistic, but also surprisingly intuitive for a
particular hypothesis, so it is worth the effort to try to get down an
explanation for the Rossi/Parkhomov effect ... one containing less than a
thousand words, by using a few images...
Here is an image of the Li-7 nucleus. Keep in mind the single tenet that
like-charges repel. In a small nucleus, and ignoring QM for a moment in
favor of macro geometrical restraints this means that nesting of nucleons
becomes complicated... since in the case of 3 protons, they must 

Re: [Vo]:Re: [Vo]:Efimov - for the third time

2015-03-27 Thread mixent
In reply to  Bob Cook's message of Tue, 24 Mar 2015 07:57:39 -0700:
Hi,

I think the Li6 nucleus is arranged like this:-

2 neutrons paired with opposite spin.
2 protons paired with opposite spin.

1 neutron left over.
1 proton left over.

I think the negative near field of the neutron implies that it has to spin in
the same direction as a proton for the pair to be magnetically attracted (N pole
of one close to S pole of the other), i.e. in the lowest energy state. Hence the
spin of 1 (1/2 + 1/2).

However this also means that the magnetic fields of the proton and the neutron
don't quite neutralize one another, so the nucleus as a whole should have a
small magnetic moment (which it does). That would allow for some magnetic
coupling.


RE: [Vo]:Re: [Vo]:Efimov - for the third timeJones--

The -1/2  Dirac spinor may actually couple with the electronic Li-6 structure, 
which in turn couples to the nucleus via a magnetic quadruple/dipole  or 
electric dipole coupling to allow transfer of spin energy to the nucleus.  The 
fact that the Li-6 is a Bose particle (spin 1) may complicate the coupling or 
make it possible?  The activated Li-6 state probably has a different spin 
number.  I do not know enough about the expected nuclear structure to comment. 
 Maybe Prof. N. Cook's book has something about this issue.  

Also the chart of nuclides that I have has a symbol for the activation cross 
section which I am not sure I understand.  It may indicate the cross section 
for photon activation, which is well known to produce isomeric nuclear states 
in Li-6. This activation must be by electric dipole stimulation or magnetic 
dipole stimulation.  I suspect the latter.  The symbol is described as 
follows: a sigma with a subscript gamma and a with a up-side-down arrow above 
the sigma followed by a cross section and resonant integral

The work by some to consistently stimulate LENR with a laser suggests the same 
thing (activation) may be possible with certain low power resonant photon 
stimulation.  

Bob
  - Original Message - 
  From: Jones Beene 
  To: vortex-l@eskimo.com 
  Sent: Monday, March 23, 2015 3:24 PM
  Subject: RE: [Vo]:Re: [Vo]:Efimov - for the third time


  From: hohlr...@gmail.com 


  Spin cartel?


  I like it!  :-)


  A related subject for those who are invested in Hotson’s famous exposition 
 of the Dirac sea is this: how is the energy which can (theoretically) be 
 pumped from another dimension into 3-space related to the Dirac spinor (or is 
 it identical) ? (this poser assumes that the zero point field is a related 
 subset of Dirac’s sea).

  Wiki sez that the Dirac spinor is a bispinor which describes relativistic 
 spin-½ wave functions, so there does seem to be a potential coupling from the 
 epo to a spin 1 nucleus like lithium-6.
Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html



Re: [Vo]:A picture is worth a thousand words, or maybe 10k

2015-03-27 Thread Bob Cook

Jones--

I agree with your observation that there is not radiation seen and hence 
probably no neutron production, which would lead to activation and decay of 
activated nuclei with their very visible gammas.  My Idea of potential 
activation of Al-27 is not likely.



 I like your idea regarding the implication of the Efimov effect in so far 
as Li-6 is concerned.


Bob
- Original Message - 
From: Jones Beene jone...@pacbell.net

To: vortex-l@eskimo.com
Sent: Friday, March 27, 2015 2:20 PM
Subject: RE: [Vo]:A picture is worth a thousand words, or maybe 10k



Given that the deuteron is a magnetic dipole - a quantum nuclear magnet
which interacts with its own electrons to form a magnon... we have an
interesting situation when 3 deuterons, connected at the focal point as if
one pole, and having an x,y, and z axis... oscillate at elevated
temperatures. Since a single pole is expressed outwardly, this arrangement
looks to all the world to be a tiny monopole, but of course it is not.

Efimov effect in quantum magnets  Nishida, et al. Nature Physics 9,
93-97 (2013)
http://www.nature.com/nphys/journal/v9/n2/abs/nphys2523.html

This paper adds some formality to the above emerging view that a lithium-6
nucleus, when acting like 3 deuterons on a transient basis, is coupling 
spin

energy from the Dirac sea into the normal spatial dimensions of a simple
reactor.

Quote: Physics is said to be universal when it emerges regardless of the
underlying microscopic details. A prominent example is the Efimov effect,
which predicts the emergence of an infinite tower of three-body bound 
states

obeying discrete scale invariance when the particles interact resonantly.
Because of its universality and peculiarity, the Efimov effect has been 
the

subject of extensive research in chemical, atomic, nuclear and particle
physics for decades. Here we employ an anisotropic Heisenberg model to 
show

that collective excitations in quantum magnets (magnons) also exhibit the
Efimov effect. We locate anisotropy-induced two-magnon resonances, compute
binding energies of three magnons and find that they fit into the 
universal

scaling law. We propose several approaches to experimentally realize the
Efimov effect in quantum magnets, where the emergent Efimov states of
magnons can be observed with commonly used spectroscopic measurements. Our
study thus opens up new avenues for universal few-body physics in 
condensed

matter systems.

_
From: Jones Beene

Bob,

In general - the evidence says that there is an almost complete lack of 
high
energy radiation, or neutron activation, in the reported experiments even 
at
the kilowatt thermal level- this means that there are no neutrons, no 
fusion

and little transmutation (other than incidental).

If any of these indicia were present, there would be substantial 
activation:
which would be proof. But there is none of this. It seem prudent to drop 
the
idea of nuclear fusion until there is minimal evidence that supports it. 
Now

it is simply a default position.

The path forward in RD is clear to me - construct two cells, one depleted
in Li7 and the other depleted in Li6. If there is no clear advantage to 
the

Li6, then this  hypothesis fails and another one must be found. Experiment
rules, and experiment says that there is no nuclear fusion.

Unfortunately, ORNL is quoting $35,000 gram for Li6. This is many times
higher - probably 100x higher than last year. It looks like politics has
become involved, and that there could be a high level effort to discourage
the use of Li6. Why?


From: Bob Cook

Jones--

The Li-6 loves neutrons and will readily change to Li-7, if one is nearby.
It may be that the Li-6 acts as a catalyst to combine the charge of a 
proton

and an electron to form a neutron and He-5, which in turn gives up another
neutron and gets to He-4. The neutrons can then combine with most anything
to form an isotope up to Ni-62 with loss of mass along the way.  It will 
be
interesting to see what the isotopic analysis of Parkhomov's ash is.  It 
is

being evaluated currently.  We may see some Si-28 coming from Al-27
transmutation via the short-lived Al-28 isotope.

Also, in thinking about the geometrical stability of the Li-7 and the lack
of the stability of Li-6.  I assume you envision a concentrated point 
charge

associated with the protons with respect to the geometry.

I for one do not think there is a segregation of charge within the 
nucleus,

but that the charge is spread  throughout the nucleus so as to eliminate
discontinuities at a 0 distance. Thus, variation in charge density within 
a

nucleus is nil. However the charge density shape can be modified by the
approach of other charges or electric or magnetic fields.  That is what
happens when Li-6 is hit with a gamma which causes it to breakup or 
activate

to a higher energy state--an isomer with an unstable charge density
configuration.

Bob

- Original Message -