As Dianne mentioned assuming that because there's no wifi you are
running on the emulator is a bit risky. There could be real phones
with no wifi and emulator emulating wifi.
Stick to any of the other methods.
On Nov 4, 6:19 am, Zhihong GUO gzhh...@gmail.com wrote:
It can not work. There is no
Yep, I agree that checking the Wifi service availability is not the
best idea
--
Roman Baumgaertner
Sr. SW Engineer-OSDC
·T· · ·Mobile· stick together
The views, opinions and statements in this email are those of the
author solely in their individual capacity, and do not necessarily
On Nov 3, 2:29 pm, Zhihong GUO gzhh...@gmail.com wrote:
Hi all,
How to know if the application is running on emulator or on a real device? I
want to implement a function to detect wifi connection. If the application
is running on emulator, just skip the wifi detection, while on real device,
if (1.equals(android.os.SystemProperties.get(ro.kernel.qemu))) {
// Run in Emulator
}
On Nov 4, 9:21 am, Emmanuel emmanuel.ast...@gmail.com wrote:
On Nov 3, 2:29 pm, Zhihong GUO gzhh...@gmail.com wrote:
Hi all,
How to know if the application is running on emulator or on a real device?
Furthermore the API call
(WifiManager)mContext.getSystemService(mWifiService);
gives you an exception on the Emulator which is an indication that
Wifi radio is not supported.
--
Roman Baumgaertner
Sr. SW Engineer-OSDC
·T· · ·Mobile· stick together
The views, opinions and statements in this
On Tue, Nov 3, 2009 at 11:10 AM, Roman ( T-Mobile USA)
roman.baumgaert...@t-mobile.com wrote:
Furthermore the API call
(WifiManager)mContext.getSystemService(mWifiService);
gives you an exception on the Emulator which is an indication that
Wifi radio is not supported.
That's only
Hi lianwei,
what's the means of ro.kernel.qemu?
2009/11/4 lianwei lianwei.w...@gmail.com
if (1.equals(android.os.SystemProperties.get(ro.kernel.qemu))) {
// Run in Emulator
}
On Nov 4, 9:21 am, Emmanuel emmanuel.ast...@gmail.com wrote:
On Nov 3, 2:29 pm, Zhihong GUO
It can not work. There is no exception throws and the wifiManager returned
can be used as wifiManager.isEnabled()
2009/11/4 Dianne Hackborn hack...@android.com
On Tue, Nov 3, 2009 at 11:10 AM, Roman ( T-Mobile USA)
roman.baumgaert...@t-mobile.com wrote:
Furthermore the API call
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