On Friday 06 April 2007 17:10, rtwas wrote:
gcc: avr-gcc (GCC) 4.1.1
libc: avr-libc-1.4.4
[...]
/usr/local/atmel/bin/avr-gcc -g -Os -Wall -mcall-prologues
-mmcu=atmega128 -save-temps main.o spim.o spim_tmr0.o diag.o uart.o
cmd.o cmd_spi.o -o avr_sdiag0.obj
It is interesting, what was a reason to declare
default char as signed for AVR port?
Many other GCC ports use unsigned.
I find only one CPU that is suitable for such
choice: PDP-11, where the shortest method to read
memory (mov_byte_from_memory_to_register) expands
a sign bit.
Dmitry.
* larry barello [EMAIL PROTECTED] [07-04-06 09:01]:
Ok, this is the most interesting answer and begs another question: Are you
just saying use either signed or unsigned (I typically use uint8_t except
when the signedness counts) or is char a distinct type that has defined
behavior across
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From:
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org] On Behalf Of Dmitry K.
Sent: Friday, April 06, 2007 1:15 AM
To: avr-gcc-list@nongnu.org
Subject: Re: [avr-gcc-list] dtostrf and the dreaded
relocation truncated to fit: R_AVR_13_PCREL error
On
As larry barello wrote:
Are you just saying use either signed or unsigned (I typically use
uint8_t except when the signedness counts) or is char a distinct
type that has defined behavior across portable systems?
char is always either signed or unsigned, but as a portable
application must not
It is interesting, what was a reason to declare
default char as signed for AVR port?
Right now, there *is* a reason: consistency. We've always had it that
way.
Many other GCC ports use unsigned.
I guess Denis inherited it from the i386 port that also defaults to
signed
On Freitag, 6. April 2007, Lars Noschinski wrote:
* larry barello [EMAIL PROTECTED] [07-04-06 09:01]:
Ok, this is the most interesting answer and begs another question: Are you
just saying use either signed or unsigned (I typically use uint8_t except
when the signedness counts) or is char a
On Freitag, 6. April 2007, Eric Weddington wrote:
I found it in avr.h of the port:
#define DEFAULT_SIGNED_CHAR 1
So this means that the AVR defaults to a signed char. Can we change this to
be unsigned?:
Why?
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As Eric Weddington wrote:
The makefile explicitly compiles with -funsigned-chars
Which just doesn't matter at all.
, yet this
produces a warning.
Sure. It's a deficiency of the old compiler to *not* have produced
that warning.
Note that the issue seems to be when it is a pointer to
a
