why you need to do that? you can use phpmyadmin to restore the sql
file, that's all.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To
Thank you VERY much :)
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
Sorry, I should have been more clear. I wasn't looking for how to do getAge(), but rather the best place to put such a method so that it would be available to views and such.I normally would put these type of methods in the value objects/transfer objects that I use to pass data between the model
$othAuthRestrictions = array(show/8,show/9);
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email
It's a method that's inherent to the model itself, and you don't need
any data outside the model to determine it. But if you're trying to
access it via the view, then you're doing something wrong. What you
should be doing is using the controller to get the value and pass it to
the view.
Hello,
I have 2 models connected with this associations:
Waypoint belongsTo WaypointType
WaypointType hasMany Waypoint
I do this:
$this-set('waypoint_types', $this-WaypointType-findAll());
It gives me all WaypointTypes with _all_ associated Waypoints. But I
want obtain only associated
Hi,
I'd like to be able to unit test my code in it's own test database with
limited test data. No data is supposed to persist between tests so I'd
like to reset the test database to a known state between each test. I
also export my schema as the structure changes between versions. In
order to
use bindModel
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more
some examples can be found at http://cakebaker.wordpress.com/2006/02/22/new-feature-bindmodelunbindmodel/Sam Dps it a great feature, but if you find yourself using it all the time you might want to think about adding conditions to the model files them self and undoing the conditions when you do
Hi all. First off, I am working on an app that has clients; clients
have projects, projects have phases, and phases have pieces. A bland ER
diagram would be:
client --[ 1:N ]-- project
project --[ 1:N ]-- phase
phase --[ 1:N ]-- piece
Obviously, each of the entities on the left side 'have many'
i *think* if you set the id of a MOdel, you can findAll the related Models
$this-Client-id = 3;
$this-Client-Project-findAll();
anyway, if you get the client using read() , find() or findAll() ,
you get an array with all the associated data.
try this in your controller:
$client =
is there a list of reserved words ?
if not , i suggest making one to the 'naming conventions' area in the manual.
going to add it in trac system
spark
On 8/14/06, nate [EMAIL PROTECTED] wrote:
You can't have a model named File. It conflicts with Cake's internally
File class. Bad idea,
i *think* if you set the id of a MOdel, you can findAll the related Models
$this-Client-id = 3;
$this-Client-Project-findAll();
or you could get the record (project/phase/piece) and check that the
id associated matches the current user, eg:
$this-Phase-id = $id;
$data = $this-Phase-read();
Hi Bakers,
Andrew McCafferty wrote:
I've noticed that when I turn on view caching the following string is
appended to the rendered document above the DOCTYPE declaration:
!--cachetime:2310440104--
This seems to cause IE6 to ignore the DOCTYPE and revert back to Quirks
mode.
Is this
Jon Bennett wrote:
i *think* if you set the id of a MOdel, you can findAll the related Models
$this-Client-id = 3;
$this-Client-Project-findAll();
or you could get the record (project/phase/piece) and check that the
id associated matches the current user, eg:
$this-Phase-id = $id;
$this-ScProject-id = 55; //doesnt matter what number i use
$data = $this-ScProject-ScPhase-find();
debug($data);
exit;
that won't work as you're setting the ID of ScProject not ScPhase, you
could do it two ways:
1. Automagically
$this-ScProject-id = 55; //doesnt matter what number i use
Hi, i've been looking through the different resources off the cake
website and around the web over the past week, and i haven't been able
to find an elegant ajax user register. I just have 4 fields: email,
username, password, confirm. Confirm is not in my data model which has
given me some grief.
Hi,
This is my first post here (new in cakephp waters) I hope you won't
mind it being a basic question.
I have a need for the following setup
site.com/team/some_name
I have created a Teams controller and made a view function that handles
data for the team view. The view function takes in
Check out rdBloggery, that has an Ajax login for posting comments:
http://cakeforge.org/projects/rdos/
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to
Try site.com/controller/index/team/some_name
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email
site.com/team/view/some_name
I have tried with the index() function and making it
index($some_name=) but that doesn't help me. I couldn't find anywhere
in the documentation how to do this. Is there a way to do this without
chaning the routes configuration? Any help would be welcome even if
Hi, I'm about to choose a PHP Framework and my options are very limited
due to the environment I'm using, I am on Apache2, PHP5 in CGI mode and
without mod_rewrite access. The admins are not willing to enable it
and I cannot point my root to the webroot directory since the
departmental site I'm
On Aug 15, 2006, at 2:01 PM, Daemon wrote:
Hi, I'm about to choose a PHP Framework and my options are very
limited
due to the environment I'm using, I am on Apache2, PHP5 in CGI mode
and
without mod_rewrite access. The admins are not willing to enable it
and I cannot point my root
Thanks,
So it has to be done with routes.
This is settled once and for all than :)
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To
Using the latest stable build (1.1.7.3363)
Here's what I have:
/app/webroot/ - /www/account/project/
/app/ - /www/account/lib/app_project/
/cake/ - /www/account/lib/cake/
In /www/account/project/index.php I have changed to:
if (!defined('ROOT')) {
define('ROOT',
On Aug 15, 2006, at 2:37 PM, Daemon wrote:Fatal error: main() [function.require]: Failed opening required 'cake/bootstrap.php' (include_path='.:/usr/local/lib/php:/www/account/lib/cake:/www/account/lib/app_project/') in /www/account/project/index.php on line 89 Is the file located at
At the present time, Cake web-based API documentation for classes is
difficult to read, with no separation between classes above and below
the desired one.
Here is a simple solution to that annoying problem, along with a
proposed solution.
In api.css, please add the following lines:
In the prior message, I meant to write, with no visible separation
between methods above and below the desired method.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send
I have hosting at 1and1.com, so i dont have access to modify the
DocumentRoot property.
Is there any way i can get cake to work without having to use urls like
mysite.com/cake/users ?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to
On Aug 15, 2006, at 3:42 PM, [EMAIL PROTECTED] wrote:
I have hosting at 1and1.com, so i dont have access to modify the
DocumentRoot property.
Is there any way i can get cake to work without having to use urls
like
mysite.com/cake/users ?
Check out the settings dealing with mod_rewrite
thanks for using cjs
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
Yes, it is along with:
app_controller.php
app_model.php
basics.php
bootstrap.php
dispatcher.php
and foud directories
Running on:
Apache/2.0.54 (Unix) mod_ssl/2.0.54 OpenSSL/0.9.7a mod_fastcgi/2.4.2
PHP/5.0.5
Thanks!
John David Anderson (_psychic_) wrote:
On Aug 15, 2006, at 2:37 PM, Daemon
Hey folks,
As a note, there are many solutions to a problem, and all of them are
good ones, this is my approach to the problem of not being able to do
something in cake.
After banging my head in trying to get generateList to concatenate two
fields (for the purpose of using the data in a
We don't respond to requests or bugs posted here. You can open a
ticket at https://trac.cakephp.org/
Thanks.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to
Donehttps://trac.cakephp.org/ticket/1321On 8/15/06, nate
[EMAIL PROTECTED] wrote:We don't respond to requests or bugs posted here.You can open a
ticket at https://trac.cakephp.org/Thanks.
--~--~-~--~~~---~--~~
You received this message because you are
I am baking my first Cake app, and I created a controller named
address_controller.php for a table named addresses:
?php
class AddressController extends AppController
{
var $name = 'Address';
//var $scaffold;
}
?
I created a model called address.php:
?php
class Address extends
Your controller needs to be plural.addresses_controller.phpclass AddressesController extends AppController{ var $name = Addresses;}On 8/15/06,
jbernat [EMAIL PROTECTED] wrote:
I am baking my first Cake app, and I created a controller namedaddress_controller.php for a table named
I try to you copy or move_uploaded_file ,but I faill!
How to upload image? Please give me a example,thanks!
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to
hey dood,
a FileHandler component has been written by Chris Partridge (thanks
Chris) that might help you:
http://cakeforge.org/snippet/browse.php?by=langlang=5 (id = 52)
http://cakeforge.org/snippet/detail.php?type=snippetid=52
also, you might want to check out:
Hi all,
If you're in the area, come check me out at BostonPHP:
http://cake.insertdesignhere.com/posts/view/6
I'll be presenting CakePHP along side some other frameworks.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google
other frameworks... there are other frameworks, dang it should of
looked at those... ;)
good luck and knock their socks off
sam d
On 8/15/06, nate [EMAIL PROTECTED] wrote:
Hi all,
If you're in the area, come check me out at BostonPHP:
http://cake.insertdesignhere.com/posts/view/6
I'll
thank you suggest,but not work!
form enctype==multipart/form-data action=/edit/product/edit
method=postinput type=hidden name=data[Product][product_id]
value=3 id=ProductProductId /input type=hidden
name=data[Product][company_id] value=1 id=ProductCompanyId /
...
input type=file
Thank you for entering that ticket, John.
I meant to write that you can see a sample of the improved appearance
at
http://jengels.maxsoft.com/test/
versus the existing page at
http://api.cakephp.org/class_controller.html
(The top of my sample page is not rendered correctly. I didn't bother
Mini,
That's a great suggestion. I'm also using sql views (not to be confused
with Cake views!) to make things easier in my project.
Incidentally, I wonder if the use of Postgres could reduce the number
of steps in that solution by means of triggers. I suspect a calculated
field could be
Gwoo updated the stylesheet already.http://api.cakephp.org/class_controller.htmlRefresh your the page if it doesn't show up.I marked it as trivial because it did not present a security concern or logical error in a code example that could lead to unworkable code (which can be very frustrating
45 matches
Mail list logo
