Query error

2004-07-02 Thread Andy Hammer
I am getting the warning: Found = in conditional, should be == at NM_000367.pl line 32. line 32 contains my sql query: my $sql = qq{ SELECT * FROM fasta WHERE accession LIKE 'NM_000367' } or die Can't prepare SQL statement: ,$ucscHandle-errstr(), \n; The query fuctions fine, but I

Re: Query error

2004-07-02 Thread Hardy Merrill
Andy, *what* is that statement supposed to be doing? Typically you 1. prepare the sql 2. execute the sql This statement: my $sql = qq{ SELECT * FROM fasta WHERE accession LIKE 'NM_000367' } or die Can't prepare SQL statement:

Query error

2004-07-01 Thread Andy Hammer
I am getting the warning: Found = in conditional, should be == at NM_000367.pl line 32. line 32 contains my sql query: my $sql = qq{ SELECT * FROM fasta WHERE accession LIKE 'NM_000367' } or die Can't prepare SQL statement: ,$ucscHandle-errstr(), \n; The query fuctions fine, but I am

Re: Query error

2004-07-01 Thread Jonathan Leffler
Andy Hammer wrote: I am getting the warning: Found = in conditional, should be == at NM_000367.pl line 32. line 32 contains my sql query: my $sql = qq{ SELECT * FROM fasta WHERE accession LIKE 'NM_000367' } or die Can't prepare SQL statement: ,$ucscHandle-errstr(), \n; The query