I think you can do this in two queries and a little perl. For the first two:
select type, count(*) from mytable group by type
That will give you a row for each type with the number in that type. Use perl
to add them up to get the total number. Watch out for rows where type is null.
For
Unless I'm missing something, you cannot do this all with one query. You can
do it with two queries, but I'm not sure that would be any more efficient
than handling each with a separate query. The reason you can't get it all in
one query is that one of these will require a Group by clause, and
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
SELECT COUNT(*) as TOTAL,
(SELECT COUNT(*) FROM Table WHERE status = 'P') as PRESENT,
(SELECT COUNT(*) FROM Table WHERE STATUS IN ('L', 'A',
'O')) AS ABSENT
FROM Table
I don't think sub-selects are suppored in MySQL, unless
