On 2008-08-26 11:50, Ron Johnson wrote:
On 08/25/08 20:34, s. keeling wrote:
Ron Johnson [EMAIL PROTECTED]:
On 08/24/08 11:32, Rick Pasotto wrote:
Why pipe it to bc? Keep it in the shell:
$ echo $[$[$(date -d 20090824 +%s) - $(date -d 20080724 +%s)] / 86400]
396
[snip]
One stylistic
Arithmetic Expansion
Arithmetic expansion allows the evaluation
of an arithmetic expression and the substitution
of the result.
The format for arithmetic expansion is:
$((expression))
The old format $[expression] is deprecated
and will be removed in upcoming versions
On 08/25/08 20:34, s. keeling wrote:
Ron Johnson [EMAIL PROTECTED]:
On 08/24/08 11:32, Rick Pasotto wrote:
Why pipe it to bc? Keep it in the shell:
$ echo $[$[$(date -d 20090824 +%s) - $(date -d 20080724 +%s)] / 86400]
396
[snip]
One stylistic reason for piping to bc is that some people
On Tue, Aug 26, 2008 at 04:50:16AM -0500, Ron Johnson wrote:
On 08/25/08 20:34, s. keeling wrote:
I've been running *nix on my home boxes since '93, and I've never even
seen that syntax. That's a bashism, I hope?
Yes. And a relatively modern one at that. Somewhere in the 3.x series.
I
Ron Johnson [EMAIL PROTECTED]:
On 08/24/08 11:32, Rick Pasotto wrote:
Why pipe it to bc? Keep it in the shell:
$ echo $[$[$(date -d 20090824 +%s) - $(date -d 20080724 +%s)] / 86400]
396
[snip]
One stylistic reason for piping to bc is that some people think that
bash's $[]
Hi all.
Does anyone have any suggestions for a command-line-interface (CLI)
calculator that can work out the difference between 2 (gregorian)
dates (i.e. that is calendar aware). My favourite cli calculator
(bc) doesn't seem to have any knowledge of the gregorian calendar.
Just to make it clear,
On Sunday 24 August 2008 18.07.59 j t wrote:
Hi all.
Does anyone have any suggestions for a command-line-interface (CLI)
calculator that can work out the difference between 2 (gregorian)
dates (i.e. that is calendar aware). My favourite cli calculator
(bc) doesn't seem to have any knowledge
On 08/24/08 10:07, j t wrote:
Hi all.
Does anyone have any suggestions for a command-line-interface (CLI)
calculator that can work out the difference between 2 (gregorian)
dates (i.e. that is calendar aware). My favourite cli calculator
(bc) doesn't seem to have any knowledge of the gregorian
j t wrote:
Hi all.
Does anyone have any suggestions for a command-line-interface (CLI)
calculator that can work out the difference between 2 (gregorian)
dates (i.e. that is calendar aware). My favourite cli calculator
(bc) doesn't seem to have any knowledge of the gregorian calendar.
Just to
On 08/24/08 10:54, Edward J. Shornock wrote:
[snip]
While I'm sure someone else will provide a much better way, I've used
something like
$ echo $(date -d 20080824 +%j) - $(date -d 20080724 +%j) | bc
31
That a good idea. I never knew date(1) could do that. The problem,
though, is that
On Sun, Aug 24, 2008 at 11:25:31AM -0500, Ron Johnson wrote:
On 08/24/08 10:54, Edward J. Shornock wrote:
[snip]
While I'm sure someone else will provide a much better way, I've used
something like
$ echo $(date -d 20080824 +%j) - $(date -d 20080724 +%j) | bc
31
That a good idea. I
On 08/24/08 11:32, Rick Pasotto wrote:
On Sun, Aug 24, 2008 at 11:25:31AM -0500, Ron Johnson wrote:
On 08/24/08 10:54, Edward J. Shornock wrote:
[snip]
While I'm sure someone else will provide a much better way, I've used
something like
$ echo $(date -d 20080824 +%j) - $(date -d 20080724
On Sun, 2008-08-24 at 11:25 -0500, Ron Johnson wrote:
On 08/24/08 10:54, Edward J. Shornock wrote:
[snip]
While I'm sure someone else will provide a much better way, I've used
something like
$ echo $(date -d 20080824 +%j) - $(date -d 20080724 +%j) | bc
31
That a good idea. I
On 24 Ago, 17:10, j t [EMAIL PROTECTED] wrote:
[snip]
(I'm happy to use any date format for input - I've only used ISO8601
as an example)
Maybe something like that:
#!/usr/bin/python
from time import mktime, strptime
from sys import argv
class DummyDate:
def __init__(self, strdate,
On 08/24/08 12:41, Damon L. Chesser wrote:
On Sun, 2008-08-24 at 11:25 -0500, Ron Johnson wrote:
On 08/24/08 10:54, Edward J. Shornock wrote:
[snip]
While I'm sure someone else will provide a much better way, I've used
something like
$ echo $(date -d 20080824 +%j) - $(date -d 20080724 +%j)
On 2008-08-24 11:13:43 -0500, Ron Johnson wrote:
I think I'd write a simple Python/Perl script: convert date1 and date2 to
seconds past epoch, subtract, and divide by 86400.
In Perl, you can also use the Date::Manip module:
4. The amount of time between two dates.
$date1 =
On 2008-08-24 12:25:00 -0500, Ron Johnson wrote:
I was thinking that integer division might result in the occasional
rounding error.
This is the contrary: AFAIK, you really want an integer division.
So, integer arithmetic is OK. But a floating-point division can
be a problem since when the
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